010'141 Engineering Mathematics II Lecture 7 Joint Probability Functions - PowerPoint PPT Presentation

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010'141 Engineering Mathematics II Lecture 7 Joint Probability Functions

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Their joint probability density function is. fY1,Y2(y1,y2) = fX1,X2(x1,x2) / J (x1,x2) ... for the joint probability density function. Example: the Rayleigh ... – PowerPoint PPT presentation

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Title: 010'141 Engineering Mathematics II Lecture 7 Joint Probability Functions


1
010.141 Engineering Mathematics IILecture
7Joint Probability Functions
  • Bob McKay
  • School of Computer Science and Engineering
  • College of Engineering
  • Seoul National University
  • Partly based on
  • Sheldon Ross A First Course in Probability

2
Outline
  • Pairwise Joint Distribution Functions
  • Example the Rayleigh Distribution

3
Joint Distribution Functions
  • It commonly arises that
  • We know the joint distribution of continuous
    random variables X1 and X2
  • We have two functionally dependent distributions
    Y1 g1(X1,X2) and Y2 g2(X1,X2)?
  • We would like to know the joint distribution of
    Y1 and Y2
  • Can we give a general formula for this joint
    distribution?
  • In fact, we require some extra constraints on Y1
    and Y2

4
Joint Distribution Functions
  • Under these conditions, Y1 and Y2 are jointly
    continuous
  • Their joint probability density function is
  • fY1,Y2(y1,y2) fX1,X2(x1,x2) / J (x1,x2)

5
Constraints onJoint Distribution Functions
  • The relationship between (X1,X2) and (Y1,Y2) must
    be an equivalence relation
  • That is, there exist h1and h2 such that ify1
    g1(x1,x2) and y2 g2(x1,x2) thenx1 h1(y1,y2)
    and x2 h2(y1,y2)
  • The Jacobean Determinant J (x1,x2) ?g1/?x1
    ?g1/?x2 ?g2/?x1 ?g2/?x2 is nonzero

6
Joint Distribution Functions Example
  • In mechanics, we often wish to switch from
    Cartesian to Polar coordinates
  • Suppose X and Y are normally distributed (with
    equal means and standard deviations) and
    independent
  • For example, we might be shooting arrows at a
    target, with our x and y errors being normally
    distributed, and independent of each other
  • We can use the transformation
  • r ? (x2 y2)?
  • ? tan-1(y/x)?
  • What is the joint distribution of the
    corresponding random variables R and ? under this
    transformation?

7
Joint Distribution Functions Example
  • The Jacobean is x / ?(x2y2) y / ?(x2y2)
    -y / (x2y2) x / (x2y2) 1 /
    ?(x2y2) 1 / r
  • The assumption of equal means gives the joint
    density function of X and Y asf(x,y) 1/2?
    e-(x2y2)/2
  • So the joint density function of R and ? isf(r,
    ?) 1/2? re-r2/2 0 lt ? lt 2?, 0 lt r lt ?
  • This is known as the Rayleigh Distribution
  • Note particularly the independence of ? (I.e.
    uniformly distributed)?

8
Summary
  • Pairwise Joint Distribution Functions
  • Conditions for a continuous pairwise joint
    distribution to exist
  • Formula for the joint probability density
    function
  • Example the Rayleigh Distribution
  • Transformation of (equal) normal distributions
    from Cartesian to Polar coordinates
  • The distribution of ? is uniform and independent
    of R

9
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