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Algebra 2

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Algebra 2. Section 2-4. Writing Linear Equations. What You'll Learn. Why ... At what number does this vertical line pass through the x-axis? At x = 6. THE END ... – PowerPoint PPT presentation

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Title: Algebra 2


1
Algebra 2
  • Section 2-4
  • Writing Linear Equations

2
What You'll LearnWhy It's Important
  • To write an equation of a line in slope-intercept
    form given the slope and one or two points, and
  • To write an equation of a line that is parallel
    or perpendicular to the graph of a given equation
  • You can use equations to explore relations in
    telecommunications and business

3
Slope-Intercept Form of a Linear Equation
  • The slope-intercept form of the equation of a
    line is y mx b, where m is the slope and b is
    the y-intercept

4
Example 1
  • Find the slope-intercept form of an equation of
    the line that has a slope of -? and passes
    through (-6,1).

5
Solution Example 1
  • Find the slope-intercept form of an equation of
    the line that has a slope of-? and passes
    through (-6,1).
  • You know the slope and the x and y values of one
    point on the graph. Substitute for m, x , and y
    in the slope-intercept form.
  • ymx b m-?, x -6, y1
  • 1(-?)(-6) b
  • 1 4 b
  • -3 b The y-intercept is -3.
  • Replace m and b in the formula ymx b with
    their values
  • So, the equation is slope-intercept form is y
    -?x - 3

6
Graph of y -?x - 3
7
Point-Slope Form of a Linear Equation
  • The point-slope form of the equation of a line is
    y y1 m(x x1) where (x1,y1) are the
    coordinates of a point on the line and m is the
    slope of the line.

8
Example 2
  • Find an equation of the line that passes through
    (3,2) and (5,3)
  • Hint you need to find the slope and
    they-interceptSlope Formula ?

9
Solution Example 2
  • Find an equation of the line that passes through
    (3,2) and (5,3)
  • First use the two points given to find the slope
    of the line.
  • Then use the point-slope form to write the linear
    equation. y y1 m(x x1) m½,
    x13, y12
  • y 2 ½(x - 3) (distribute to get rid of
    parentheses)
  • (add 2 to each side to
    isolate y)
  • y ½x ½

10
Solution Example 2
  • Find an equation of the line that passes through
    (3,2) and (5,3)
  • I could have used (5,3) as x1 and y1
  • Then use the point-slope form to write the linear
    equation. y y1 m(x x1) m½,
    x15, y13
  • y 3 ½(x - 5) (distribute to get rid of
    parentheses)
  • (add 3 to each side to
    isolate y)
  • y ½x ½

11
Real Life ApplicationRenting a Car
3 min 4 sec
12
Example 3
  • With a certain long-distance company, the price
    of a 4-minute long-distance call is 1.70. An
    11-minute call with the same company costs 4.15.
  • a. Write a linear equation that describes the
    cost of these telephone calls. Assume that the
    changes increase linearly.
  • b. How much would a 20-minute telephone call cost?

13
Solution Example 3A
  • With a certain long-distance company, the price
    of a 4-minute long-distance call is 1.70. An
    11-minute call with the same company costs 4.15.
  • a. Write a linear equation that describes the
    cost of these telephone calls. Assume that the
    changes increase linearly.
  • The line passes through the points (4,1.70) and
    (11,4.15). Find the slope of the line.
  • Now use the point-slope from to write the linear
    equation. y y1 m(x x1) m0.35,
    x14, y11.70
  • y 1.70 0.35(x - 4) (distribute to get rid of
    parentheses)
  • y-1.70 0.35x 1.4 (add 1.70 to each side to
    isolate the y)
  • y0.35x 0.3

14
Solution Example 3b
  • With a certain long-distance company, the price
    of a 4-minute long-distance call is 1.70. An
    11-minute call with the same company costs 4.15.
  • b. How much would a 20-minute telephone call
    cost?
  • y0.35x 0.3
  • y0.35(20) 0.3
  • y70.3
  • y7.30
  • A 20-minute call would cost 7.30

15
Example 4Integration Geometry
  • Write an equation of the line that passes through
    (-9,5) and is perpendicular to the line whose
    equation is y-3x 2

16
Solution Example 4Integration Geometry
  • Write an equation of the line that passes through
    (-9,5) and is perpendicular to the line whose
    equation is y-3x 2
  • The slope of the given line is -3. So the slope
    of the perpendicular line is the opposite
    reciprocal of -3/1 which is 1/3
  • You can use either ymx b or y y1 m(x x1)
  • y mx b m?, x-9, y5
  • 5 ?(-9) b
  • 5 -3b
  • b 8
  • y ?x 8

When you graph both lines on a graphing
calculator sometimes you need to zoom in to see
the 90 degree angle
17
Special Case
  • Write an equation in slope-intercept form that
    satisfies each condition.
  • Passes through (6,2) and (6,5)

18
Solution Special Case
  • Write an equation in slope-intercept form that
    satisfies each condition.
  • Passes through (6,2) and (6,5)
  • Find the slopeThe slope is undefined, so the
    line is vertical
  • Vertical lines cross the x-axis
  • At what number does this vertical line pass
    through the x-axis?
  • At x 6

19
THE END
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