Title: TMHsiung2007 142
1Chapter 07 Let the Titrations Begin
2Contents in Chapter07
- Overview of Titrimetry
- Grades of Chemicals
- Titration Calculations
- Precipitation Titrations
- 1) Titration curve
- 2) Argentometric titration
- Establish Precipitation Titration Curves with a
Spreadsheet
3- Overview of Titrimetry
- Define Titration
- Titrations (or titrimetric method) are based on
measuring the amount of a reagent of known
concentration that reacts with the unknown. - A general equation can be expressed
- aA tT ? products
- A analyte
- T titrant
4- Revisiting Keywords of Titration
- Equivalence point The point (e.g., volume of
titrant) in a titration where (theoretically)
stoichiometrically equivalent amounts of analyte
and titrant react. - Indicator A colored compound whose change in
color signals the (experimental) end point of a
titration. - End point The point (e.g., volume of titrant) in
a (experimental) titration where we stop adding
titrant in an experiment. - Titration error The determinate error in a
titration due to the difference between the end
point and the equivalence point.
5- Type of Titrations based on Chemical Reactions
- Acid-Base Titrations, example
- H OH ? H2O K 1/Kw
- Precipitation Titrations, example
- Ag(aq) Cl(aq) ? AgCl(s) K1/Ksp
- Redox Titrations
- 5 H2O2 2 MnO4 H ? 5 O2 2 Mn2 8H2O
- Complexometric Titrations, example
- EDTA Ca2 ? (CaEDTA)2
6- Type of Titrations based on Measuring Techniques
- Volumetric titrimetry Measuring the volume of a
solution of a known concentration (e.g., mol/L)
that is needed to react completely with the
analyte. - Gravimetric (weight) titrimetry Measuring the
mass of a solution of a known concentration
(e.g., mol/kg) that is needed to react completely
with the analyte. - Coulometric titrimetry Measuring total charge
(current x time) to complete the redox reaction,
then estimating analyte concentration by the
moles of electron transferred.
75) Type of Titration Curves
8- 2. Grades of Chemicals
- Terms and Definitions
- Reagent Grade The reagents which meets or
surpasses the latest American Chemical Society
specifications. - Primary standard The reagent which is ready to
be weighted and used prepare a solution with
known concentration (standard). - Requirements of primary reagent are
- - Known stoichiometric composition
- - High purity
- - Nonhygroscopic
- - Chemically stable both in solid and solution
- - High MW or FW
9- Secondary standard A standard which is
standardized against a primary standard. - Certified reference materials (CRM) A reference
material, accompanied by a certificate, which has
been analysed by different laboratories to
determine consensus levels of the analyte
concentration. - NIST Standard Reference Material (SRM) A CRM
issued by NIST that also meets additional
NIST-specific certification criteria and is
issued with a certificate. - Standardization The process by which the
concentration of a reagent is determined by
reaction with a known quantity of a second
reagent
10- Titration Calculations
- Terms and Definitions
- Blank Titration Titration procedure is carried
out without analyte (e.g., a distilled water
sample). It is used to correct titration error. - Back titration A titration in which a (known)
excess reagent is added to a solution to react
with the analyte. The excess reagent remaining
after its reaction with the analyte, is
determined by a titration.
112) Standardization
Example To standardizing a KMnO4 stock solution,
the primary standard of 9.1129 g Na2C2O4 is
dissolved in 250.0 mL volumetric flask. 10.00 mL
of the Na2C2O4 solution require 48.36 mL of KMnO4
to reach the titration end point. What is the
molarity (M) of MnO4 stock solution? (FW Na2C2O4
134.0)
Solution
5C2O42(aq) 2MnO4(aq) 16H(aq) ? 10CO2(g)
Mn2(aq) 8H2O(l)
Ans
123) Unknown Analysis with a Blank Correction
Example A 0.2865 g sample of an iron ore is
dissolved in acid, and the iron is converted
entirely to Fe2. To titrate the resulting
solution, 0.02653 L of 0.02250 M KMnO4 is
required. Also a blank titration require 0.00008
L of KMnO4 solution. What is the Fe (w/w) in
the ore? (AW Fe 55.847)
Solution MnO4(aq) 5Fe2 8H(aq) ? Mn2(aq)
5Fe3 4H2O(l)
Ans
134) Back Titration
Solution mL x M mmol Total mmol Ag added
(mmol Ag consumed by SCN) (mmol Ag consumed
by H3AsO4)
14Ans
15- Kjeldahl Analysis for Total Nitrogen (TN)
- i) KD description
16Example A typical meat protein contains 16.2
