Section 12'4: Expected Value - PowerPoint PPT Presentation

1 / 26
About This Presentation
Title:

Section 12'4: Expected Value

Description:

... incorrectly)=4 ... you guess correctly, and lose 1/2 point if you guess incorrectly. ... P(Guess incorrectly)=3/4. and. E = (1/4)x(2) (3/4)x(-1/2) = 2/4-3/8 ... – PowerPoint PPT presentation

Number of Views:46
Avg rating:3.0/5.0
Slides: 27
Provided by: fredb67
Category:

less

Transcript and Presenter's Notes

Title: Section 12'4: Expected Value


1
Section 12.4 Expected Value
  • Dr. Fred Butler
  • Math 121 Fall 2004

2
Idea of Expected Value
  • Expected value (also called expectation) is often
    used to determine the expected results of an
    experiment or business venture over the long run.
  • It is used in business to predict future profits
    of a new product, in the insurance industry to
    determine how much each persons insurance rate
    is, and to predict the expected gain in games
    such as the lottery, roulette, craps, and slot
    machines.

3
An Example of Expected Value
  • Suppose I tell you I will give you 1 if you can
    roll an even number on a single die, and you have
    to give me 1 if you fail to roll an even number.
  • Who would win money in the long run if this game
    were played many times?

4
An Example of Expected Value contd.
  • Since there are 3 even numbers (2, 4, 6) out of a
    total of 6 possible number (1,2,3,4,5,6), we can
    expect that about half the time you will win and
    I will give you 1, and about half the time you
    will lose and have to give me 1.
  • Thus in the long run, we would probably both
    break even playing this game.

5
Computing Expected Value Mathematically
  • Mathematically we could find your expected gain
    or loss playing this game by the following
  • P(You win)x(Amount you win)
  • P(You lose)x(Amount you lost)
  • (1/2)x(1)(1/2)x(-1) 1/2(-1/2) 0.
  • Note that an amount of money that is lost is
    written as a negative number.
  • Since the expected value of this game is 0, we
    call it a fair game.

6
Formula for Expected Value
  • In general, the expected value E is calculated by
    multiplying the probability of each possible
    event occurring by the net amount gained or lost
    if the event occurs, and adding these values
    together.
  • If P1 is the probability that the first event
    occurs and A1 is the net amount won or lost if
    event 1 occurs, P2 is the probability that the
    second event occurs and A2 is the net amount won
    or lost if event 2 occurs, etc., then
  • E P1xA1 P2xA2 PnxAn.

7
Interpretation of Expected Value
  • An expected value of zero indicates that you can
    expect to break even in the long run.
  • A positive expected value indicates that you can
    expect to make money in the long run.
  • A negative expected value indicates that you can
    expect to lose money in the long run.

8
PRS Question 5.4
  • Suppose you roll a single die and I tell you I
    will pay you 4 if you roll a 1, and you have to
    pay me 1 if you dont roll a 1. Can you expect
    to make money at this game in the long run?
  • 1. Yes 2. No

9
Answer to PRS Question 5.4
  • P(Rolling 1)1/6 and P(Not rolling 1)1-1/65/6.
  • Then
  • E P(Rolling 1)x(Amount won)
  • P(Not rolling 1)x(Amount lost)
  • (1/6)x(4) (5/6)x(-1) (4-5)/6-1/6
  • -0.17.
  • So you can expect to lose around 17 cents at this
    game in the long run.

10
Example 1
  • Suppose you are taking a multiple choice exam in
    which each question has 5 possible answers.
  • You will receive 2 points for each correct
    answer, but you will lost 1/2 point for each
    incorrect answer.
  • Question If you dont know an answer, is it to
    your advantage to guess?

11
Example 1 contd.
  • If you completely guess on a question with 5
    choices, then
  • P(Guess correctly)1/5
  • P(Guess incorrectly)4/5.
  • Then
  • E P(Guess correctly)x(Points gained for
    correct answer)P(Guess incorrectly)x(Points lost
    for incorrect answer) (1/5)x(2)(4/5)x(-1/2)
    2/5 - 4/10 2/5 2/5 0.

