Title: Lecture 31 Biaxial Column
1Lecture 31 - Biaxial Column
- November 13, 2002
- CVEN 444
2Lecture Goals
- Short Column Biaxial Design
3Biaxial Column Example
The section of a short tied column is 16 x 24 in.
and is reinforced with 8 10 bars as shown.
Determine the allowable ultimate load on the
section f Pn if its acts at ex 8 in. and ey
12 in. Use fc 5 ksi and fy 60 ksi.
4Biaxial Column Example
Compute the P0 load, compression with no moments
5Biaxial Column Example
Compute Pnx, by starting with ey term and assume
that compression controls. Check by Compute
the nominal load, Pnx and assume second
compression steel does not contribute
assume small
6Biaxial Column Example
The components of the equilibrium equation
are Use similar triangles to find the
stress in the steel, fs
7Biaxial Column Example
Compute the moment about the tension
steel where The resulting equation is
8Biaxial Column Example
Combine the two equations and solve for Pn using
an iterative solution Set the two equation
equal to one another and sole for fs and the
definition
9Biaxial Column Example
Combine the two equations and solve for c using
an iterative technique You are solving a cubic
equation
10Biaxial Column Example
Check the assumption that Cs2 is close to zero
This value is small relative to the others
11Biaxial Column Example
This Cs2 11 kips relatively small verses the
overall load, which is So Pnx 733.0 kips
12Biaxial Column Example
Start with ex term and assume that compression
controls. Compute the nominal load, Pny and
assume second compression steel does not
contribute
assume small
13Biaxial Column Example
The components of the equilibrium equation are
14Biaxial Column Example
Compute the moment about the tension
steel where The resulting equation is
15Biaxial Column Example
Combine the two equations and solve for Pn using
an iterative solution Set the two equation
equal to one another and sole for fs and the
definition
16Biaxial Column Example
Combine the two equations and solve for c using
an iterative technique You are solving a cubic
equation
17Biaxial Column Example
Check the assumption that Cs2 is close to zero
This value is negative so it does not contribute
18Biaxial Column Example
This Cs2 - 2.1 kips relatively small verses the
overall load, which is So Pnx 684.6 kips
19Biaxial Column Example
Compute the nominal load
20Biaxial Column Example
Note the Pnx Pny include the corner steel bars
in both calculations a more conservative solution
would be to use 1/2 the steel in each direction
so As 2(1.27 in2) which would reduce Pu .
(Remember fs can not be greater than 60 ksi, so
that Pnx 620.3 k and Pny 578.4 k Pn 360.7
k and Pu 234.5 k )
21Homework due (11/25/02)