Outline - PowerPoint PPT Presentation

1 / 81
About This Presentation
Title:

Outline

Description:

The location and identity of some amino acid in these fragments can be ... You should not lend credence to 'one scan wonders.' 37 / 81 ... – PowerPoint PPT presentation

Number of Views:56
Avg rating:3.0/5.0
Slides: 82
Provided by: Fuji238
Category:
Tags: credence | outline

less

Transcript and Presenter's Notes

Title: Outline


1
Outline
  • Introduction
  • What's it all about
  • Course Mechanics
  • From Genomics to Proteomics
  • Protein Separation
  • Protein Identification
  • Mass Spectrometry
  • Fundamentals
  • Protein Chemistry
  • Ionization Techniques
  • Fragmentation techniques
  • Mass Analyzers
  • CID MS/MS Interpretation
  • Peptide Fragmentation Chemistry
  • Interpretation of Spectra

2
Analyzing Spectra
3
Identifying Proteins with MS
  • There are three main approaches for identifying
    proteins.
  • Peptide sequence tag
  • Database search
  • Using de novo algorithm to build peptide sequence.

4
Identifying Proteins with MSUsing Peptide
Sequence Tags
  • In tandem mass spectrometry, peptides are
    fragmented.
  • The location and identity of some amino acid in
    these fragments can be determined by the spacing
    of these fragments of the mass of that amino
    acid.
  • Since there are 20 kinds of amino acids
  • Some combinations of amino acids are sufficient
    to identify protein in database
  • Or at least help greatly to reduce the number of
    matched peptide sequence
  • Called peptide sequence tags
  • Mann and Wilm used a combination of a partial de
    novo algorithm and a database search to implement
    this method
  • The limitation of this method is that if the
    peptide sequence tag is not suitably selected
  • It will produce both false positives
  • And false negatives.

5
Identifying Proteins with MSUsing Database
Search
  • During the process of mass spectrometry, the
    related mass spectra represent the experimental
    spectrum.
  • For all sequences in a protein database or
    genomic database
  • We construct a theoretical mass spectrum.
  • An exhaustive search is then used to compare
    experimental spectrum and all these theoretical
    ones.
  • This method has following limitations
  • Post-translational modifications will reduce the
    accuracy of identification
  • With accumulation of protein sequences, this
    method can be slow.
  • This method will not find new proteins that are
    not in the database.

6
Identifying Proteins with MSBy de novo Sequencing
  • First generate a spectrum graph.
  • Then attempt to find what is called a feasible
    path through this graph.
  • The feasible path corresponds to a valid peptide
    sequence.

7
De novo Peptide Sequencing
Sequence
8
Generating a Theoretical Spectrum for a Database
Search
9
Generating a Theoretical Spectrum for a Database
Search
10
Generating a Theoretical Spectrum for a Database
Search
11
Building a Spectrum Graph for de novo Sequencing
  • How to calculate masses of b and y ions
  • How to create vertices (from masses)
  • How to create edges (from mass differences)
  • How to score paths
  • How to find best path

12
(No Transcript)
13
Protein Backbone Plus Water at Termini
H...-HN-CH-CO-NH-CH-CO-NH-CH-CO-OH
Ri-1
Ri
Ri1
C-terminus
N-terminus
AA residuei-1
AA residuei1
AA residuei
14
y Ion Mass
  • C terminal peptide has an extra OH
  • N terminal peptide has an extra H
  • Must add
  • 18 Da. for the H20
  • 1 Da. for the proton
  • So, add the residue masses and add 19
  • Assuming singly charged

15
b Ion Mass
  • b ion is different
  • C terminal peptide forms cyclic structure (see
    next slide)
  • Thus, has no extra OH
  • In fact, the N on the final residue (on the C
    terminal end) has an extra covalent bond with the
    backbone Carbons
  • Thus, it doesnt have an H
  • Thus, the residue is 1 Da less
  • (see next slide again)
  • N terminal peptide has an extra Hydrogen
  • Must add
  • 1 Da. for the N terminal H
  • 1 Da. for the proton
  • -1 Da for the loss of the H on the final residue
  • So, add the residue masses and add 1
  • Assuming singly charged

