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EEE 498598 Overview of Electrical Engineering

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Conservative field. Gauss's law. Constitutive relation. Lecture 5 ... Applying conservative law to the path, we have. Lecture 5. The boundary condition is ... – PowerPoint PPT presentation

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Title: EEE 498598 Overview of Electrical Engineering


1
EEE 498/598Overview of Electrical Engineering
  • Lecture 5
  • Electrostatics Dielectric Breakdown,
    Electrostatic Boundary Conditions, Electrostatic
    Potential Energy Conduction Current and Ohms Law

2
Lecture 5 Objectives
  • To continue our study of electrostatics with
    dielectric breakdown, electrostatic boundary
    conditions and electrostatic potential energy.
  • To study steady conduction current and Ohms law.

3
Dielectric Breakdown
  • If a dielectric material is placed in a very
    strong electric field, electrons can be torn from
    their corresponding nuclei causing large currents
    to flow and damaging the material. This
    phenomenon is called dielectric breakdown.

4
Dielectric Breakdown (Contd)
  • The value of the electric field at which
    dielectric breakdown occurs is called the
    dielectric strength of the material.
  • The dielectric strength of a material is denoted
    by the symbol EBR.

5
Dielectric Breakdown (Contd)
  • The dielectric strength of a material may vary by
    several orders of magnitude depending on various
    factors including the exact composition of the
    material.
  • Usually dielectric breakdown does not permanently
    damage gaseous or liquid dielectrics, but does
    ruin solid dielectrics.

6
Dielectric Breakdown (Contd)
  • Capacitors typically carry a maximum voltage
    rating. Keeping the terminal voltage below this
    value insures that the field within the capacitor
    never exceeds EBR for the dielectric.
  • Usually a safety factor of 10 or so is used in
    calculating the rating.

7
Fundamental Laws of Electrostatics in Integral
Form
Conservative field
Gausss law
Constitutive relation
8
Fundamental Laws of Electrostatics in
Differential Form
Conservative field
Gausss law
Constitutive relation
9
Fundamental Laws of Electrostatics
  • The integral forms of the fundamental laws are
    more general because they apply over regions of
    space. The differential forms are only valid at
    a point.
  • From the integral forms of the fundamental laws
    both the differential equations governing the
    field within a medium and the boundary conditions
    at the interface between two media can be derived.

10
Boundary Conditions
  • Within a homogeneous medium, there are no abrupt
    changes in E or D. However, at the interface
    between two different media (having two different
    values of e), it is obvious that one or both of
    these must change abruptly.

11
Boundary Conditions (Contd)
  • To derive the boundary conditions on the normal
    and tangential field conditions, we shall apply
    the integral form of the two fundamental laws to
    an infinitesimally small region that lies
    partially in one medium and partially in the
    other.

12
Boundary Conditions (Contd)
  • Consider two semi-infinite media separated by a
    boundary. A surface charge may exist at the
    interface.

13
Boundary Conditions (Contd)
  • Locally, the boundary will look planar

rs
x x x x x x
14
Boundary Condition on Normal Component of D
  • Consider an infinitesimal cylinder (pillbox)
    with
  • cross-sectional area Ds and height Dh lying
    half in
  • medium 1 and half in medium 2

Ds
Dh/2
rs
x x x x x x
Dh/2
15
Boundary Condition on Normal Component of D
(Contd)
  • Applying Gausss law to the pillbox, we have

0
16
Boundary Condition on Normal Component of D
(Contd)
  • The boundary condition is
  • If there is no surface charge

For non-conducting materials, rs 0 unless an
impressed source is present.
17
Boundary Condition on Tangential Component of E
  • Consider an infinitesimal path abcd with width
    Dw
  • and height Dh lying half in medium 1 and half
    in
  • medium 2

Dw
d
a
Dh/2
Dh/2
b
c
18
Boundary Condition on Tangential Component of E
(Contd)
19
Boundary Condition on Tangential Component of E
(Contd)
  • Applying conservative law to the path, we have

20
Boundary Condition on Tangential Component of E
(Contd)
  • The boundary condition is

21
Electrostatic Boundary Conditions - Summary
  • At any point on the boundary,
  • the components of E1 and E2 tangential to the
    boundary are equal
  • the components of D1 and D2 normal to the
    boundary are discontinuous by an amount equal to
    any surface charge existing at that point

22
Electrostatic Boundary Conditions - Special Cases
  • Special Case 1 the interface between two perfect
    (non-conducting) dielectrics
  • Physical principle there can be no free surface
    charge associated with the surface of a perfect
    dielectric.
  • In practice unless an impressed surface charge
    is explicitly stated, assume it is zero.

