Title: Acids
1 2ARRHENIUS THEORYACIDS and BASES
- ACIDS - proton or H donor
- BASE - hydroxide or OH- donor
- NEUTRALIZATION - H OH- ?? H2O
- Problems
- H3O -- hydronium ion rather than H
- OH(H2O)3- -- not OH-
- Other substances have acidic or basic
properties also.
3H surrounded by four H-bonded H2O molecules
4OH- surrounded by three H-bonded H2O molecules
5Bronsted-Lowery TheoryAcids and Bases
- Acid any substance donating a proton, H
- Base any substance accepting a proton
- Conjugate Acid-Base Pairs
- e.g. HF NH3 ??? NH4 F-
- acid 1 base 2 acid 2
base 1 - AMPHOTERIC substances have both acidic and basic
properties. - Mono-, di-, tri-,. to polyprotic acids.
- Acidic versus nonacidic H atoms in compounds.
6- For each of the following reactions, identify
the acid, the base, the conjugate base, and the
conjugate acid - a. H2O H2O ??? H3O OH-
-
- b. CH3O- CH3CCH3 ??? CH3OH CH3C CH2
- c. H2S NH3 ??? HS- NH4
- d. H2SO4 H2O ??? H3O HSO4-
- e. H OH- ??? H2O
- f. H2PO4- H2O ??? H3PO4 OH-
- g. H2PO4- H2PO4- ??? H3PO4 HPO42-
- h. H2PO4- H2O ??? HPO42- H3O
- i. Fe(H2O)63 H2O ??? Fe(H2O)5(OH) 2
H3O - j. HCN CO32-??? CN- HCO3-
- k. CO2 2H2O ??? HCO3- H3O
O-
O
7Graphical representations of strong and weak acid
equilibria
8Acid strength versus conjugate base strength
9BRONSTED-LOWRY THEORY
- ACID and BASE STRENGTHS
- A proton transfers from a a stronger acid to a
stronger base, from a weaker acid and weaker
base. - LEVELING EFFECT of SOLVENTS
- The strongest acid in a solvent is the conjugate
acid of the solvent. The strongest base is the
conjugate base. - Acid H3O in water
- Base OH- in water
10Relative strengths of some Bronsted-Lowry acids
and their conjugate bases
- Acid Base
- Strongest HClO4 ClO4- Weakest
- Acid H2SO4 HSO4- bases
- HI I-
- HBr Br-
- HCl Cl-
- HNO3 NO3-
- H3O H2O
- HSO4- SO42-
- H2SO3 HSO3-
- H3PO4 H2PO4-
- HNO2 NO2-
- HF F-
- CH3CO2H CH3CO2-
- H2CO3 HCO3-
- H2S HS-
- NH4 NH3
- HCN CN-
- HCO3- CO32-
11STRONG ACIDS, BASES IN WATER
- Autoionization
- H2O(l) H2O(l) ??? H3O(aq) OH-(aq)
- Kw H3O OH- 1.0 x 10-14 at 25oC
- At equilibrium
- H3O OH-
- so each 1.0 x 10-7
- Kw changes with temperature
- but H3O OH-
12pH, pOH, pM, pX SCALES
- pH - log H3O
- pOH - log OH-
- pM - log M
- etc.
13pH, pOH CALCULATIONS
- pH - log H3O
- pOH - log OH-
- Kw H3O OH- 1.0 x 10-14
- so pH3O pOH- 14.00
- or pH 14.00 pOH
- CALULATE SOME pH and pOH VALUES
14- H pH
- 10-14 14 1 M NaOH
- 10-13 13
- Basic 10-12 12 Ammonia 10-11 11
- 10-10 10
- 10-9 9
- 10-8 8
- Neutral 10-7 7 Pure Water
- 10-6 6
- 10-5 5
- 10-4 4
- 10-3 3
- Acidic 10-2 2
- 10-1 1
- 1 0
(Household Cleaner)
Blood
Milk
Vinegar
Lemon juice
Stomach acid
1 M HCl
15- Calculate the pH of each solution
- a. H 1.4 x 10-3 M e. OH- 8 x 10-11 M
- b. H 2.5 x 10-10 M f. OH- 5.0 M
- c,. H 6.1 M g. pOH 10.5
- d. OH- 3.5 x 10-2 M h. pOH 2.3
- Calculate H and OH- for each solution
- a. pH 7.41 (the normal pH of blood)
- b. pH 15.3
- c. pH -1.0 e. pOH 5.0
- d. pH 3.2 f. pOH 9.6
- How many significant figures are there in the
numbers 10.78, 6.78, 0.78? If these were pH
values, to how many significant figures can you
express the H? Explain any discrepancies
between your answers to the two questions.
