Title: 11/4 Torque in Equilibrium
111/4 Torque in Equilibrium
- Today Finding Torque, ? Your Lab
- HW 11/4 HW Handout Extended FBD and Torque due
Thur 11/7 (None due Wed) - Exam 3 Thursday, 11/14
- Example problem
2Torque
Max torque
0 torque
Medium torque
Pivot (axis)
3Perpendicular force method
F? ?
F sin ?
?
Torque ? F? ? distance from axis (r)
? r F sin ?
4Lever arm method
? r F sin ?
F? ?
F sin ?
?
l r sin ?
? F l
F r sin ?
90
?
90
r
5Torque
- Depends on
- Size of the force
- Distance from the axis (you choose axis!!!)
- Angle of the force with respect to a line drawn
to the axis from location the force is applied. - Must draw an extended FBD!!
6CM in Lab
Where is the center of mass of the bar?
F1
O
F3
equilibrium
F2
F4 mbarg but where is it applied?
D
7Example
Find the tension in the angled string and the
force (magnitude and direction) the pivot puts on
the bar.
1kg
?
30
2m
3kg
?CW ?CCW ? 0
W(1) T2(2) T1,?(2)
10 60 T1,?(2)
T1,? 35N
T1,? T1sin30
T1 70N
Note FBD not to scale
8Example
Find the tension in the angled string and the
force (magnitude and direction) the pivot puts on
the bar.
T1 70N
1kg
?
30
2m
3kg
?CW ?CCW ? 0
FUp FDown a 0
Can use either concept to get pivot force of 61N
at 4.7 above horizontal toward the right.
Will need to pick a new axis to use torque.