Title: Advanced propulsion systems 3 lectures
1Advanced propulsion systems (3 lectures)
- Hypersonic propulsion background (Lecture 1)
- Why hypersonic propulsion?
- Whats different at hypersonic conditions?
- Real gas effects (non-constant CP, dissociation)
- Aircraft range
- How to compute thrust?
- Idealized compressible flow (Lecture 2)
- Isentropic, shock, friction (Fanno)
- Heat addition at constant area (Rayleigh), T, P
- Hypersonic propulsion applications (Lecture 3)
- Ramjet/scramjets
- Pulse detonation engines
21D steady flow of ideal gases
- Assumptions
- Ideal gas, steady, quasi-1D
- Constant CP, Cv, ? ? CP/Cv
- Unless otherwise noted adiabatic, reversible,
constant area - Note since 2nd Law states dS ?Q/T ( for
reversible, gt for irreversible), reversible
adiabatic ? isentropic (dS 0) - Governing equations
- Equations of state
- Isentropic (S2 S1) (where applicable)
- Mass conservation
- Momentum conservation, constant area duct
- Cf friction coefficient C circumference of
duct - No friction
- Energy conservation
- q heat input per unit mass fQR if due to
combustion - w work output per unit mass
31D steady flow of ideal gases
- Types of analyses everything constant except
- Area (isentropic nozzle flow)
- Entropy (shock)
- Momentum (Fanno flow) (constant area with
friction) - Diabatic (q ? 0) - several possible assumptions
- Constant area (Rayleigh flow) (useful if limited
by space) - Constant T (useful if limited by materials)
(sounds weird, heat addition at constant T) - Constant P (useful if limited by structure)
- Constant M (covered in some texts but really
contrived, lets skip it) - Products of analyses
- Stagnation temperature
- Stagnation pressure
- Mach number u/c u/(?RT)1/2 (c sound speed
at local conditions in the flow (NOT at ambient
condition!)) - From this, can get exit velocity ue, exit
pressure Pe and thus thrust
4Isentropic nozzle flow
- Reversible, adiabatic ? S constant, A ?
constant, w 0 - Momentum equation not used - simple constant-area
form (slide 15) doesnt apply - Recall stagnation temperature Tt temperature of
gas stream when decelerated adiabatically to M
0 - Thus energy equation becomes simply T1t T2t,
which simply says that the sum of thermal energy
(the 1 term) and kinetic energy (the (?-1)M2/2
term) is a constant
5Isentropic nozzle flow
- Pressure is related to temperature through
isentropic compression law - Recall stagnation pressure Pt pressure of gas
stream when decelerated adiabatically and
reversibly to M 0 - Thus the pressure / Mach number relation is
simply P1t P2t
6Isentropic nozzle flow
- Relation of P T to duct area A determined
through mass conservation - But for adiabatic reversible flow T1t T2t and
P1t P2t also define throat area A area at M
1 then - A/A shows a minimum at M 1, thus it is indeed
a throat
7Isentropic nozzle flow
- Mass flow and velocity can be determined
similarly
8Isentropic nozzle flow
- Summary
-
- A area at M 1
- Implications
- P and T decrease monotonically as M increases
- Area is minimum at M 1 - need a throat to
transition from M lt 1 to M gt 1 or vice versa - mdot/A is maximum at M 1 - flow is choked at
throat - if flow is choked then any change in
downstream conditions cannot affect mdot - Note for supersonic flow, M (and u) INCREASE as
area increases - this is exactly opposite
subsonic flow as well as intuition (e.g. garden
hose - velocity increases as area decreases)
9Isentropic nozzle flow
A/A
T/Tt
P/Pt
10Isentropic nozzle flow
- When can choking occur? If M 1 or
- so need pressure ratio gt 1.89 for choking (if
all assumptions satisfied) - Where did Pt come from? Mechanical compressor
(turbojet) or vehicle speed (high flight Mach
number M1) - Where did Tt come from? Combustion! (Even if at
high M thus high Tt, no thrust unless Tt
increased!) (Otherwise just reversible
compression expansion)
11Stagnation temperature and pressure
- From previous page
- No thrust if P1t P9t,P9 P1 T1t T9t to
get thrust we need either - T9t T1t, P9t P1t P1 P9 lt P1
- (e.g. tank of high-P, ambient-T gas,
- reversible adiabatic expansion)
- B. T9t gt T1t, P9t P1t gt P1 P9
- (e.g. high-M ramjet/scramjet,
- no Pt losses)
- C. T9t gt T1t, P9t gt P1t P1 P9
- (e.g. low-M turbojet or fan)
- Fan T9t/T1t (P9t/P1t)(?-1)/?
- due to adiabatic compression
- Turbojet T9t/T1t gt (P9t/P1t)(?-1)/?
