Title: QNT 561 Week 4 Weekly Learning Assessments
1QNT 561 Week 4 Weekly Learning Assessments -
Assignment
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2Chapter 10 Exercise 2
The following information applies to the
questions displayed below. A sample of 36
observations is selected from a normal
population. The sample mean is 12, and the
population standard deviation is 3. Conduct the
following test of hypothesis using the 0.01
significance level H0 µ 10 H1 µ gt 10 1.
Award 10 out of 10.00 points a. Is this a one-
or two-tailed test? b. What is the decision
rule?
c. What is the value of the test statistic? d.
What is your decision regarding H0? e. What is
the p-value?
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3Chapter 10 Exercise 10
Given the following hypotheses H0 µ 400 H1
µ ? 400 A random sample of 12 observations is
selected from a normal population. The sample
mean was 407 and the sample standard deviation 6.
Using the .01 significance level a. State the
decision rule. (Negative amount should be
indicated by a minus sign. Round your answers to
3 decimal places.) b. Compute the value of the
test statistic. (Round your answer to 3 decimal
places.) c. What is your decision regarding the
null hypothesis?
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4Chapter 10 Exercise 12
The management of White Industries is considering
a new method of assembling its golf cart. The
present method requires 42.3 minutes, on the
average, to assemble a cart. The mean assembly
time for a random sample of 24 carts, using the
new method, was 40.6 minutes, and the standard
deviation of the sample was 2.7 minutes. Using
the .10 level of significance, can we conclude
that the assembly time using the new method is
faster? a. What is the decision rule? (Negative
amount should be indicated by a minus sign. Round
your answer to 3 decimal places.) b. Compute the
value of the test statistic. (Negative amount
should be indicated by a minus sign. Round your
answer to 3 decimal places.) c. What is your
decision regarding H0?
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5Chapter 10 Exercise 16
Given the following hypotheses H0 µ 100 H1
µ ? 100 A random sample of six resulted in the
following values 118, 105, 112, 119, 105, and
111. Assume a normal population. a. Using the
.05 significance level, determine the decision
rule? (Negative amounts should be indicated by a
minus sign. Round your answers to 3 decimal
places.) b. Compute the value of the test
statistic. (Round your answer to 2 decimal
places.) c-1. What is your decision regarding
the H0? c-2. Can we conclude the mean is
different from 100? d. Estimate the p-value.
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6Chapter 11 Exercise 2
A sample of 65 observations is selected from one
population with a population standard deviation
of 0.75. The sample mean is 2.67. A sample of 50
observations is selected from a second population
with a population standard deviation of 0.66. The
sample mean is 2.59. Conduct the following test
of hypothesis using the .08 significance
level. H0 µ1 µ2 H1 µ1 gt µ2 a. This a
-tailed test. b. State the decision rule.
(Negative values should be indicated by a minus
sign. Round your answer to 2 decimal places.) c.
Compute the value of the test statistic. (Round
your answer to 2 decimal places.) d. What is
your decision regarding H0? e. What is the
p-value? (Round your answer to 4 decimal places.)
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7Chapter 11 Exercise 8
The null and alternate hypotheses are A random
sample of 15 observations from the first
population revealed a sample mean of 350 and a
sample standard deviation of 12. A random sample
of 17 observations from the second population
revealed a sample mean of 342 and a sample
standard deviation of 15. At the .10
significance level, is there a difference in the
population means? a. This is a -tailed test.
b. The decision rule is to reject if
(Negative amounts should be indicated by a minus
sign. Round your answers to 3 decimal places.)
c. The test statistic is (Round your answer to
3 decimal places.) d. What is your decision
regarding? e. The p-value is between and.
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8Chapter 11 Exercise 14
The null and alternate hypotheses are H0 µ1
µ2 H1 µ1 gt µ2 A random sample of 20 items from
the first population showed a mean of 100 and a
standard deviation of 15. A sample of 16 items
for the second population showed a mean of 94 and
a standard deviation of 8. Use the .05
significant level. a. Find the degrees of
freedom for unequal variance test. (Round down
your answer to the nearest whole number.) b.
State the decision rule for .05 significance
level. (Round your answer to 3 decimal
places.) c. Compute the value of the test
statistic. (Round your answer to 3 decimal
places.) d. What is your decision regarding the
null hypothesis? Use the .05 significance level.
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9Chapter 12 Exercise 8
The following are six observations collected from
treatment 1, four observations collected from
treatment 2, and five observations collected from
treatment 3. Test the hypothesis at the 0.05
significance level that the treatment means are
equal.
Treatment1 Treatment 2 Treatment
3 9 13 10 7 20 9 11 14 15 9 13 14 12 15
10
a. State the null and the alternate
hypothesis. Ho H1 Treatment means are all
the same. b. What is the decision rule? (Round
your answer to 2 decimal places.) c. Compute
SST, SSE, and SS total. (Round your answers to 2
decimal places.) d. Complete the ANOVA table.
