Motion - PowerPoint PPT Presentation

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Motion

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Select the formula you need to solve the problem ... The slope of a displacement ... Average velocity = the slope of a straight line joining 2 points on a ... – PowerPoint PPT presentation

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Title: Motion


1
Chapter 2 Motion
2
Problem Format
  • Example If you travel 30 km in 15 min, what is
    your speed?
  • List what is known and what you are looking for
  • Select the formula you need to solve the problem
  • 3. Show setup work
  • 4. Show answer (include magnitude and units) and
    circle or box in answer

d30 km t .25 hr v ?
vd/t
v30km/.25hr
120 km/hr
3
(No Transcript)
4
Percentage Error Percentage Error Absolute
Error x 100 Accepted value Absolute
Error Observed value accepted value
Experimental 9.92 Accepted 9.81
(9.92 9.81)/ 9.81 x 100
1
5
Rate anything compared to time
Rate Quantity time
Motionall motion is relative. (its compared to
something else)
6
Distance
  • A scalar quantity
  • How far moved or traveled
  • Linear amount covered

7
Displacement
  • a vector quantity
  • The magnitude and direction of a change in
    position
  • How far and in what direction traveled from
    starting point

B
A
Displacement x xf - xi
Can be positive or negative
8
Speed rate at which distance is covered
Speed distance time
Scalar Quantity
9
Velocity
  • rate at which displacement occurs
  • Speed in a given direction- if in a straight line

V x or v xf xi
t tf - ti
Vector Quantity
10
Velocity/ Graphing
  1. If the line on a displacement v. time graph is a
    straight line, this shows uniform velocity
  2. The slope of a displacement/time graph is
    velocity
  3. Average velocity total displacement/time
    interval
  4. Average velocity the slope of a straight line
    joining 2 points on a displacement/time graph
  5. Instantaneous Velocity the slope of a tangent
    to a displacement/time graph

Velocity v. Time Graphs
Distance (m)
Distance(m)
Time (sec)
Time (sec)
11
Acceleration change in velocity/ time a
v/ t a vf vi t Acceleration
can be positive negative (deceleration) Accerat
ion due to gravity 9.81 m/s2
12
  • Terminal Velocity
  • occurs when an object is falling through a
    material which provides resistance
  • The maximum speed reached
  • When the force of gravity force of resistance
  • There is no furture acceleration

13
  • g
  • acceleration due to gravity
  • Can be put in formula in place of a
  • -9.81 m/s2
  • Up down -
  • Free Fall
  • An object falling in a vacuum in the absences of
    air resistance. No terminal velocity

14
Graphs Velocity slope of displacement/time
graph Acceleration slope of a velocity/time
graph Displacement area beneath the slope of a
velocity/time graph
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