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Title: Biomedical Instrumentation II


1
Biomedical Instrumentation II
  • Dr. Hugh Blanton
  • ENTC 4370

2
More ULTRASONOGRAPHY
3
CHARACTERISTICS OF SOUND
4
Propagation of Sound
  • Sound is mechanical energy that propagates
    through a continuous, elastic medium by the
    compression and rarefaction of particles that
    compose it.

5
Propagation of Sound
  • Compression is caused by a mechanical deformation
    induced by an external force, with a resultant
    increase in the pressure of the medium.
  • Rarefaction occurs following the compression
    event.
  • The compressed particles transfer their energy to
    adjacent particles, with a subsequent reduction
    in the local pressure amplitude.
  • While the medium itself is necessary for
    mechanical energy transfer (i.e., sound
    propagation), the constituent particles of the
    medium act only to transfer mechanical energy
    these particles experience only very small
    back-and-forth displacements.
  • Energy propagation occurs as a wave front in the
    direction of energy travel, known as a
    Iongitudinal wave.

6
Wavelength, Frequency, and Speed
  • The wavelength (l) of the ultrasound is the
    distance (usually expressed in millimeters or
    micrometers) between compressions or
    rarefactions, or between any two points that
    repeat on the sinusoidal wave of pressure
    amplitude.
  • The frequency (f) is the number of times the wave
    oscillates through a cycle each second (sec).

7
  • Sound waves with frequencies less than 15
    cycles/sec (Hz) are called infrasound, and the
    range between 15 Hz and 20 kHz comprises the
    audible acoustic spectrum.
  • Ultrasound represents the frequency range above
    20 kHz.
  • Medical ultrasound uses frequencies in the range
    of 2 MHz to 10 MHz, with specialized ultrasound
    applications up to 50 MHz.

8
  • The period is the time duration of one wave
    cycle, and is equal to 1/f where f is expressed
    in cycles/sec.
  • The speed of sound is the distance traveled by
    the wave per unit time and is equal to the
    wavelength divided by the period.

9
  • Since period and frequency are inversely related,
    the relationship between speed, wavelength, and
    frequency for sound waves is
  • where c (m/sec) is the speed of sound of
    ultrasound in the medium,
  • l (m) is the wavelength, and
  • f (cycleslsec) is the frequency.
  • The speed of sound is dependent on the
    propagation medium and varies widely in different
    materials.

10
  • The wave speed is determined by
  • the ratio of the bulk modulus (b)
  • a measure of the stiffness of a medium and its
    resistance to being compressed, and
  • the density (r) of the medium
  • SI units are
  • kg/(m-sec2) for b,
  • kg/m3 for r, and
  • m/sec for c.

11
  • A highly compressible medium, such as air, has a
    low speed of sound, while a less compressible
    medium, such as bone, has a higher speed of
    sound.
  • A less dense medium has a higher speed of sound
    than a denser medium (e.g.. dry air vs. humid
    air).

12
  • The speeds of sound in materials encountered in
    medical ultrasound are listed below.

13
  • Of major importance are
  • the speed of sound in air (330 m/sec),
  • the average speed for soft tissue (1,540 m/sec),
    and
  • fatty tissue (1,450 m/sec).

14
  • The difference in the speed of sound at tissue
    boundaries is a fundamental cause of contrast in
    an ultrasound image.

15
  • Medical ultrasound machines assume a speed of
    sound of 1,540 in/sec.
  • The speed of sound in soft tissue can be
    expressed in other units such as 154,000 cm/sec
    and 1.54 mm/msec.

16
  • The ultrasound frequency is unaffected by changes
    in sound speed as the acoustic beam propagates
    through various media.
  • Thus, the ultrasound wavelength is dependent on
    the medium.

17
Example
  • A 2-MHz beam has a wavelength in soft tissue of
  • A 10-MHz ultrasound beam has a corresponding
    wavelength in soft tissue of
  • So, higher frequency sound has shorter
    wavelength.

18
Example
  • A 5-MHz beam travels from soft tissue into fat.
    Calculate the wavelength in each medium, and
    determine the percent wavelength change.
  • In soft tissue,
  • In fat,
  • A decrease in wavelength of 5.8 occurs in going
    from soft tissue into fat, due to the differences
    in the speed of sound.

19
  • The wavelength in mm in soft tissue can be
    calculated from the frequency specified in MHz
    using the approximate speed of sound in soft
    tissue (c 1540 m/sec 1.54 mm/msec)
  • A change in speed at an interface between two
    media causes a change in waveIength.

