Title: Cellular Manufacturing Systems - ADDVALUE - Nilesh Arora
1Cellular Manufacturing
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2ORIGINS
- FLANDERS PRODUCT ORIENTED DEPARTMENTS FOR
STANDARIZED PRODUCTS WITH MINIMAL TRANSPORTATION
(1925) - SOKOLOVSKI/MITROFANOV PARTS WITH SIMILAR
FEATURES MANUFACTURED TOGETHER
3BASIC PRINCIPLE
- SIMILAR THINGS SHOULD BE DONE SIMILARLY
- THINGS
- PRODUCT DESIGN
- PROCESS PLANNING
- FABRICATION ASSEMBLY
- PRODUCTION CONTROL
- ADMINISTRATIVE FUNCTIONS
4TENETS OF GROUP TECHNOLOGY
- DIVIDE THE MANUFACTURING FACILITY INTO SMALL
GROUPS OR CELLS OF MACHINES (1-5) - THIS IS CALLED CELLULAR MANUFACTURING
5SYMPTOMS FOR RE-LAYOUT
- Symptoms that allow us to detect the need for a
re-layout - Congestion and bad utilization of space.
- Excessive stock in process at the facility.
- Long distances in the work flow process.
- Simultaneous bottle necks and workstations with
idle time. - Qualified workers carrying out too many simple
operations. - Labor anxiety and discomfort. Accidents at the
facility. - Difficulty in controlling operations and
personnel.
6What is Group Technology (GT)?
- GT is a theory of management based on the
principle that similar things should be done
similarly - GT is the realization that many problems are
similar, and that by grouping similar problems, a
single solution can be found to a set of problems
thus saving time and effort - GT is a manufacturing philosophy in which similar
parts are identified and grouped together to take
advantage of their similarities in design and
production
7Implementing GT
- Where to implement GT?
- ?Plants using traditional batch production and
?process type layout - ? If the parts can be grouped into part families
- ?How to implement GT?
- ?Identify part families
- ?Rearrange production machines into machine cells
8Types of Layout
- In most of todays factories it is possible to
divide all the made components into families and
all the machines into groups, in such a way that
all the parts in each family can be completely
processed in one group only. - The three main types of layout are
- Line (product) Layout
- Functional Layout
- Group Layout
9Line (product) Layout
- It involves the arrangements of machines in one
line, depending on the sequence of operations. In
product layout, if there is a more than one line
of production, there are as many lines of
machines. - Line Layout is used at present in simple process
industries, in continuous assembly, and for mass
production of components required in very large
quantities.
10Functional Layout
- In Functional Layout, all machines of the same
type are laid out together in the same section
under the same foreman. Each foreman and his team
of workers specialize in one process and work
independently. This type of layout is based on
process specialization.
11Group Layout
- In Group Layout, each foreman and his team
specialize in the production of one list of parts
and co-operate in the completion of common task.
This type of layouts based on component
specialization.
12The Difference between group and functional
layout
13Evaluations of cell system design are incomplete
unless they relate to the Cell Design.
Evaluation criteria of Cell Design
- A few typical performance variables related to
system operation are - Equipment utilization (high)
- Work-in-process inventory (low)
- Queue lengths at each workstation (short)
- Job throughput time (short)
- Job lateness (low)
14Cell Formation Approach
- Machine - Component Group Analysis
- Machine - Component Group Analysis is based on
production flow analysis
15Machine - Component Group Analysis
- Production flow analysis involves four stages
- Stage 1 Machine classification.
- Machines are classified on the basis of
operations that can be performed on them. A
machine type number is assigned to machines
capable of performing similar operations.
16Production flow analysis involves four stages
Machine - Component Group Analysis
- Stage 2 Checking parts list and production
route information. -
- For each part, information on the operations to
be undertaken and the machines required to
perform each of these operations is checked
thoroughly.
17Production flow analysis involves four stages
Machine - Component Group Analysis
- Stage 3 Factory flow analysis.
-
- This involves a micro-level examination of flow
of components through machines. This, in turn,
allows the problem to be decomposed into a number
of machine-component groups.
18Production flow analysis involves four stages
Machine - Component Group Analysis
- Stage 4 Machine-component group analysis.
- An intuitive manual method is suggested to
manipulate the matrix to form cells. However, as
the problem size becomes large, the manual
approach does not work. Therefore, there is a
need to develop analytical approaches to handle
large problems systematically.