16- Values of Kw as a function of temperature are as
follows - Temp (oC) Kw
- 0 1.14 x 10-15
- 25 1.00 x 10-14
- 35 2.09 X 10-14
- 40 2.92 x 10-14
- 50 5.47 x 10-14
- a. Is the autoionization of water exothermic or
endothermic? - b. What is the pH of pure water at 50oC?
- c. Restate your answers to water at 50oC. Which
of the three criteria for neutrality is most
general? - d. From a plot of ln(Kw) versus 1/T (using the
Kelvin scale), estimate Kw at 37oC, normal
physiological temperature. - e. What is the pH of a neutral solution at 37oC?
17-28
Y -9.2338 6870.6x R2 0.999
-29
-30
ln Kw
-31
-32
-33
-34
-35
0.0028
0.0030
0.0032
0.0034
0.0036
1/T
18pH MEASUREMENT
- -- INDICATORS. colored weak acids and bases
- -- pH Meters. Glass membrane with a voltage
(potential) difference across the glass. - pH and BODY CHEMISTRY
- Normal pH 7.3 to 7.5
- Acidosis pH lt 7.3
- Alkalosis pH gt 7.45
- Body Chemistry is buffered with carbonates and
phosphates which reduce the acid/alkalinity
changes. These reduce the pH effects.
19WEAK ACIDSIONIZATION CONSTANTS
- HA(aq) H2O(l) ??? H3O(aq) A-(aq)
- Ka values at 25oC are known and tabulated for a
large number of weak acids.
20Graphic representations of strong and weak acid
equilibria
21Values of Ka for Some Common Monoprotic Acids
- Formula Name Value of Ka
- HSO4- Hydrogen sulfate ion 1.2 x 10-2
- HClO2 Chlorous acid 1.2 x 10-2
- HC2H2ClO2 Monochloroacetic acid 1.35 x 10-3
- HF Hydrofluoric acid 7.2 x 10-4
- HNO2 Nitrous acid 4.0 x 10-4
- HC2H3O2 Acetic acid 1.8 x 10-5
- Al(H2O)63 Hydrated aluminum (III) ion 1.4
x10-5 - HOCl Hypochlorous acid 3.5 x 10-8
- HCN Hydrocyanic acid 6.2 x 10-10
- NH 4 Ammonium ion 5.6 x 10-10
- HOC6H5 Phenol 1.6 x 10-10
- The units of Ka are mol/L, but are customarily
omitted.
Increasing acid strength
22- Write the dissociation reaction and the
corresponding equilibrium expression for each of
the following acids in water. - a. H3PO4 f. Acetic acid, CH3CO2H (HC2H3O2)
- b. H2PO4- g. Phenol, C6H5OH
- c. HPO42- h. Benzoic acid, C6H5CO2H
- d. Ti(H2O)64 i. Glycine, H2NCH2CO2H
- e. HCN
23- Write the reaction and the corresponding Kb
equilibrium expression for each of the following
substances acting as bases in water. - a. PO43- g. Glycine, NH2CH2CO2H
- b. HPO42- h. Ethylamine, CH3CH2NH2
- c. H2PO4- I. Aniline, C6H5NH2
- d. NH3 j. Dimethylamine, (CH3)2NH
- e. CN-
- f. Pyridine, C5H5N
24WEAK ACID CALCULATIONS
- HA(aq) H2O(l) ??? H3O(aq) A-(aq)
- 2H2O(l) ??? H3O(aq) OH-(aq)
- To simplify calculations, if ionization is lt
5, then CHA ? HA OR HA CHA H3O, - Set up pH equilibria calculations in tables as in
previous equilibria problems.
25Solving Weak Acid Equilibrium Problems
- List the major species in the solution
- Choose the species that can produce H, and write
balanced equations for the reactions producing H - Using the values of the equilibrium constants for
the reactions you have written, decide which
equilibrium will dominate in producing H - Write the equilibrium expression for the dominant
equilibrium. - List the initial concentrations of the species
participating in the dominant equilibrium. - Define the change needed to achieve equilibrium
that is, define x.. - Write the equilibrium concentrations in terms of
x. - Substitute the equilibrium concentrations into
the equilibrium expression. - Solve for x the easy way that is , by assuming
that HA0-x ? HA0. - Use the 5 rule to verify whether the
approximation is valid.
26- For trichlorophenol (HC6H2Cl3O), Ka 1 x
10-6, Calculate the concentrations of all
species and the pH of a 0.05 M solution of
trichlorophenol in water. - A solution is prepared by dissolving 0.56 g
benzoic acid (C6H5CO2H), Ka 6.4 x 10-5) in
enough water to make 1.0 L of solution.
Calculate C6H5CO2H. C6H5CO2-, H, OH-,
and the pH in this solution. - Calculate the pH of a solution containing a
mixture of 0.050 M HNO3 and 0.50M HC2H3O2.