16
b and y Ion Chemistry
17
S E Q U E N C E
b
Mass/Charge (M/Z)
18

a
S E Q U E N C E
Mass/Charge (M/Z)
19
a is an ion type shift in b
S E Q U E N C E
Mass/Charge (M/Z)
20

y
E C N E U Q E S
Mass/Charge (M/Z)
21
y with corresponding intensities
E C N E U Q E S
Intensity
Mass/Charge (M/Z)
22

Intensity
Mass/Charge (M/Z)
23
Intensity
Mass/Charge (M/Z)
24

noise
Mass/Charge (M/Z)
25
MS/MS Spectrum
Intensity
Mass/Charge (M/z)
26
Mass Differences Correspond to Amino Acids
u
q
e
e
q
s
u
e
n
n
c
e
e
e
q
c
s
n
e
s
u
e
c
e
27
de novo Sequencing from the C terminus (1/4)
  • To begin sequencing a tryptic peptide, Assume
    that the C-terminus of the peptide is either
    lysine or arginine.
  • This assumption is usually true except for
  • Tryptic peptides derived from non-tryptic
    cleavage
  • Due to contaminating chymotryptic activity
  • Or tryptic peptides encompassing the C-terminus
    of the original protein
  • Where the C-terminal residue of the protein is
    not lysine or arginine.
  • The y1 ion is calculated by adding 19.018 Da t o
    the residue masses of lysine and arginine
  • Three hydrogens and one oxygen
  • H20 plus proton
  • Lysine
  • 128.095 19.018 147.113 Da
  • Arginine
  • 156.1011 19.018 175.119 Da
  • If either mass is present, make a note.

28
de novo Sequencing from the C terminus (2/4)
  • On ion traps, the y1 ions will be below the mass
    cutoff
  • The corresponding high m/z b-type ion is often
    found, though
  • This b ion contains all of the residues except
    the arginine or lysine at the C-terminus.
  • These b ions are calculated by
  • Subtract 17.002 Da from the precursor mass
  • 17.002 Da One oxygen and one hydrogen
    Water loss plus proton gain
  • Subtract the residue mass of arginine or lysine.
  • If this b ion is found, make a note of it.

29
de novo Sequencing from the C terminus (3/4)
  • If a y1 ion for lysine or arginine is found
  • Get peak corresponding to higher product ion
    masses
  • Subtract the y1 mass
  • Check in the residue mass table to see if any
    mass differences correspond to an amino acid.
  • If any differences equate to an amino acid
    residue mass
  • Make a note of what each putative y2 ion might be
  • Also subtract each possible residue mass from the
    high mass b ions
  • Recall these correspond to loss of arginine or
    lysine from precusor
  • high m/z b ions rarely seen for ion traps or
    QTOFs
  • Proceed to the y3 ion and higher
  • For each, check to see if the corresponding high
    m/z b-type ion is present.
  • Eventually as amino acid residue masses are added
    to the y ion series, it passes the b ion series.

30
de novo Sequencing from the C terminus (4/4)
  • Favored partial sequence appear to have both
  • High m/z b ions
  • Corresponding y ions.
  • Eventually, you might get a complete sequence for
    the peptide
  • Hypothesized sequence should have a calculated
    mass that equals the observed precursor mass
  • Within the error tolerance of the peptide mass
    measurement
  • Often you cannot get a complete sequence all the
    way to the N-terminus
  • It is common for a CID spectrum to lack
    fragmentations between the first and second amino
    acids at the N-terminus.
  • Therefore, no b1 ion observed
  • The N-terminus of this proposed has the combined
    residue mass of the first two amino acids.
  • Make sure that this unsequenced mass at the
    N-terminus corresponds to the sum of two amino
    acid residue masses.
  • For example, an unsequenced N-terminal mass of
    150 Da is not possible in the absence of the
    additional mass of a post-translational
    modification.