23
Electrostatic Boundary Conditions - Special Cases
  • Special Case 2 the interface between a conductor
    and a perfect dielectric
  • Physical principle there can be no
    electrostatic field inside of a conductor.
  • In practice a surface charge always exists at
    the boundary.

24
Potential Energy
  • When one lifts a bowling ball and places it on a
    table, the work done is stored in the form of
    potential energy. Allowing the ball to drop back
    to the floor releases that energy.
  • Bringing two charges together from infinite
    separation against their electrostatic repulsion
    also requires work. Electrostatic energy is
    stored in a configuration of charges, and it is
    released when the charges are allowed to recede
    away from each other.

25
Electrostatic Energy in a Discrete Charge
Distribution
  • Consider a point charge Q1 in an otherwise empty
    universe.
  • The system stores no potential energy since no
    work has been done in creating it.

26
Electrostatic Energy in a Discrete Charge
Distribution (Contd)
  • Now bring in from infinity another point charge
    Q2.
  • The energy required to bring Q2 into the system is
  • V12 is the electrostatic potential due to Q1
  • at the location of Q2.

27
Electrostatic Energy in a Discrete Charge
Distribution (Contd)
  • Now bring in from infinity another point charge
    Q3.
  • The energy required to bring Q3 into the system is

28
Electrostatic Energy in a Discrete Charge
Distribution (Contd)
  • The total energy required to assemble the system
    of three charges is

29
Electrostatic Energy in a Discrete Charge
Distribution (Contd)
  • Now bring in from infinity a fourth point charge
    Q4.
  • The energy required to bring Q4 into the system
    is
  • The total energy required to assemble the system
    of four charges is

30
Electrostatic Energy in a Discrete Charge
Distribution (Contd)
  • Bring in from infinity an ith point charge Qi
    into a system of i-1 point charges.
  • The energy required to bring Qi into the system
    is
  • The total energy required to assemble the system
    of N charges is

31
Electrostatic Energy in a Discrete Charge
Distribution (Contd)
  • Note that

? Physically, the above means that the partial
energy associated with two point charges is equal
no matter in what order the charges are assembled.
32
Electrostatic Energy in a Discrete Charge
Distribution (Contd)
33
Electrostatic Energy in a Discrete Charge
Distribution (Contd)
34
Electrostatic Energy in a Discrete Charge
Distribution (Contd)
? Physically, Vi is the potential at the location
of the ith point charge due to the other
(N-1) charges.
35
Electrostatic Energy in a Continuous Charge
Distribution
36
Electrostatic Energy in a Continuous Charge
Distribution (Contd)
37
Electrostatic Energy in a Continuous Charge
Distribution (Contd)
Divergence theorem and
38
Electrostatic Energy in a Continuous Charge
Distribution (Contd)
  • Let the volume V be all of space. Then the
    closed surface S is sphere of radius infinity.
    All sources of finite extent look like point
    charges. Hence,

39
Electrostatic Energy in a Continuous Charge
Distribution (Contd)
Electrostatic energy density in J/m3.
40
Electrostatic Energy in a Continuous Charge
Distribution (Contd)
energy required to set the field up in free space
energy required to polarize the dielectric
41
Electrostatic Energy in a Capacitor
42
Electrostatic Energy in a Capacitor
  • Letting V V12 V2 V1

43
Electrostatic Forces The Principle of Virtual
Work
  • Electrostatic forces acting on bodies can be
    computed using the principle of virtual work.
  • The force on any conductor or dielectric body
    within a system can be obtained by assuming a
    differential displacement of the body and
    computing the resulting change in the
    electrostatic energy of the system.

44
Electrostatic Forces The Principle of Virtual
Work (Contd)
  • The electrostatic force can be evaluated as the
    gradient of the electrostatic energy of the
    system, provided that the energy is expressed in
    terms of the coordinate location of the body
    being displaced.

45
Electrostatic Forces The Principle of Virtual
Work (Contd)
  • When using the principle of virtual work, we can
    assume either that the conductors maintain a
    constant charge or that they maintain a constant
    voltage (i.e, they are connected to a battery).

46
Electrostatic Forces The Principle of Virtual
Work (Contd)
  • For a system of bodies with fixed charges, the
    total electrostatic force acting on the body is
    given by

47
Electrostatic Forces The Principle of Virtual
Work (Contd)
  • For a system of bodies with fixed potentials, the
    total electrostatic force acting on the body is
    given by

48
Force on a Capacitor Plate
  • Compute the force on one plate of a charged
    parallel plate capacitor. Neglect fringing of
    the field.
  • The force on the
  • upper plate can be
  • found assuming a
  • system of fixed
  • charge.