27WEAK BASESIONIZATION CONSTANTS
- B(aq) H2O(l) ??? BH(aq) OH-(aq)
- Kb values at 25oC are tabulated or may be
calculated from Kw and Ka - Kw KaKb so Kb Kw/Ka
- Where Ka is the conjugate acid constant
28- Thallium (Tl) hydroxide is a strong base used in
the synthesis of some organic compounds.
Calculate the pH of a solution containing 2.48 g
TlOH per liter. - For the reaction of hydrazine (N2H4) in water.
- H2NNH2 H2O ??? H2NNH3 OH-
- Kb is 3.0 x 10-6. Calculate the concentrations
of all species and the pH of a 2.0 M solution of
hydrazine in water.
29Two Weak Acid in Solution
- A solution of 0.100 M HClO, Ka 3.5 x 10-8 and
0.100 M Formic acid, HCO2H, Ka 1.8 x 10-4 are
mixed. What is the resulting solution pH?
30Polyprotic Acid Equilibria
- What is the pH of a solution 0.100 M sulfurous
acid, H2SO3, Ka1 1.5 x 10-2 and Ka2 1.0 x
10-7?
31ACID-BASE PROPERTIES OF THE OXIDES (PART I)
32ACID BASE PROPERTIES OF THE OXIDES (PART II)
33ACID-BASE PROPERTIES OF THE OXIDES (PART III)
34ACID BASE PROPERTIES OF THE OXIDES (PART IV)
35ACID-BASE PROPERTIES OF THE OXIDES (PART V)
36ACID BASE PROPERTIES OF THE OXIDES PART (VI)
37 ACID BASE PROPERTIES OF THE OXIDES PART (VII)
38 ACID-BASE PROPERTIES OF THE OXIDES PART (VIII)
39BRONSTED-LOWRY THEORY
- OXIDES, HYDROXIDES, ANHYDRIDES
- Acid, base reactions
- Dehydrations (formation of anhydrides)
- Hydration of oxides
40ACID STRENGTHSof WEAK ACIDS
- Oxoacids Ka ? up as the central atom
- oxidation state ? up.
- Ka ? up as central atom of same oxidation state
moves left to right in the periodic table. - Ka ? up as the central atom of the same
oxidation state moves UP in the same Group or
family. - Polyprotic acids
- Ka decreases by approximately 105 for each
successive H ionized. - Binary acids (only H and another element)
- Within a period, Ka ? up as electronegativity
of the other element. - Within a group, Ka ? up going down the group
to higher mass and larger size.
41- SnO2 ? H2O ?? ?
- ?HCrO4- ?? ?Cr2O72- ?
- ?HMnO4- ?? ? Mn (VI) compound ?
42HYDROLOYSIS OF IONIC SALTS
- The pH of each type salt in solution depends on
the Ka or Kb of the hydrolyzing ion(s).
43- Salt Derived Ions Undergoing
- From Hydrolysis pH Examples
- Strong base Neither Neutral NaCl, KNO3,
- strong acid pH 7 BaCl2, CaBr2
- Strong base Anion Basic LiCN, KNO2, CaF2
- weak acid pH gt 7 NaCH3CO2
- Weak base Cation Acidic, NH4Cl, Al(NO3)3,
- strong acid pH lt 7 (CH3)3NHBr
- Weak base, Both Acidic NH4NO2
- weak acid if Kblt Ka
- Neutral NH4CH3CO2
- if Kb Ka
- basic NH4CN
44- Arrange the following 0.10 M solutions in order
from most acidic to most basic - KOH, KBr, KCN, NH4Br, NH4CN, HCN
- Given that the Ka value for acetic acid is 1.8 x
10-5 and the Ka value for hypochlorous acid is 3
x 10-8, which is the stronger base, OCl- or
C2H3O2-
45- Acid-Base Equilibria
- What is the pH of a solution of 0.150 M sodium
nitrite, NaNO2? - HNO2, Ka 4.0 x 10-4.
- What is the pH of a solution of 0.150 M
hydrazinnium chloride, H2NNH3? - H2NNH3, Kb 3.0 x 10-6
46- Calculate the pH of each of the following
solutions. - a. 0.10 M CH3NH3Cl
- b. 0.050 M NaCN
- c. 0.20 M Na2CO3 (consider only the reaction )
- CO32- H2O ?? HCO3- OH-
- Sodium azid (NaN3) is sometimes added to water to
kill bacteria. Calculate the concentration of
all species in a 0.010 M solution of NaN3. The
Ka value for hydrazoic acid (HN3) is 1.9 x 10-5.
47LEWIS THEORYACIDS and BASES
- Lewis base - an electron pair donor
- Lewis acid - an electron pair acceptor
- Lewis acid Lewis base ??? Adduct
- (coordination compound)
- e.g. Cu2(aq) 4CN-(aq) ?? Cu(CN)42-(aq)
- Look at Lewis Dot structures for lone pairs.