12
PRS Question 5.5
  • Suppose you dont know the answer, but you can
    eliminate one of the choices as definitely not
    right. So there are 4 possible answers and you
    gain 2 points if you guess correctly, and lose
    1/2 point if you guess incorrectly.
  • Is it to your advantage to guess in this case?
  • 1. Yes 2. No

13
Answer to PRS Question 5.5
  • In this case
  • P(Guess correctly)1/4
  • P(Guess incorrectly)3/4
  • and
  • E (1/4)x(2)(3/4)x(-1/2) 2/4-3/8
  • 4/8-3/81/8.
  • In the long run you can expect to gain 1/8 point,
    so you should guess in this case.

14
Example 2
  • Suppose 1000 raffle tickets are sold for 1 each.
    There is one grand prize of 500, and two
    consolation prizes of 100 each. All of the
    tickets are placed in a bin and randomly selected
    for the prizes, and each ticket selected for a
    prize is returned to the bin before the next
    ticket is selected.
  • Question What is the expected value if we
    purchase one ticket?

15
Example 2 contd.
  • There are three amounts to be considered
  • 1. The net gain of winning the grand prize
  • 2. The net gain of winning a consolation prize
  • 3. The net loss of buying a ticket and winning
    nothing.
  • The net gain in winning the grand prize is
    500-1499, the net gain in winning a
    consolation prize is 100-199, and the net
    loss or buying a ticket and winning nothing is
    -1.

16
Example 2 contd.
  • The probability of winning the grand prize is
    1/1000, the probability of winning a consolation
    prize is 2/1000, and the probability of winning
    nothing is
  • 1-1/1000-2/1000997/1000.
  • Thus
  • E(1/1000)x(499)(2/1000)x(99)
  • (997/1000)x(-1)
  • (499198-997)/1000-300/1000-0.30.

17
Example 3
  • Question In the same raffle, what is our
    expected value if we buy five tickets?
  • Our expected value when purchase one ticket is
    -0.30.
  • Thus our expected value when purchasing five
    tickets is given by
  • E 5x(Expected value when purchasing one
    ticket) 5x(-0.30) -1.50.

18
Fair Price
  • The fair price for playing a game is the amount
    to be paid that will result in an expected value
    of 0 (thus making it a fair game).
  • Fair price can be found by the formula
  • Fair price Expected value Cost to play.

19
Fair Price Example
  • For the example with 1000 raffle tickets sold for
    1 each, with one grand prize of 500 and two
    consolation prizes of 100 each, we found that
    E-0.30.
  • Since the cost to play is 1, the formula tells
    us
  • Fair price Expected value Cost to play
    -0.30 1 0.70.

20
A Fair Price Example contd.
  • So if the price for a ticket in this raffle were
    0.70, the expected value of this game would be
    0.
  • We see directly that
  • E (1/1000)(500-0.70) (2/1000)(100-0.70)
    (997/1000)(-0.70)
  • (499.30198.60-697.90)/1000 0.
  • So paying 0.70 for a raffle ticket (instead of
    1) makes the expectation 0, and makes this
    raffle a fair game.

21
Example 4
  • Suppose it costs 5 to play a game where you spin
    the pointer, and you win the amount that the
    pointer lands on.
  • Question What is your expected value playing
    this game?
  • We need to remember to subtract the cost to play
    from any prize you win.

22
Example 4 contd.
23
Example 4 contd.
  • So you have a 1/2 chance of losing 4, a 1/4
    chance of losing 3, and a 1/4 chance of winning
    5.
  • Thus E (1/2)(-4)(1/4)(-3)(1/4)(5)
  • (-8-35)/4-6/4-1.50.
  • So in the long run you can expect to lose 1.50
    playing this game.

24
PRS Question 5.6
  • What is a fair price for the spinner game?
  • 1. 5 2. 3.50 3. 1.50

25
Lecture Summary
  • The expected value is computed by the formula
  • E P1xA1 P2xA2 PnxAn.
  • The fair price for playing a game is the amount
    to be paid that will result in an expected value
    of 0 .

26
Homework
  • Do problems from Section 12.4 of textbook.
  • Have a nice Thanksgiving break!
Write a Comment
User Comments (0)
About PowerShow.com