20
  • The resolution of the ultrasound image and the
    attenuation of the ultrasound beam energy depend
    on the wavelength and frequency.
  • Ultrasound wavelength determines the spatial
    resolution achievable along the direction of the
    beam.
  • A high-frequency ultrasound beam (small
    wavelength) provides superior resolution and
    image detail than a low-frequency beam.
  • However, the depth of beam penetration is reduced
    at higher frequency.
  • Lower frequency ultrasound has longer wavelength
    and less resolution, but a greater penetration
    depth.

21
  • Ultrasound frequencies selected for imaging are
    determined by the imaging application.
  • For thick body parts (e.g., abdominal imaging), a
    lower frequency ultrasound wave is used (3.5 to 5
    MHz) to image structures at significant depths,
    whereas
  • For small body parts or organs close to the skin
    surface (e.g., thyroid, breast), a higher
    frequency is employed (7.5 to 10 MHz).
  • Most medical imaging applications use frequencies
    in the range of 2 to 10 MHz.

22
  • Modern ultrasound equipment consists of multiple
    sound transmitters that create sound beams
    independent of each other.
  • Interaction of two or more separate ultrasound
    beams in a medium results in constructive and/or
    destructive wave interference.
  • Constructive wave interference results in an
    increase in the amplitude of the beam, while
    destructive wave interference results in a loss
    of amplitude.

23
  • The amount of constructive or destructive
    interference depends on several factors, but the
    most important are the phase (position of the
    periodic wave with respect to a reference point)
    and amplitude of the interacting beams.
  • When the beams are exactly in phase and at the
    same frequency, the result is the constructive
    addition of the amplitudes.
  • For equal frequency and a 180-degree phase
    difference, the result will be the destructive
    subtraction of the resultant beam amplitude.
  • With phase and frequency differences, the results
    of the beam interaction can generate a complex
    interference pattern.
  • The constructive and destructive interference
    phenomena are very important in shaping and
    steering the ultrasound beam.

24
  • When the beams are exactly in phase and at the
    same frequency, the result is the constructive
    addition of the amplitudes.

25
  • For equal frequency and a 180-degree phase
    difference, the result will be the destructive
    subtraction of the resultant beam amplitude.

26
  • With phase and frequency differences, the results
    of the beam interaction can generate a complex
    interference pattern.
  • The constructive and destructive interference
    phenomena are very important in shaping and
    steering the ultrasound beam.

27
Pressure, Intensity, and the dB Scale
28
  • Sound energy causes particle displacements and
    variations in local pressure in the propagation
    medium.
  • The pressure variations are most often described
    as pressure amplitude (P).
  • Pressure amplitude is defined as the peak maximum
    or peak minimum value from the average pressure
    on the medium in the absence of a sound wave.

29
  • In the case of a symmetrical waveform, the
    positive and negative pressure amplitudes are
    equal however, in most diagnostic ultrasound
    applications, the compressional amplitude
    significantly exceeds the rarefactional
    amplitude.

30
  • The SI unit of pressure is the pascal (Pa),
    defined as one newton per square meter (N/m2).
  • The average atmospheric pressure on earth at sea
    level of 14.7 pounds per square inch is
    approximately equal to 100,000 Pa.
  • Diagnostic ultrasound beams typically deliver
    peak pressure levels that exceed ten times the
    earths atmospheric pressure, or about 1 MPa
    (megapascal).

31
  • Intensity, I, is the amount of power (energy per
    unit time) per unit area and is proportional to
    the square of the pressure amplitude
  • A doubling of the pressure amplitude quadruples
    the intensity.

32
  • Medical diagnostic ultrasound intensity levels
    are described in units of milliwatts/cm2the
    amount of energy per unit time per unit area.
  • The absolute intensity level depends on the
    method of ultrasound production.
  • Relative intensity and pressure levels are
    described with a unit termed the decibel (dB).
  • or

33
  • In diagnostic ultrasound, the ratio of the
    intensity of the incident pulse to thar of the
    returning echo can span a range of 1 million
    times or more!
  • The logarithm function compresses the large and
    expands the small values into a more manageable
    number range.

34
  • An intensity ratio of 106 (e.g., an incident
    intensity 1 million times greater than the
    returning echo intensity) is equal to 60 dB,
    whereas an intensity ratio of 102 is equal to 20
    dB.
  • A change of 10 in the dB scale corresponds to an
    order of magnitude (ten times) change in
    intensity
  • A change of 20 corresponds to two orders of
    magnitude (100 times) change, and so forth.