(w/w) nitrogen. A 0.500 mL aliquot of protein
solution was digested, and the liberated NH3 was
distilled into 10.00 mL of 0.02140 M HCl. The
unreacted HCl required 3.26 mL of 0.0198 M NaOH
for complete titration. Find the concentration of
protein (mg protein/mL) in the original
sample. Solution
17Ans
186) Titration of a Mixture
19Ans
Ans
20- Precipitation Titrations
- A titration in which the reaction between the
analyte and titrant involves a precipitation. - 1) Titration curve
- i) Guidance in precipitation titration
calculation - Find Ve (volume of titrant at equivalence point)
- Find y-axis values
- - At beginning
- - Before Ve
- - At Ve
- - After Ve
21- Example For the titration of 50.0 mL of 0.0500 M
Cl with 0.100 M Ag. The reaction is - Ag(aq) Cl(aq) ? AgCl(s) K 1/Ksp
1/(1.81010) 5.6 x 109 - Find pAg and pCl of Ag solution added
- 0 mL (b) 10.0 mL (c) 25.0 mL (d) 35.0 mL
- Solution
22(a) 0 mL Ag added (At beginning) Ag 0, pAg
can not be calculated. Cl 0.0500, pCl 1.30
(b) 10 mL Ag added (Before Ve)
23(c) 25 mL Ag added (At Ve) AgCl(s) ? Ag(aq)
Cl(aq) Ksp 1.81010 s
AgCl Ksp 1.81010 s2 AgCl1.3
5x105 pAg 4.89 pCl 4.89
24(d) 35 mL Ag added (After Ve)
25ii) Construct a titration curve Example
Titration of 50.0 mL of 0.0500 M Cl with 0.100 M
Ag
26iii) End point determination
27iv) Diluting effect of the titration curves
25.00 mL 0.1000 M I titrated with 0.05000 M Ag
25.00 mL 0.01000 M I titrated with 0.005000 M
Ag
25.00 mL 0.001000 M I titrated with 0.0005000 M
Ag
28v) Ksp effect of the titration curves
25.00 mL 0.1000 M halide (X) titrated with
0.05000 M Ag
29vi) Titration of a mixture (uncertainty
concerned)
- 40.00 mL of 0.0502 M KI 0.0500 M KCl, titrated
with 0.0845 M Ag - 20.00 mL of 0.1004 M KI titrated with 0.0845 M
Ag
30Example A 25.00 mL solution containing Br and
Cl was titrated with 0.03333 M AgNO3.
Ksp(AgBr)5x1013, Ksp(AgCl)1.8x1010.
- Which analyte is precipitated first?
- The first end point was observed at 15.55 mL.
Find the concentration of the first that
precipitated (Br or Cl?). - The second end point was observed at 42.23 mL.
Find the concentration of the second that
precipitated (Br or Cl?).
Solution
(a) Ag(aq) Br(aq) ? AgBr(s) K 1/Ksp(AgBr)
2x1012 Ag(aq) Cl(aq) ? AgCl(s) K
1/Ksp(AgCl) 5.6x109 Ans AgBr precipitated first
31(b)
Ans
(c)
Ans
32- Argentometric Titration
- General information
- Define Argentometric Titration A precipitation
titration in which Ag is the titrant. - Argentometric Titration classified by types of
End-point detection - Volhard method A colored complex (back
titration) - Fajans method An adsorbed/colored indicator
- Mohr method A colored precipitate
332) Volhard method A colored complex (back
titration). Analysing Cl for example
Step 1 Adding excess Ag into sample Ag Cl
? AgCl(s) left Ag Step 2 Removing AgCl(s) by
filtration/washing Step 3 Adding Fe3 into
filtrate (i.e., the left Ag) Step 4 Titrating
the left Ag by SCN Ag SCN ?
AgSCN(s) Step 5 End point determination by red
colored Fe(SCN)2 complex. (when all Ag has been
consumed, SCN reacts with Fe3) SCN Fe3 ?
Fe(SCN)2(aq)
Total mol Ag (mol Ag consumed by Cl)
(mol Ag consumed by SCN)
34- Fajans Method An adsorbed/colored indicator.
Titrating Cl and adding - dichlorofluoroscein for example
Cl
Before Ve (Cl excess) Greenish yellow solution
AgCl(s)
1st layer
Ag
In pink
AgCl(s)
After Ve (Ag excess)
1st layer
354) Mohr Method A colored precipitate formed by
Ag with anion, other than analyte, once the Ve
reached. Analysing Cl and adding CrO42 for
example
Precipitating Cl Ag Cl ? AgCl(s) Ksp 1.8
x 1010 End point determination by red colored
precipitate, Ag2CrO4(s) 2Ag CrO42 ?
Ag2CrO4(s) Ksp 1.2 x 1012
365) Applications of argentometric titrations
37- Establish Precipitation Titration Curves with a
Spreadsheet - Example
- M(aq) X(aq) ? MX(s) K 1/Ksp
Titrant
Analyte
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381) Derive the equation
moles of M in precipitate
moles of X in precipitate
Mass balance The moles of an element in all
species in a mixture equal to the total moles of
that element delivered to the solution.
392) Apply the equation
40- Example Construct a titration curve for the
titration of 50.0 mL of 0.0500 M Cl with 0.100 M
Ag. (Ksp of AgCl 1.81010)
41EXCEL 961_Ch07_Titration_X_with_Ag
42Homework Problem 7-30/p.139, Due
2007/11/7 ?????????? Examples All Exercise A-E
, G Problems 1-7, 11-14, 31, 36
End of Chapter07