Title: ECE 1100 Introduction to Electrical and Computer Engineering
1ECE 6340 Intermediate EM Waves
Fall 2006
Prof. Donald R. Wilton ECE Dept.
Notes 26
Based on Notes by Prof. David R. Jackson
2Equivalence Principle
Basic idea We can replace the actual sources in
a region by equivalent sources at the boundary.
Keep original fields E , H outside S. Put zero
fields inside S.
3Equivalence Principle (cont.)
Ea E
Ha H
Note (Ea , Ha) and (Eb , Hb) both satisfy
Maxwells equations.
4Equivalence Principle (cont.)
The B.C.s on S are violated. Use equivalent
sources to make B.C.s valid.
5Equivalence Principle (cont.)
Hence
Equivalent sources
Outside S, these sources radiate the same fields
as the original antenna, and produce zero fields
inside S. This is justified by the uniqueness
theorem.
6Equivalence Principle (cont.)
Note If there are zero fields throughout a
region, it doesnt matter what material is placed
there (or removed).
7Scattering by a PEC
8Scattering by a PEC
9Example (cont.)
Conclusion The conductor can be removed.
10Example (cont.)
Integral equation for the unknown current
(E , H)
(0 ,0)
source
Electric Field Integral Equation (EFIE)
so
This integral equation has to be solved
numerically.
11Example Scattering by Dielectric Body
12Exterior Equivalence
Replace body by free space (since material
doesnt matter in zero-field region).
13Summary for Exterior
Original problem
Free-space problem
14Interior Equivalence
15Summary for Interior
Original problem
16Integral Equation
The means calculate the fields inside the
surface, assuming an infinite dielectric region.
Note The means calculate the fields outside
the surface, radiated by the sources in free
space.
Boundary conditions
Hence
PMCHWT Integral Equation
17Fields in a Half Space
Equivalent sources
18Fields in a Half Space (cont.)
Put PEC in zero-field region
The electric surface current on the PEC does not
radiate.
Hence, we have
19Fields in a Half Space (cont.)
Now use image theory
(E , H)
correct fields
incorrect fields
Note fields are not correct for z lt 0 (the image
method gives incorrect fields in this region).
20Fields in a Half Space Summary
21Fields in a Half Space (cont.)
Alternative (better when H is known)
Mse does not radiate on PMC, and is therefore not
included.
22Example Radiation from Waveguide
23Example (cont.)
Step 1
Step 2
24Example (cont.)
25Example (cont.)
Apply Duality
Solve this problem first
Then use