35
  • When the intensity ratio is greater than 1 (e.g.,
    the incident ultrasound intensity to the detected
    echo intensity), the dB values are positive when
    less than 1, the dB values are negative.
  • A loss of 3 dB (-3 dB) represents a 50 loss of
    signal intensity.
  • The tissue thickness that reduces the ultrasound
    intensity by 3 dB is considered the half-value
    thickness.

36
  • The table lists a comparison of the dB scale and
    the corresponding intensity or pressure amplitude
    ratios.

37
Example
  • Calculate the remaining intensity of a 100-mW
    ultrasound pulse that loses 30 dB while traveling
    through tissue.

38
INTERACTIONS OF ULTRASOUND WITH MATTER
39
  • Ultrasound interactions are determined by the
    acoustic properties of matter.
  • As ultrasound energy propagates through a medium,
    interactions that occur include
  • reflection,
  • refraction,
  • scattering, and
  • absorption.

40
  • Reflection occurs at tissue boundaries where
    there is a difference in the acoustic impedance
    of adjacent materials.
  • When the incident beam is perpendicular to the
    boundary, a portion of the beam (an echo) returns
    directly back to the source, and the transmitted
    portion of the beam continues in the initial
    direction.

41
  • Refraction describes the change in direction of
    the transmitted ultrasound energy with
    non-perpendicular incidence.

42
  • Scattering occurs by reflection or refraction,
    usually by small particles within the tissue
    medium, causes the beam to diffuse in many
    directions, and gives rise to the characteristic
    texture and gray scale in the acoustic image.

43
  • Absorption is the process whereby acoustic energy
    is converted to heat energy.
  • In this situation, sound energy is lost and
    cannot be recovered.

44
  • Attenuation refers to the loss of intensity of
    the ultrasound beam from absorption and
    scattering in the medium.

45
Acoustic impedance
  • The acoustic impedance (Z) of a material is
    defined as
  • where r is the density in kg/m3 and c is the
    speed of sound in m/sec.
  • The SI units for acoustic impedance are
    kg/(m2-sec) and are often expressed in rayls,
    where 1 rayl is equal to 1kg/(m2-sec).

46
Acoustic impedance
  • The table lists the acoustic impedances of
    materials and tissues commonly encountered in
    medical ultrasonography.

47
Acoustic impedance
  • In a simplistic way, the acoustic impedance can
    be likened to the stiffness and flexibility of a
    compressible medium such as a spring.
  • When springs with different compressibility are
    connected together, the energy transfer from one
    spring to another depends mostly on stiffness.
  • A large difference in the stiffness results in a
    large reflection of energy, an extreme example of
    which is a spring attached to a wall.
  • Minor differences in stiffness or compressibility
    allow the continued propagation of energy, with
    little reflection at the interface.

48
Acoustic impedance
  • Sound propagating through a patient behaves
    similarly.
  • Soft tissue adjacent to air-filled lungs
    represents a large difference in acoustic
    impedance thus, ultrasonic energy incident on
    the lungs from soft tissue is almost entirely
    reflected.
  • When adjacent tissues have similar acoustic
    impedances, only minor reflections of the
    incident energy occur.
  • Acoustic impedance gives rise to differences in
    transmission and reflection of ultrasound energy,
    which is the basis for pulse echo imaging.

49
Reflection
  • The reflection of ultrasound energy at a boundary
    between two tissues occurs because of the
    differences in the acoustic impedances of the two
    tissues.
  • The reflection coefficient describes the fraction
    of sound intensity incident on an interface that
    is reflected.

50
Reflection
  • For perpendicular incidence, the reflection
    pressure amplitude coefficient, RP, is defined as
    the ratio of reflected pressure, Pr, and incident
    pressure, Pi, as

51
  • The intensity reflection coefficient, RI, is
    expressed as the ratio of reflected intensity,
    Ir, and the incident intensity, Ii, as
  • The subscripts 1 and 2 represent tissues proximal
    and distal to the boundary.

52
  • The intensity transmission coefficient, T1, is
    defined as the fraction of the incident intensity
    that is transmitted across an interface.
  • With conservation of energy, the intensity
    transmission coefficient is T1 1 - RI.

