Chapter 35 - PowerPoint PPT Presentation

About This Presentation
Title:

Chapter 35

Description:

Huygens' principle: All points on a wavefront serve as point sources of spherical secondary wavelets. ... After a time t, the new position of the wavefront will ... – PowerPoint PPT presentation

Number of Views:58
Avg rating:3.0/5.0
Slides: 14
Provided by: ITSD
Learn more at: http://people.uncw.edu
Category:
Tags: chapter | huygens

less

Transcript and Presenter's Notes

Title: Chapter 35


1
Chapter 3536 Interference and the Wave Nature of
Light
  • Light as a Wave
  • THE PRINCIPLE OF LINEAR SUPERPOSITION
  • Young's Double-Slit Experiment
  • Diffraction

2
What is physics?
3
Light as a Wave
  • Huygens' principle
  • All points on a wavefront serve as point
    sources of spherical secondary wavelets. After a
    time t, the new position of the wavefront will be
    that of a surface tangent to these secondary
    wavelets.

4
Constructive Interference
  • Condition , m0, 1, 2, 3, .

5
Destructive Interference
  • Condition , m0, 1, 2, 3,
    .

6
Young's Double-Slit Experiment
7
Bright fringes
Dark fringes
Where m1, 2, 3,
8
Example 1  Youngs Double-Slit Experiment
  • Red light (?664 nm in vacuum) is used in
    Youngs experiment with the slits separated by a
    distance d1.20104 m. The screen in Figure is
    located at a distance of L2.75 m from the slits.
    Find the distance y on the screen between the
    central bright fringe and the third-order bright
    fringe.

9
Interference from Thin Films
Condition for destructive interference is
10
Diffraction
The diffraction is the bending of waves around
obstacles or the edges of an opening
11
Diffraction determined by the ratio ?/W
Smaller ? /W, less diffraction
Larger ? /W, more diffraction
12
Conditions for dark fringes
  • Conditions for dark fringes in single-slit
    diffraction

13
Example   Single-Slit Diffraction
  • Light passes through a slit and shines on a
    flat screen that is located L0.40 m away (see
    Figure). The width of the slit is W4.0106 m.
    The distance between the middle of the central
    bright fringe and the first dark fringe is y.
    Determine the width 2y of the central bright
    fringe when the wavelength of the light in a
    vacuum is (a) ?690 nm (red) and (b) ?410 nm
    (violet).
Write a Comment
User Comments (0)
About PowerShow.com