- due to adiabatic compression
- plus heat addition
- Could get thrust even with
P9t P1t P9 lt P1 T9t T1t
P1 P1t (M1 0)
Case A
P9t P1t P9 P1 T9t gt T1t
P1t gt P1 (M1 gt 0)
Case B
P9t gt P1t P9 P1 T9t gt T1t
P1t P1 (M1 0)
Case C
12Stagnation temperature and pressure
- Note also ?(Tt) heat or work transfer
13Constant everything except S (shock)
- Q what if A constant but S ? constant? Can
anything happen while still satisfying mass,
momentum, energy, eqn. of state? - A YES! (shock)
- Implications
- One possibility is no change in state ( )1 ( )2
- If M1 gt 1 then M2 lt 1 and vice versa - equations
dont show a preferred direction, but only M1 gt
1, M2 lt 1 results in dS gt 0, thus M1 lt 1, M2 gt 1
is impossible - Tt constant (no change in total enthalpy) but Pt
decreases across shock (a lot if M gtgt 1!), P, T
increase - Note there are only 2 states, ( )1 and ( )2 - no
continuum of states
14Constant everything except S (shock)
T2/T1
P2/P1
T2t/T1t
M2
P2t/P1t
15Everything constant except momentum (Fanno flow)
- Since friction loss is path dependent, need to
use differential form of momentum equation
(constant A by assumption) - Combine and integrate with differential forms of
mass, energy, eqn. of state from Mach M to
reference state ( ) at M 1 (not a throat in
this case since constant area!) - Implications
- Stagnation pressure always decreases towards M
1 - Cant cross M 1 with constant area with
friction! - M 1 corresponds to the maximum length (L) of
duct that can transmit the flow for the given
inlet conditions (Pt, Tt) and duct properties
(C/A, Cf)
16Everything const. but momentum (Fanno flow)
- What if neither the initial state (1) nor final
state (2) is the choked () state? Again use
P2/P1 (P2/P)/(P1/P) etc., except for L, where
we subtract to get net length ?L
17Everything constant except momentum
Pt/Pt
Tt/Tt
T/T
Length
P/P
Length
18Everything constant except momentum
Pt/Pt
P/P
Length
Tt/Tt
T/T
Length
19Heat addition at constant area (Rayleigh flow)
- Mass, momentum, energy, equation of state all
apply - Reference state ( ) use M 1 (not a throat in
this case!) - Energy equation not useful except to calculate
heat input (q Cp(T2t - T1t)) or dimensionless
q/CPTt 1 - Tt/Tt) - Implications
- Stagnation pressure always decreases towards M
1 - Stagnation temperature always increases towards M
1 - Cant cross M 1 with constant area heat
addition! - M 1 corresponds to the maximum possible heat
addition - but theres no particular reason we have to keep
area (A) constant when we add heat!
20Heat addition at const. Area (Rayleigh flow)
- What if neither the initial state (1) nor final
state (2) is the choked () state? Again use
P2/P1 (P2/P)/(P1/P) etc.
21Heat addition at constant area
Pt/Pt
Tt/Tt
T/T
P/P
22T-s diagram - reference state M 1
Fanno
M lt 1
Shock
Rayleigh
M lt 1
M gt 1
23T-s diagram - Fanno, Rayleigh, shock
Rayleigh
Shock
Constant area, with friction, no heat addition
M lt 1
Constant area, no friction, with heat addition
Fanno
M lt 1
M gt 1
This jump constant area, no friction, no heat
addition ? SHOCK!
M gt 1
24Heat addition at constant pressure
- Relevant for hypersonic propulsion if maximum
allowable pressure (i.e. structural limitation)
is the reason we cant decelerate the ambient air
to M 0) - Momentum equation AdP mdotdu 0 ? u
constant - Reference state ( ) use M 1 again but nothing
special happens there - Again energy equation not useful except to
calculate q - Implications
- Stagnation temperature increases as M decreases,
i.e. heat addition corresponds to decreasing M - Stagnation pressure decreases as M decreases,
i.e. heat addition decreases stagnation T - Area increases as M decreases, i.e. as heat is
added
25Heat addition at constant pressure
- What if neither the initial state (1) nor final
state (2) is the reference () state? Again use
P2/P1 (P2/P)/(P1/P) etc.
26Heat addition at constant P
Pt/Pt
P/P
Tt/Tt
T/T, A/A
27Heat addition at constant temperature
- Probably most appropriate case for hypersonic
propulsion since temperature (materials) limits
is usually the reason we cant decelerate the
ambient air to M 0 - T constant ? c (sound speed) constant
- Momentum AdP mdotdu 0 ? dP/P ?MdM 0
- Reference state ( ) use M 1 again
- Implications
- Stagnation temperature increases as M increases
- Stagnation pressure decreases as M increases,
i.e. heat addition decreases stagnation T - Minimum area (i.e. throat) at M ?-1/2
- Large area ratios needed due to exp term
28Heat addition at constant temperature
- What if neither the initial state (1) nor final
state (2) is the reference () state? Again use
P2/P1 (P2/P)/(P1/P) etc.
29Heat addition at constant T
Tt/Tt
A/A
T/T
Pt/Pt
P/P
30T-s diagram for diabatic flows
Const P
Const T
Rayleigh (Const A)
Rayleigh (Const A)
31Pt vs. Tt for diabatic flows
Rayleigh (Const A)
Const P
Rayleigh (Const A)
Const T
32Area ratios for diabatic flows
Const T
Const T
Const P
Const A
33Summary
- Choking - mass, heat addition at constant area,
friction with constant area - at M 1 - Supersonic results usually counter-intuitive
- If no friction, no heat addition, no area change
- its a shock! - Which is best way to add heat?
- If maximum T or P is limitation, obviously use
that case - What case gives least Pt loss for given increase
in Tt? - Minimize d(Pt)/d(Tt) subject to mass, momentum,
energy conservation, eqn. of state - Result (Lots of algebra - many trees died to
bring you this result) - Adding heat (increasing Tt) always decreases Pt
- Least decrease in Pt occurs at lowest possible M
34Summary
35Summary of heat addition processes