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Mathematical Investigation: Staircase Numbers

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To our knowledge, a staircase number is one that can be expressed as a sum of ... For larger staircases, finding the triangular number to subtract from the block ... – PowerPoint PPT presentation

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Title: Mathematical Investigation: Staircase Numbers


1
Mathematical InvestigationStaircase Numbers
  • By
  • Lisa Stephens
  • Megan Lombo

2
Initial Reaction
  • Negative attitude
  • - Limited understanding
  • - Lack of information given
  • Persistence
  • - Approached investigation as best we knew how,
    using an array of strategies
  • Basic outline of process
  • - Tried out formulas
  • - Tested formulas
  • - Made conjectures
  • - Tested conjectures

3
Our topic
  • A staircase number is the number of cubes needed
    to make a staircase that has at least two steps
    with each step (other than the first) being one
    cube high. Investigate.

Staircase number is 6
Staircase number is 9
4
But what is a staircase number?
  • To our knowledge, a staircase number is one that
    can be expressed as a sum of consecutive numbers.
    For example, 12 is a staircase number because
    34512. When staircases are drawn, it is clear
    to see that we must add consecutive numbers to
    find the staircase number.

See here, 1236
5
Our aim for the investigation- Use a combination
of the following strategies to explain what we
did and how we did it.
6
The Simultaneous Approach
  • The first formula that we came up with was
  • (l x h) 1
  • Where l no. of cubes in length of block
  • h no. of cubes in height of block

Testing conjectures
Analysing conjectures
7
Testing conjectures
4
1
5
2
4
2
2
1
3
6
5
3
3
1
(l x h) 1 (2 x 3) 1 6 1 5
(l x h) 1 (2 x 2) 1 4 1 3
(l x h) 1 (3 x 3) 1 9 1 8 6
Back
8
Analysing conjectures
  • But it doesnt work for more than two steps!
  • Maybe we need a new approach
  • How about we try a different formula for each
    number of steps!

9
Lisas Formula
  • Lisa devised the following formula
  • 2 steps (l x h) 1
  • 3 steps (l x h) 3
  • 4 steps (l x h) 6
  • Number deducted from block increases by 3.

Testing conjectures
Analysing conjectures
10
Testing Lisas Formula
7
10
1
4
8
11
6
2
4
9
5
2
3
7
12
3
5
6
1
3
6
10
13
8
4
1
3 steps (l x h) 3 (3 x 3) 3 9 3 6
14
9
5
2
4 steps (l x h) 6 (4 x 4) 6 16 6 10
4 steps (l x h) 6 (4 x 5) 6 20 6 14
However
11
However
  • Further testing of this formula indicated that,
    in fact, the numbers were not increasing by 3 at
    all!

1
5 steps (l x h) 9 (5 x 5) 9 25 9 16
15
Back to the drawing board!
6
2
10
7
3
13
11
8
4
14
15
12
9
5
12
Analysing Lisas Formula
  • Upon further evaluation of Lisas formula, we
    continued to find new formulas for each step
    staircases in an attempt to find a regular
    pattern in the number of cubes that needed to be
    extracted from the block to form the staircase
    number.
  • And then

13
HINT!
  • TRIANGULAR NUMBERS

14
Megans Formula
  • This can be shown by the formula
  • (l x h) (l 1)
  • Where (l 1) becomes the nth term of the
    triangular number sequence.
  • Number deducted from the block forms the
    triangular sequence with each increasing step.

Analysing conjectures
Testing conjectures
15
Testing Megans Formula
7
1
10
4
8
2
5
11
6
9
5
2
3
6
8
3
7
12
1
3
6
10
9
7
4
13
8
4
1
(l x h) (l 1) (3 x 4) (3 1) 12 2nd
triangular no. 12 3 9
14
9
5
2
(l x h) (l 1) (4 x 4) (4 1) 16 3rd
triangular no. 16 6 10
(l x h) (l 1) (4 x 5) (4 1) 20 3rd
triangular no. 20 6 14
Back
16
Analysing Megans Formula
  • For larger staircases, finding the triangular
    number to subtract from the block may become too
    difficult.
  • To overcome this problem, we needed to find a
    formula that would enable us to easily work out
    triangular numbers.

17
Sum of an arithmetic sequence
  • Triangular numbers when placed in sequence form
    an arithmetic progression.
  • Therefore, to find the sum of triangular numbers,
    we can use the formula
  • Sn n/2 (a l)
  • (l 1) in Megans formula is equivalent to the n
    in the above formula.
  • a is the first term in the series (1 in these
    cases), and l is the number of terms you are
    looking for.

18
Final testing- 2 step formula
Firstly, find triangular no.- Sn n/2 (a l)
5/2 (1 5 ) 2.5 (6) 15 Secondly,
substitute this into Megans formula- (l x h)
15 (6 x 6) 15 36 15 21
5 is found by using (l 1) in Megans formula,
as mentioned on the previous slide
1
2
7
3
8
12
4
9
13
16
Where (l x h) is equivalent to Sn.
5
10
14
17
19
6
11
21
20
18
15
19
More testing
Firstly, find triangular no.- Sn n/2 (a l)
3/2 (1 3) 1.5 (4) 6 Secondly,
substitute this into Megans formula- (l x h)
6 (4 x 5) 6 20 6 14
10
11
6
3
7
12
13
8
4
1
14
9
5
2
20
Conclusion
  • This is where we chose to end our investigation
    of staircase numbers.
  • If time permitted we would have further
    investigated other aspects, such as whether or
    not you can work out if any given number is a
    staircase number by using a set formula.

21
E-portfolio
  • This investigation PowerPoint presentation can
    be viewed in the Curriculum Knowledge section
    of both of our E-portfolios.
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