19Machine - Component Group Analysis
Example Consider a problem of 4 machines and 6
parts. Try to group them.
Components
Machines 1 2 3 4 5 6
M1 1 1 1
M2 1 1 1
M3 1 1 1
M4 1 1 1
20Machine - Component Group Analysis
Solution
Components
Machines 2 4 6 1 3 5
M1 1 1 1
M2 1 1 1
M3 1 1 1
M4 1 1 1
21Cellular Layout
Process (Functional) Layout
Group (Cellular) Layout
A cluster or cell
Similar resources placed together
Resources to produce similar products placed
together
22Group Technology (CELL) Layouts
- One of the most popular hybrid layouts uses Group
Technology (GT) and a cellular layout - GT has the advantage of bringing the efficiencies
of a product layout to a process layout
environment
23Process Flows before the Use of GT Cells
24Process Flows after the Use of GT Cells
25Designing Product Layouts
- Designing product layouts requires consideration
of - Sequence of tasks to be performed by each
workstation - Logical order
- Speed considerations line balancing
26Designing Product Layouts cont
- Step 1 Identify tasks immediate predecessors
- Step 2 Determine TAKT TIME
- Step 3 Determine cycle time
- Step 4 Compute the Theoretical Minimum number of
Stations - Step 5 Assign tasks to workstations (balance the
- line)
- Step 6 Compute efficiency, idle time balance
delay
27Step 1 Identify Tasks Immediate Predecessors
28Layout Calculations
- Step 2 Determine TAKT TIME
- Vicki needs to produce 60 pizzas per hour
- TAKT TIME 60 sec/unit
- Step 3 Determine cycle time
- The amount of time each workstation is allowed to
complete its tasks - Limited by the bottleneck task (the longest task
in a process)
29Layout Calculations
- Step 4 Compute the theoretical minimum number of
stations - TM number of stations needed to achieve 100
efficiency (every second is used) - Always round up (no partial workstations)
- Serves as a lower bound for our analysis
30Layout Calculations
- Step 5 Assign tasks to workstations
- Start at the first station choose the longest
eligible task following precedence relationships - Continue adding the longest eligible task that
fits without going over the desired cycle time - When no additional tasks can be added within the
desired cycle time, begin assigning tasks to the
next workstation until finished
31Last Layout Calculation
- Step 6 Compute efficiency and balance delay
- Efficiency () is the ratio of total productive
time divided by total time - Balance delay () is the amount by which the line
falls short of 100
32Other Product Layout Considerations
- Shape of the line (S, U, O, L)
- Share resources, enhance communication
visibility, impact location of loading
unloading - Paced versus Un-paced lines
- Paced lines use an automatically enforced cycle
time - Number of Product Models produced
- Single
- Mixed-model lines
33LINE BALANCING
34The Line Balancing Problem
- The problem is to arrange the individual
processing and assembly tasks at the workstations
so that the total time required at each
workstation is approximately the same. - Nearly impossible to reach perfect balance
35Things to consider
- Sequence of tasks is restricted, there is a
required order - Called precedence constraints
- There is a production rate needed, i.e. how many
products needed per time period - Design the line to meet demand and within
constraints
36Terminology and Definitions
- Minimum Work Element
- Total Work Content
- Workstation Process time
- Cycle Time
- Precedence Constraints
- Balance Delay
37Minimum Work Element
- Dividing the job into tasks of a rational and
smallest size - Example Drill a hole, cant be divided
- Symbol Time for element j
- is a constant
38Total Work Content
- Aggregate of work elements
39Workstation Process time
- The amount of time for an individual workstation,
after individual tasks have been combined into
stations - Sum of task times sum of workstation times
40Cycle time
- Time between parts coming off the line
- Ideally, the production rate, but may need to be
adjusted for efficiency and down time - Established by the bottleneck station, that is
station with largest time
41Precedence Constraints
- Generally given, determined by the required order
of operations - Draw in a network style for understanding
- Cannot violate these, an element must be complete
before the next one is started
42Balance Delay
- Measure of line inefficiency due to imbalances in
station times
43Line Balancing Example
- EXAMPLE
- Green Grasss plant manager just received
marketings latest forecasts of fertilizer
spreader sales for the next year. She wants its
production line to be designed to make 2,400
spreaders per week. The plant will operate 40
hours per week.