(Round SS, MS and F values to 2 decimal
places.) e. State your decision regarding the
null hypothesis.
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10Chapter 12 Exercise 14
A stock analyst wants to determine whether there
is a difference in the mean rate of return for
three types of stock utility, retail, and
banking stocks. The following output is
obtained a. Using the .05 level of
significance, is there a difference in the mean
rate of return among the three types of
stock? b. Can the analyst conclude there is a
difference between the mean rates of return for
utility and retail stocks? For utility and
banking stocks? For banking and retail stocks?
Explain.
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11Chapter 12 Exercise 18
There are three hospitals in the Tulsa, Oklahoma,
area. The following data show the number of
outpatient surgeries performed on Monday,
Tuesday, Wednesday, Thursday, and Friday at each
hospital last week. At the 0.05 significance
level, can we conclude there is a difference in
the mean number of surgeries performed by
hospital or by day of the week?
Number of Surgeries Performed Day St.
Luke's St. Vincent Mercy Monday 14 18 24 Tuesday
20 24 14 Wednesday 16 22 14 Thursday 18 20 22 F
riday 20 28 24
1.Set up the null hypothesis and the alternative
hypothesis. For Treatment Null hypothesis H0
µSt. Luke's µSt. Vincent 2. Alternative
hypothesis H1 Not all means are
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123. For blocks Null hypothesis H0 µMon µTue
µWed µThu 4. Alternative hypothesis H1 Not
all means are 5. State the decision rule for
.05 significance level. (Round your answers to 2
decimal places.) For Treatment Reject H0 if Fgt
For blocks Reject H0 if Fgt 6. Complete the
ANOVA table. (Round SS, MS and F to 2 decimal
places.) 7.What is your decision regarding the
null hypothesis? The decision for the F value
(Treatment) at 0.05 significance is Do not
Reject 8. The decision for the F value (Block)
at 0.05 significance is Do not Reject 9. Can
we conclude there is a difference in the mean
number of surgeries performed by hospital or by
day of the week? There is no in the mean number
of surgeries performed by hospital or by day of
the week.
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13Chapter 13 Exercise 16
Mr. James Mc Whinney, president of Daniel-James Financial Services, believes there is a relationship between the number of client contacts and the dollar amount of sales. To document this assertion, Mr. Mc Whinney gathered the following sample information. The X column indicates the number of client contacts last month, and the Y column shows the value of sales ( thousands) last month for each client sampled.
Number of Sales Number of Sales Contacts, (
thousands), Contacts, ( thousands), X Y X Y 1
4 24 23 30 12 14 48 90 20 28
50 85 16 30 55 120 46 80
50 110
- Determine the regression equation. (Negative
amounts should be indicated by a minus sign. Do
not round intermediate calculations. Round final
answers to 2 decimal places.) - Determine the estimated sales if 40 contacts are
made.(Do not round intermediate - calculations. Round final answers to 2 decimal
places.)
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14Chapter 13 Exercise 18
We are studying mutual bond funds for the purpose
of investing in several funds. For this
particular study, we want to focus on the assets
of a fund and its five-year performance. The
question is Can the five-year rate of return be
estimated based on the assets of the fund? Nine
mutual funds were selected at random, and their
assets and rates of return are shown below.
- Assets Return Assets Return
- Fund ( millions) () Fund ( millions) ()
- AARP High Quality Bond 622.20 10.8 MFS Bond
A 494.50 11.6 - Babson Bond L 160.4 11.3 Nichols
Income 158.3 9.5 - Compass Capital
- Fixed Income 275.7 11.4 T. Rowe Price
- Short-term 681 8.2
- Galaxy Bond Retail 433.2 9.1 Thompson
- Keystone Custodian B-1 437.9 9.2 Income B
241.3 6.8
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15b-1. Compute the coefficient of correlation.
(Round your answer to 3 decimal places. Negative
amount should be indicated by a minus
sign.) b-2. Compute the coefficient of
determination. (Round your answer to 3 decimal
places.) c. Give a description of the degree of
association between the variables. d. Determine
the regression equation. Use assets as the
independent variable. (Round your answers to 4
decimal places. Negative amounts should be
indicated by a minus sign.) e. For a fund with
400.0 million in sales, determine the five-year
rate of return (in percent). (Round your answer
to 4 decimal places.)
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16Chapter 13 Exercise 30
On the first statistics exam, the coefficient of
determination between the hours studied and the
grade earned was 80. The standard error of
estimate was 10. There were 20 students in the
class. Develop an ANOVA table for the regression
analysis of hours studied as a predictor of the
grade earned on the first statistics exam.
Source DF SS MS Regression Error Total
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