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Sampling Distributions for Proportions

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When using the normal distribution (which is continuous) to approximate p-hat, a ... Is it appropriate to the normal distribution? Find the mean and the ... – PowerPoint PPT presentation

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Title: Sampling Distributions for Proportions


1
Sampling Distributions for Proportions
  • Allow us to work with the proportion of successes
    rather than the actual number of successes in
    binomial experiments.

2
Sampling Distribution of the Proportion
  • n number of binomial trials
  • r number of successes
  • p probability of success on each trial
  • q 1 - p probability of failure on each trial

3
Sampling Distribution of the Proportion
  • If np gt 5 and nq gt 5 then p-hat r/n can be
    approximated by a normal random variable (x)
    with

4
The Standard Error for
5
Continuity Correction
  • When using the normal distribution (which is
    continuous) to approximate p-hat, a discrete
    distribution, always use the continuity
    correction.
  • Add or subtract 0.5/n to the endpoints of a
    (discrete) p-hat interval to convert it to a
    (continuous) normal interval.

6
Continuity Correction
  • Since n 20,
  • .5/n 0.025
  • 5/8 - 0.025 0.6
  • 6/8 0.025 0.775
  • Required x interval is 0.6 to 0.775
  • If n 20, convert a p-hat interval from 5/8 to
    6/8 to a normal interval.
  • Note 5/8 0.625
  • 6/8 0.75
  • So p-hat interval is 0.625 to 0.75.

7
Suppose 12 of the population is in favor of a
new park.
  • Two hundred citizen are surveyed.
  • What is the probability that between10 and 15
    of them will be in favor of the new park?

8
Is it appropriate to the normal distribution?
  • 12 of the population is in favor of a new park.
  • p 0.12, q 0.88
  • Two hundred citizen are surveyed.
  • n 200
  • Both np and nq are greater than five.

9
Find the mean and the standard deviation
10
What is the probability that between 10 and
15of them will be in favor of the new park?
  • Use the continuity correction
  • Since n 200, .5/n .0025
  • The interval for p-hat (0.10 to 0.15) converts to
    0.0975 to 0.1525.

11
Calculate z-score for x 0.0975
12
Calculate z-score for x 0.1525
13
P(-0.98 lt z lt 1.41)
  • 0.9207 -- 0.1635 0.7572
  • There is about a 75.7 chance that between 10
    and 15 of the citizens surveyed will be in favor
    of the park.

14
Control Chart for Proportions
  • P-Chart

15
Constructing a P-Chart
  • Select samples of fixed size n at regular
    intervals.
  • Count the number of successes r from the n
    trials.
  • Use the normal approximation for r/n to plot
    control limits.
  • Interpret results.

16
Determining Control Limits for a P-Chart
  • Suppose employee absences are to be plotted.
  • In a daily sample of 50 employees, the number of
    employees absent is recorded.
  • p/n for each day number absent/50.For the
    random variable p-hat p/n, we can find the mean
    and the standard deviation.

17
Finding the mean and the standard deviation
18
Is it appropriate to use the normal distribution?
  • The mean of p-hat p 0.12
  • The value of n 50.
  • The value of q 1 - p 0.88.
  • Both np and nq are greater than five.
  • The normal distribution will be a good
    approximation of the p-hat distribution.

19
Control Limits
  • Control limits are placed at two and three
    standard deviations above and below the mean.

20
Control Limits
The center line is at 0.12. Control limits are
placed at -0.018, 0.028, 0.212, and 0.258.
21
Control Chart for Proportions
Employee Absences 0.3 3s 0.258
0.2 2s 0.212 0.1 mean 0.12
0.0 -2s 0.028 -0.1 -3s
-0.018
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