49
Force on a Capacitor Plate (Contd)
  • The capacitance can be written as a function of
    the location of the upper plate
  • The electrostatic energy stored in the capacitor
    may be evaluated as a function of the charge on
    the upper plate and its location

50
Force on a Capacitor Plate (Contd)
  • The force on the upper plate is given by
  • Using Q CV,

51
Force on a Capacitor Plate (Contd)
  • Compute the force on one plate of a charged
    parallel plate capacitor. Neglect fringing of
    the field.
  • The force on the
  • upper plate can be
  • found assuming a
  • system of fixed
  • potential.

52
Force on a Capacitor Plate (Contd)
  • The capacitance can be written as a function of
    the location of the upper plate
  • The electrostatic energy stored in the capacitor
    may be written as a function of the voltage
    across the plates and the location of the upper
    plate

53
Force on a Capacitor Plate (Contd)
  • The force on the upper plate is given by
  • Manipulating, we obtain

54
Steady Electric Current
  • Electrostatics is the study of charges at rest.
  • Now, we shall allow the charges to move, but with
    a constant velocity (no time variation).
  • steady electric current direct current (DC)

55
Conductors and Conductivity
  • A conductor is a material in which electrons are
    free to migrate over macroscopic distances within
    the material.
  • Metals are good conductors because they have many
    free electrons per unit volume.
  • Other materials with a smaller number of free
    electrons per unit volume are also conductors.
  • Conductivity is a measure of the ability of the
    material to conduct electricity.

56
Semiconductor
  • A semiconductor is a material in which electrons
    in the outermost shell are able to migrate over
    macroscopic distances when a modest energy
    barrier is overcome.
  • Semiconductors support the flow of both negative
    charges (electrons) and positive charges (holes).

57
Conduction Current
  • When subjected to a field, an electron in a
    conductor migrates through the material
    constantly colliding with the lattice and losing
    momentum.
  • The net effect is that the electron moves
    (drifts) with an average drift velocity that is
    proportional to the electric field.

electron mobility
58
Conduction Current (Contd)
  • Consider a conducting wire in which charges
    subject to an electric field are moving with
    drift velocity vd.

electron
E
vd
Ds
cross-section
59
Conduction Current (Contd)
  • If there are nc free electrons per cubic meter of
    material, then the charge density within the wire
    is
  • Consider an infinitesimal volume associated with
    Ds

60
Conduction Current (Contd)
  • The total charge contained within Dv is
  • This charge packet moves through the surface Ds
    with speed
  • The amount of time it takes for the charge packet
    to move through Ds is

61
Conduction Current (Contd)
  • Current is the rate at which charges passes
    through a specified surface area (such as the
    cross-section of a wire).
  • The incremental current through Ds is given by

62
Current Density
  • The component of the current density in the
    direction normal to Ds is
  • In general, the current density is given by

63
Current Density (Contd)
  • The constant of proportionality between the
    electric field and the conduction current density
    is called the conductivity of the material
  • Ohms law at a point

64
Current Density (Contd)
  • The conductivity of the medium is the macroscopic
    quantity which allows us to treat conduction
    current without worrying about the microscopic
    behavior of conductors.
  • In semiconductors, we have both holes and
    electrons

hole mobility
hole density
65
Current Density (Contd)
  • The total current flowing through a
    cross-sectional area S may be found as
  • If the current density is uniform throughout the
    cross-section, we have

cross-sectional area
66
Current Flow
  • Consider a wire of non-uniform cross-section

67
Current Flow (Contd)
  • To maintain a constant electric field and a
    steady current flow, both E and J must be
    parallel to the conductor boundaries.
  • The total current passing through the
    cross-section A1 must be the same as through the
    cross-section A2. So the current density must be
    greater in A2.

68
Ohms Law and Resistors
  • Consider a conductor of uniform cross-section
  • Let the wires and the two
  • exposed faces of the
  • resistor be perfect
  • conductor.
  • In a perfect conductor
  • J is finite
  • s is infinite
  • E must be zero.

69
Ohms Law and Resistors (Contd)
  • To derive Ohms law for resistors from Ohms law
    at a point, we need to relate the circuit
    quantities (V and I) to the field quantities (E
    and J)
  • The electric field within the material is given
    by
  • The current density in the wire is

70
Ohms Law and Resistors (Contd)
  • Plugging into J sE, we have
  • Define the resistance of the device as
  • Thus,

Ohms law for resistors
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