53
  • For a fatmuscle interface, the pressure
    amplitude reflection coefficient and the
    intensity reflection and transmission
    coefficients are calculated as

54
  • The actual intensity reflected at a boundary is
    the product of the incident intensity and the
    reflection coefficient.
  • For example, an intensity of 40 mW/cm2 incident
    on a boundary with RI 0.015 reflects 40 x 0.015
    0.6 mW/cm2.

55
  • The intensity reflection coefficient at a tissue
    interface is readily calculated from the acoustic
    impedance of each tissue.
  • Examples of tissue interfaces and respective
    reflection coefficients are listed below.

56
  • For a typical musclefat interface, approximately
    1 of the ultrasound intensity is reflected, and
    thus almost 99 of the intensity is transmitted
    to greater depths in the tissues.
  • At a muscleair interface, nearly 100 of
    incident intensity is reflected, making anatomy
    unobservable beyond an air-filled cavity.
  • This is why acoustic coupling gel must be used
    between the face of the transducer and the skin
    to eliminate air pockets.
  • A conduit of tissue that allows ultrasound
    transmission through structures such as the lung
    is known as an acoustic window.

57
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58
  • When the beam is perpendicular to the tissue
    boundary, the sound is returned back to the
    transducer as an echo.
  • As sound travels from a medium of lower acoustic
    impedance into a medium of higher acoustic
    impedance, the reflected wave experiences a
    180-degree phase shift in pressure amplitude
    (note the negative sign on some of the pressure
    amplitude values in the previous table).
  • The above discussion assumes a smooth boundary
    between tissues, where the wavelength of the
    ultrasound beam is much greater than the
    structural variations of the boundary.

59
  • With higher frequency ultrasound beams, the
    wavelength becomes smaller, and the boundary no
    longer appears smooth relative to the wavelength.
  • In this case, returning echoes are diffusely
    scattered throughout the medium, and only a small
    fraction of the incident intensity returns to the
    source (the ultrasound transducer, as described
    below).
  • For nonperpendicular incidence at an angle qi ,
    the ultrasound energy as reflected at an angle qr
    equal to the incident angle, qi qr.
  • Echoes are directed away from the source of
    ultrasound, causing loss of the returning signal
    from the boundary.

60
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61
Refraction
  • Refraction describes the change in direction of
    the transmitted ultrasound energy at a tissue
    boundary when the beam is not perpendicular to
    the boundary.
  • Ultrasound frequency does not change when
    propagating into the next tissue, but a change in
    the speed of sound may occur.

62
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63
  • Angles of incidence, reflection, and transmission
    are measured relative to the normal incidence on
    the boundary.
  • The angle of refraction qt is determined by the
    change in the speed of sound that occurs at the
    boundary and is related to the angle of incidence
    (qi) by Snells law
  • where qi, and qt, are the incident and
    transmitted angles, c1 and c2 are the speeds of
    sound in medium 1 and 2.

64
  • For small angles of incidence and transmission,
    Snells law can be approximated as

65
  • When c2 gt c1, the angle of transmission is
    greater than the angle of incidence, and the
    opposite with c2 lt c1.

66
  • No refraction occurs when the speed of sound is
    the same in the two media, or with perpendicular
    incidence, and thus a straight-line trajectory
    occurs.
  • This straight-line propagation is assumed in
    ultrasound machines, and when refraction occurs,
    it can cause artifacts in the image.

67
  • A situation called total reflection occurs when
    c2 gt c1 and the angle of incidence of the sound
    beam with a boundary between two media exceeds an
    angle called the critical angle.
  • In his case, the refracted portion of the beam
    does not penetrate the second medium at all, but
    travels along the boundary.
  • The critical angle (qc) is calculated by setting
    (qt) 90 degrees in Snells law where sin (90?)
    1, producing the equation

68
Scattering
  • A specular reflector is a smooth boundary between
    two media, where the dimensions of the boundary
    are much larger than the wavelength of the
    incident ultrasound energy.
  • Acoustic scattering arises from objects within a
    tissue that are about the size of the wavelength
    or smaller, and represent a rough or nonspecular
    reflector surface.

69
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70
  • Most organs have a characteristic structure that
    gives rise to a defined scatter signature and
    provides much of the diagnostic information
    contained in the ultrasound image.
  • Because nonspecular reflectors reflect sound in
    all directions, the amplitudes of the returning
    echoes are significantlv weaker than echoes from
    tissue boundaries.
  • Fortunately, the dynamic range of the ultrasound
    receiver is sufficient to detect echo information
    over a wide range of amplitudes.
  • In addition, the intensities of returning echoes
    from nonspecular reflectors in the tissue
    parenchyma are not greatly affected by beam
    direction, unlike the strong directional
    dependence of specular reflectors.

