Title: Sampling Distributions for Proportions
1Sampling Distributions for Proportions
- Allow us to work with the proportion of successes
rather than the actual number of successes in
binomial experiments.
2Sampling Distribution of the Proportion
- n number of binomial trials
- r number of successes
- p probability of success on each trial
- q 1 - p probability of failure on each trial
3Sampling Distribution of the Proportion
- If np gt 5 and nq gt 5 then p-hat r/n can be
approximated by a normal random variable (x)
with
4The Standard Error for
5Continuity Correction
- When using the normal distribution (which is
continuous) to approximate p-hat, a discrete
distribution, always use the continuity
correction. - Add or subtract 0.5/n to the endpoints of a
(discrete) p-hat interval to convert it to a
(continuous) normal interval.
6Continuity Correction
- Since n 20,
- .5/n 0.025
- 5/8 - 0.025 0.6
- 6/8 0.025 0.775
- Required x interval is 0.6 to 0.775
- If n 20, convert a p-hat interval from 5/8 to
6/8 to a normal interval. - Note 5/8 0.625
- 6/8 0.75
- So p-hat interval is 0.625 to 0.75.
7Suppose 12 of the population is in favor of a
new park.
- Two hundred citizen are surveyed.
- What is the probability that between10 and 15
of them will be in favor of the new park?
8Is it appropriate to the normal distribution?
- 12 of the population is in favor of a new park.
- p 0.12, q 0.88
- Two hundred citizen are surveyed.
- n 200
- Both np and nq are greater than five.
9Find the mean and the standard deviation
10What is the probability that between 10 and
15of them will be in favor of the new park?
- Use the continuity correction
- Since n 200, .5/n .0025
- The interval for p-hat (0.10 to 0.15) converts to
0.0975 to 0.1525.
11Calculate z-score for x 0.0975
12Calculate z-score for x 0.1525
13P(-0.98 lt z lt 1.41)
- 0.9207 -- 0.1635 0.7572
- There is about a 75.7 chance that between 10
and 15 of the citizens surveyed will be in favor
of the park.
14Control Chart for Proportions
15Constructing a P-Chart
- Select samples of fixed size n at regular
intervals. - Count the number of successes r from the n
trials. - Use the normal approximation for r/n to plot
control limits. - Interpret results.
16Determining Control Limits for a P-Chart
- Suppose employee absences are to be plotted.
- In a daily sample of 50 employees, the number of
employees absent is recorded. - p/n for each day number absent/50.For the
random variable p-hat p/n, we can find the mean
and the standard deviation.
17Finding the mean and the standard deviation
18Is it appropriate to use the normal distribution?
- The mean of p-hat p 0.12
- The value of n 50.
- The value of q 1 - p 0.88.
- Both np and nq are greater than five.
- The normal distribution will be a good
approximation of the p-hat distribution.
19Control Limits
- Control limits are placed at two and three
standard deviations above and below the mean.
20Control Limits
The center line is at 0.12. Control limits are
placed at -0.018, 0.028, 0.212, and 0.258.
21Control Chart for Proportions
Employee Absences 0.3 3s 0.258
0.2 2s 0.212 0.1 mean 0.12
0.0 -2s 0.028 -0.1 -3s
-0.018