Lecture 4 Voltage and Current Dividers PowerPoint PPT Presentation

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Title: Lecture 4 Voltage and Current Dividers


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Lecture 4Voltage and Current Dividers
  • ECE 205
  • Prof. Ali Keyhani

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Voltage Division
  • Provides a simple way to find the voltage across
    an element in a series circuit without solving
    the circuit equations

The elements are in series so the same current
passes through each resistor
Using Ohms law the voltage across each resistor
is found
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Voltage Division
  • From the equations a pattern is derived for the
    series connected resistors
  • The voltage across each resistor is equal to its
    resistance divided by the equivalent series
    resistance of the connection times the voltage
    across the series circuit.

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Example 1
  • a) Find the voltage across the 560 O resistor.

b) Assume Ro is not known. Find the value of Ro
so that the voltage across the Vo is 6 V
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Example 2
  • What is the voltage Vo when D1 and D0 are closed?
  • B) What is the voltage value is D0 is open
  • and D1 is closed?

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Current Division
  • Provides a simple way to find the current through
    an element in a parallel circuit without solving
    the circuit equations

The elements are in parallel so the same voltage
appears across each conductance
Using Ohms law the current through each resistor
is found
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Current Division
  • From the equations a pattern is derived for the
    resistors connected in parallel
  • The source current divides among the parallel
    resistors in proportion to their conductances
    divided by the equivalent conductances in
    parallel connection.

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Example 3
  • Find the current ix.
  • Solution The circuit is divided into two paths.
    Then the current division rule is applied to the
    equivalent circuit.
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