Young's DoubleSlit PHY 213 and PHY 201

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Young's Double-SlitPHY 213 and PHY 201

• Important points to consider
•  
• The value of m is determined by which points you
  choose, to find "y". If you solve for ? using the
  distance (y) from the center maximum fringe to
  the first maximum fringe, then m 1.

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The Problem In a certain Youngs double-slit
experiment for which L 1.00 m and d 0.10 cm,
the bright fringes are 0.050 cm apart. What
wavelength of light is being used?
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Bright fringes are points on the screen which
represent areas of maximum constructive
interference bright spots for light and loud
spots for sound. In this example, two bright
fringes are located at m 1 and m 0. At m
0, the path difference for waves leaving points A
and B equals 0. At m 1, this path difference
equals one wavelength or m?. Upon solving the
triangle below, this path difference becomes (d
sin ?).
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Now, because this opposite side is the path
difference, m?
If we choose the point, m 1, and we know the
value of d, all that is needed is ?.
m 1
y
?
L
m 0
The bright fringes (m 0, m 1) are 0.050 cm
apart.
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