31
de novo Sequencing from the Middle (1/4)
  • Procedure
  • Get some partial sequence from the middle of the
    peptide
  • Try to connect this partial sequence to the
    peptide N-terminus.
  • Proceed to C terminus.
  • For Qtof or Triple Quads there is a short stretch
    of fairly intense ions at a m/z greater than the
    precursor m/z
  • The mass differences between these ions in the
    series correspond to amino acid residue masses
  • These are the so-called sequence tags introduced
    by Matthias Mann
  • In principal, one does not know if these are
    b-type or y-type ions
  • And hence, whether the partial sequence goes
    forward or backwards
  • For Qtof and triple quad tryptic peptides it is
    usually safe to guess that this is a partial y
    ion series.
  • The precursor must be doubly or triply charged

32
de novo Sequencing from the Middle (2/4)
  • Take the peptide mass 2.016 Da, and subtract the
    highest mass ion in this series
  • This is the mass of two protons
  • The peptide mass has no ions, but the b and y
    ions each have one.
  • This mass difference would correspond to a
    hypothetical lower mass b ion.
  • (Precursor Mass 2) - (y ion with proton) (b
    ion with proton)
  • Often times a y ion series will encompass all but
    the two N-terminal amino acids
  • Then the mass difference between that y ion and
    the precursor mass 2 corresponds to a b2 ion.
  • If that b2 ion is present, check to see if there
    is another ion 27.995 Da lower
  • Which would possibly be the matching a2 ion.

33
de novo Sequencing from the Middle (3/4)
  • If all of these ions are found
  • The putative high m/z y ion
  • Plus the alleged low m/z b
  • Plus the a ion
  • Then its most likely a real peptide ion.
  • If you are lucky, the high m/z y-type ion series
    extends all the way to the N-terminus
  • In which case this mass difference corresponds to
    b1 ion
  • An amino acid residue mass plus a hydrogen
  • Don't bother looking for a b1 ion they don't
    exist.
  • If a partial y ion series is found, then try to
    identify the low mass b ion series that
    corresponds to the high m/z y ion series.

34
de novo Sequencing from the Middle (4/4)
  • For Qtof and triple quad tryptic peptides, the b
    ions usually decrease in intensity to negligible
    values at the high end
  • At the same time the corresponding y ions are
    going into the low m/z end of the spectrum, where
    its harder to see.
  • This portion of the spectrum usually contains
    many more fragment ions of different type
  • Immonium ions
  • b ions
  • a ions
  • y ions
  • Other charged fragments
  • Keep trying to connect the high m/z y-type ion
    series until you reach a y1 ion for the
    C-terminal lysine or arginine
  • 147.113 Da or 175.119 Da, respectively

35
Peak Tips What to Look for in a Spectrum
  • Look for the tallest peak in the spectrum above
    200 mass units.
  • The low end of a spectrum can often be confounded
    with solvent noise.
  • Then look for peaks that are roughly double or
    half the mass.
  • This may tell you whether there are multiply
    charged species present which can help with mass
    determination.   
  • Counts. 
  • Resist interpreting meager spectra.
  • If you know that on a particular day that 1.0106
    is a respectable, reliable signal then you will
    know that a spectrum that tops out at 1.0104
    counts (or at background) may not be a reliable
    spectrum to interpret.    

36
Peak Tips What to Look for in a Spectrum
  • The quality of the spectrum is important.
  • You will waste valuable time interpreting a low
    quality spectrum. 
  • If you are not happy with the quality of the
    spectrum try averaging several or many low level
    spectra to obtain a better quality "averaged mass
    spectrum." 
  • Compare this to a background spectrum to see if
    the peaks really stand out.  
  • Reproducibility is important. 
  • The peak must be consistent to be considered a
    relevant peak.
  • You should not lend credence to "one scan
    wonders."  

37
Peak Tips What to Look for in a Spectrum
  • Determining the charge state of a peak when only
    one peak is obvious
  • A molecule will often have adduct ions associated
    with it other than hydrogen . 
  • Look for sodium or ammonium adducts. 
  • These adducts can often give you a hint as to the
    charge state of a peak. 
  • For example if there is only one major species in
    a spectrum, look for the sodium adduct following
    that peak. 
  • If it is a singly charged species the sodium
    adduct will be found at 22 mass units higher
    than the MH peak. 
  • If the peak is doubly charged the adduct will
    appear at 11 mass units.

38
Isotopes
  • If the mass spectrometer you are working with has
    sufficient resolution, look at the isotopes
  • A singly charged ion will show isotopic peaks
    that differ by 1 mass unit
  • A doubly charged ion will show peaks that differ
    by 0.5 mass units and so on.
  • This is another way to deduce the charge state of
    a peak and thus the mas. 