- What should be the lines cycle time or
throughput rate per hour be? - Throughput rate/hr 2400 / 40 60 spreaders/hr
- Cycle Time 1/Throughput rate 1/60 1 minute
60 seconds
44Line balancing Example
- Assume that in order to produce the new
fertilizer spreader on the assembly line requires
doing the following steps in the order specified - What is the total number of stations or machines
required? - TM (total machines) total production time /
cycle time 244/60 4.067 or 5
Work Element Description Time (sec) Immediate Predecessor(s)
A Bolt leg frame to hopper 40 None
B Insert impeller shaft 30 A
C Attach axle 50 A
D Attach agitator 40 B
E Attach drive wheel 6 B
F Attach free wheel 25 C
G Mount lower post 15 C
H Attach controls 20 D, E
I Mount nameplate 18 F, G
Total 244
45Draw a Precedence Diagram
- SOLUTION
- The figure shows the complete diagram. We begin
with work element A, which has no immediate
predecessors. Next, we add elements B and C, for
which element A is the only immediate
predecessor. After entering time standards and
arrows showing precedence, we add elements D and
E, and so on. The diagram simplifies
interpretation. Work element F, for example,
can be done anywhere on the line after element
C is completed. However, element I must await
completion of elements F and G.
Precedence Diagram for Assembling the Big
Broadcaster
46Allocating work or activities to stations or
machines
- The goal is to cluster the work elements into
workstations so that - The number of workstations required is minimized
- The precedence and cycle-time requirements are
not violated
- The work content for each station is equal (or
nearly so, but less than) the cycle time for the
line
47Finding a Solution
- The minimum number of workstations is 5 and the
cycle time is 60 seconds, so Figure 5 represents
an optimal solution to the problem
Firtilizer Precedence Diagram Solution
48Calculating Line Efficiency
- c. Now calculate the efficiency measures of a
five-station solution
Balance delay () 100 Efficiency 100 -
81.3 18.7
Idle time nc ?t 5(60) 244 56 seconds
49A Line Process
- The desired output rate is matched to the
staffing or production plan - Line Cycle Time is the maximum time allowed for
work at each station is
where c cycle time in hours r desired
output rate
50A Line Process
- The theoretical minimum number of stations is
where ?t total time required to assemble each
unit
51A Line Process
- Idle time, efficiency, and balance delay
Idle time nc ?t
where n number of stations
Balance delay () 100 Efficiency
52Solved Problem 2
- A company is setting up an assembly line to
produce 192 units per 8-hour shift. The following
table identifies the work elements, times, and
immediate predecessors
Work Element Time (sec) Time (sec) Time (sec) Immediate Predecessor(s)
A 40 None
B 80 A
C 30 D, E, F
D 25 B
E 20 B
F 15 B
G 120 A
H 145 G
I 130 H
J 115 C, I
Total 720 Total 720 Total 720
53Solved Problem 2
- a. What is the desired cycle time (in seconds)?
- b. What is the theoretical minimum number of
stations? - c. Use trial and error to work out a solution,
and show your solution on a precedence diagram. - d. What are the efficiency and balance delay of
the solution found?
SOLUTION a. Substituting in the cycle-time
formula, we get
54Solved Problem 2
- b. The sum of the work-element times is 720
seconds, so
which may not be achievable.
55Solved Problem 2
- c. The precedence diagram is shown in Figure 7.6.
Each row in the following table shows work
elements assigned to each of the five
workstations in the proposed solution.
Work Element Immediate Predecessor(s)
A None
B A
C D, E, F
D B
E B
F B
G A
H G
I H
J C, I
Figure 7.6 Precedence Diagram
56Solved Problem 2
Station Candidate(s) Choice Work-Element Time (sec) Cumulative Time (sec) Idle Time(c 150 sec)
S1
S2
S3
S4
S5
A A 40 40 110
B B 80 120 30
D, E, F D 25 145 5
E, F, G G 120 120 30
E, F E 20 140 10
F, H H 145 145 5
F, I I 130 130 20
F F 15 145 5
C C 30 30 120
J J 115 145 5
57Solved Problem 2
- d. Calculating the efficiency, we get
96
Thus, the balance delay is only 4 percent
(10096).
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