71
  • Thus, parenchyma-generated echoes typically have
    similar echo strengths and gray-scale levels in
    the image.
  • Differences in scatter amplitude that occur from
    one region to another cause corresponding
    brightness changes on the ultrasound display.

72
  • In general, the echo signal amplitude from the
    insonated tissues depends on
  • the number of scatterers per unit volume,
  • the acoustic impedance differences at the
    scatterer interfaces,
  • the sizes of the scatterers, and
  • the ultrasonic frequency.

73
  • The terms hyperechoic (higher scatter amplitude)
    and hypoechoic (lower scarier amplitude) describe
    the scatter characteristics relative to the
    average background signal.

74
  • Hyperechoic areas usually have
  • greater numbers of scatterers,
  • larger acoustic impedance differences, and
  • larger scatterers.

75
  • Acoustic scattering from nonspecular reflectors
    increases with frequency. while specular
    reflection is relatively independent of
    frequency thus, it is often possible to enhance
    the scattered echo signals over the specular echo
    signals by using higher ultrasound frequencies.

76
Attenuation
  • Ultrasound attenuation, the loss of acoustic
    energy with distance traveled, is caused chiefly
    by scattering and tissue absorption of the
    incident beam.

77
Attenuation
  • Absorbed acoustic energy is converted to heat in
    the tissue.
  • The attenuation coefficient, m, expressed in
    units of dB/cm, is the relative intensity loss
    per centimeter of travel for a given medium.

78
Attenuation
  • Tissues and fluids have widely varying
    attenuation coefficients, as listed in the table.

79
Attenuation
  • Ultrasound attenuation expressed in dB is
    approximately proportional to frequency.
  • An approximate rule of thumb for soft tissue is
    0.5 dB per cm per MHz, or 0.5 (dB/cm)/MHz.

80
Attenuation
  • The product of the ultrasound frequency (in MHz)
    with 0.5 (dB/cm)/MHz gives the approximate
    attenuation coefficient in dB/cm.
  • Thus, a 2-MHz ultrasound beam will have
    approximately twice the attenuation of a 1-MHz
    beam
  • a 10-MHz beam will suffer ten times the
    attenuation per unit distance.
  • Since the dB scale progresses logarithmically,
    the beam intensity is exponentially attenuated
    with distance

81
  • The ultrasound half value thickness (HVT) is the
    thickness of tissue necessary no attenuate the
    incident intensity by 50, which is equal to a
    3-dB reduction in intensity (6 dB drop in
    pressure amplitude).
  • As the frequency increases, the HVT decreases, as
    demonstrated by the examples below.

82
Example
  • Calculate the approximate intensity HVT in soft
    tissue for ultrasound beams of 2 MHz and 10 MHz.
    Determine the number of HVTs the incident beam
    and the echo travel at a 6-cm depth.
  • Answer. Information needed is (a) the attenuation
    coefficient approximation 0.5 (dB/cm)/MHz, and
    (b) one HVT produces a 3-dB loss. Given this
    information, the HVT in soft tissue for a/MHz
    beam is

83
  • Number of HVTs
  • A 6-cm depth requires a travel distance of 12 cm
    (round trip).
  • For a 2-MHz beam, this is 12 cm/(3 cm /HVT2MHz)
    4 HVT2MHz.
  • For a 10-MHz beam this is 12 cm/(0.6 cm
    /HVT10MHz) 20 HVT10MHz.

84
  • EXAMPLE

85
  • The echo intensity is one hundredth of the
    incident intensity in this example (20 dB).
  • If the boundary reflected just 1 of the incident
    intensity (a typical value), the returning echo
    intensity would be or 10,000 times less than the
    incident intensity (40 dB).
  • Considering the depth and travel distance of the
    ultrasound energy, the detector system must have
    a dynamic range of 120 to 140 dB in pressure
    amplitude variations (up to a 10,000,000 times
    range) to be sensitive to acoustic signals
    generated in rhe medium.

86
  • When penetration to deeper structures is
    important, lower frequency ultrasound transducers
    must be used, because of the strong dependence of
    attenuation with frequency.
  • Another consequence of frequency-dependent
    attenuation is the preferential removal of the
    highest frequency components in a broadband
    ultrasound pulse and a shift to lower frequencies.
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