39
Frequently Asked Questions
  • Q How can I tell if a peak is real?
  • A Wow, this is some question. 
  • All peaks are real. 
  • In an LC/MS run, we look for peaks that reoccur
    in multiple adjacent scans (spectra) but not in
    every scan. 
  • If the peak occurs in every scan it may be a
    background peak.
  • It is possible to get system noise or spikes that
    only occur in one scan or sporadically these are
    most likely electronic or some other form of
    system noise. 

40
Frequently Asked Questions
  • Q How can I be sure of the identity of a peak.
  • A Well, a mass is just a mass and many compounds
    have isobaric mass so you can't be sure from just
    a mass. 
  • In the old days we would
  • Perform an enzymatic digest on a protein
  • Run an LC/MS peptide map and
  • Match up the mass with the theoretical fragments.
  • Today the bar is rightly higher and we go one
    step further in the identification
  • We take the peak through a fragmentation
  • And match up the fragment masses with the
    theoretical CID fragment masses for that peptide.
  • This gives us a positive ID.
  • Another overlooked component in LC/MS
  • The correlation of mass and LC retention time. 
  • This is part of what makes LC/MS so powerful
  • If the retention time of a molecule has been
    previously characterized this information can be
    linked with the mass information for a positive
    ID.
  • If you are characterizing a new molecule
  • Try modifying the molecule to see if you can
    modify the mass. 
  • Try an enzyme digest if the unknown is a protein

41
Frequently Asked Questions
  • Q How can I differentiate a compound at one mass
    from another at twice the mass? 
  • For example a compound with mass 1000 will
    display peaks at m/z 1001 and 501,
  • (1000 1) / 1
  • (1000 2) / 2
  • A compound with mass 2000 may display peaks at
    m/z 2001, 1001, 667.7 and 501. 
  • (2000 1) / 1
  • (2000 2) / 2
  • (2000 3) / 3
  • (2000 4) / 4
  • The mass determination can further be confounded
    if the peptide at 1000 forms dimers during the
    electrospray process.

42
Frequently Asked Questions
  • A
  • The peak envelope does not skip peaks
  • For example the 2000 mass even if it does not
    have an obvious peak at 2001 it should have the
    667.7 peak between the 1001 and 501 peaks.
  • Also try to determine the charge state of the
    ions from the adducts or from the isotopes. 
  • This will tell you what the mass of the compound
    is.
  • Dimer formation can be a major problem in some
    analyses.
  • Try to reduce the concentration of the analyte.
  • Often if the concentration is too high dimers
    will be observed in the spectrum. 
  • Also dimers can be reduced by changing some of
    the setting on the mass spectrometer.

43
Frequently Asked Questions
  • With the peak envelope of larger molecules
    (10kDa) look for smooth peak distributions. 
  • The peak distribution should have a smooth bell
    shaped curve appearance, sometimes trailing off
    to the right.
  • The peak to peak relationship should be
    predictable
  • If one observes an alternating pattern of peak
    intensities this may be a clue to a co-eluting
    dimer. 

44
Example
45
(No Transcript)
46
(No Transcript)
47
(No Transcript)
48
(No Transcript)
49
(No Transcript)
50
(No Transcript)
51
(No Transcript)
52
(No Transcript)
53
(No Transcript)
54
Example
55
Example
389.9 (2/2) 2 779.8 - 2 777.8
(777.8 2) - 518.3 261.5 261.2
27.995 233.2
56
(No Transcript)
57
(No Transcript)
58
(No Transcript)
59
Example
60
Example
389.9 (2/2) 2 779.8 - 2 777.8
(777.8 2) 431.2 348.6
61
Example
348.0 - 27.995 320.0
62
(No Transcript)
63
(No Transcript)
64
(No Transcript)
65
(No Transcript)
66
Example
67
Example
389.9 (2/2) 2 779.8 - 2 777.8
(777.8 2) 303.1 476.7
68
(No Transcript)
69
(No Transcript)
70
(No Transcript)
71
Example
72
Example
389.9 (2/2) 2 779.8 - 2 777.8
(777.8 2) 204.1 575.7
73
(No Transcript)
74
(No Transcript)
75
(No Transcript)
76
Example
77
Example
389.9 (2/2) 2 779.8 - 2 777.8
(777.8 2) 147.1 632.7
78
(No Transcript)
79
(No Transcript)
80
  • Kinter Sherman pg. 93

81
(No Transcript)
Write a Comment
User Comments (0)
About PowerShow.com