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Solutions to Problems Chapter 1 DecisionMaking Under Uncertainty

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... ranks lotteries according to: V( , 2)= (10- ) (a) Lottery p pays 10 with probability 1; Lottery q pays ... Max V(a,b)=0.5u(2a b) 0.5u(b) Subject to qa b W0 10 ... – PowerPoint PPT presentation

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Title: Solutions to Problems Chapter 1 DecisionMaking Under Uncertainty


1
Solutions to Problems Chapter 1 Decision-Making
Under Uncertainty
  • Exercise 1
  • (a) There are 27 different functions
  • (b) One can draw a 3-dimensional space for f(s1),
    f(s2), f(s3) which each three cases
  • (c) Let (p?,p?,p?) be a probability distribution
    over the consequences. See the next slide for a
    plot.

2
Probability distribution
p?
1
2/3
1/3
1/3
2/3
1
p?
3
Exercise 3
  • U(x1,x2)pu(x1)(1-p)u(x2). u(.) is concave.
  • The MRS(x1,x2)p/(1-p). u(x1)/u(x2)

x2
U(x1,x2)
p/1-p
x1
0
4
Exercise 3 (continued)
  • (b) V(p1,p2,p3)p1u(x1)p2u(x2)p3u(x3)
  • pi?0 and p1p2p31
  • For constant utility levels k we can rewrite
  • p3(k-u(x2))/(u(x3)-u(x2))
    (u(x1)-u(x2))/(u(x3-u(x2)).p1

5
Exercise 3 (continued)
p3
1
Higher levels of utility
p1
0
1
6
Exercise 4(a)
  • A decision maker ranks lotteries according to
    V(?,?2)?(10-?)
  • (a) Lottery p pays 10 with probability 1 Lottery
    q pays 10 or 20 wit probability ½
  • ?xpx1(1-p)x2, ?x2p(x1- ?x)2(1-p)(x2- ?x)2, so
    ?p10, ?p20, ?q15, and ?q225, so Vp100 and
    Vq75

7
Exercise 5(b)
  • (i) Ra(x) -b lnA
  • (ii) Ra(x) ?/x
  • (iii) Ra(x) 1/x
  • (iv) Ra(x)-2a/(2ax1)
  • Rr(x) -x b lnA
  • Rr(x) ?
  • Rr(x) 1
  • Rr(x) -2ax/(2ax1)

8
Exercise 6
  • u(x)x-0.05 x2 and initial wealth W0lt10.
  • Two assets a bond has a price 1 and returns 1
    unit, a stock costs qlt1 and returns 2 in state 1
    and 0 in state 2. The probability of state 1 (2)
    is equal to 0.5
  • Amount invested in stock is a, in bonds b
  • Pay-off in state 1 is 2ab, in state 2 b

9
Exercise 6 (continued)
  • Max V(a,b)0.5u(2ab)0.5u(b)
  • Subject to qab?W0lt10
  • V(a,b)0.5(2ab)-0.025(2ab)20.5b-0.025b2ab-0.0
    25 (4a24abb2b2)ab-0.1a2-0.1ab-0.05b2
  • La(W0-qa)-0.1a2-0.1a(W0-qa)-0.05(W0-qa)2
  • ?L/?a1-q-0.2a-0.1W00.2qa0.1q(W0-qa)0
  • (0.2q-0.1q2-0.2)q-10.1W0-0.1qW0
  • a(10-W0)(1-q)/(q2-2q2)
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