Title: Discrete Random Variables:
1- Discrete Random Variables
- The Binomial Distribution
2Bernoullis trials
- J. Bernoulli (1654-1705) analyzed the idea of
repeated independent trials for discrete random
variables that had two possible outcomes success
or failure - In his notation he wrote that the probability of
success is denoted by p and the probability of
failure is denoted by q or 1-p
3Binomial distribution
- The binomial distribution is just n independent
individual (Bernoulli) trials added up. - It is the number of successes in n trials.
- The sum of the probabilities of all the
independent trials totals 1. - We can define a success as a 1, and a failure
as a 0.
4Binomial distribution
- x is a binomial distribution if its probability
function is - Examples (note success/failure could be
switched!)
probability of success
probability of failure
Situation x1 (success) x0 (failure)
Coin toss to get heads Turns up heads Turns up tails
Rolling dice to get 1 Lands on 1 Lands on anything but 1
While testing a product, how many are found defective Product is defective Product is not defective
5Binomial distribution
- The binomial distribution is just n independent
Bernoulli trials added up
- It requires that the trials be done with
replacement ex. testing bulbs for defects
- Lets say you make many light bulbs
- Pick one at random, test for defect, put it back
- Repeat several times
- If there are many light bulbs, you do not have to
replace (it wont make a significant difference) - The result will be the binomial probability of a
defective bulb (defective total sample).
6Binomial distribution - formula
- Lets figure out a binomial random variables
probability function or formula - Suppose we are looking at a binomial with n3
(ex. 3 coin flips heads is a success) - We will start with all tails P(x0)
- Can happen only one way 000
- Which is (1-p)(1-p)(1-p)
- Simplified (1-p)3
7Binomial distribution - formula
- Lets figure out a binomial probability function
(for n 3) - This time we want 1 success plus 2 failures (ex.
1 heads 2 tails, or P(x1)) - This can happen three ways 100, 010, 001
- Which is p(1-p)(1-p)(1-p)p(1-p)(1-p)(1-p)p
- Simplified 3p(1-p)2
8Binomial distribution - formula
- Lets figure out a binomial probability function
(for n 3) - We want 2 successes P(x2)
- Can happen three ways 110, 011, 101, or
- pp(1-p)(1-p)ppp(1-p)p, which simplifies to..
- 3p2(1-p)
9Binomial distribution - formula
- Lets figure out a binomial probability function
(n 3) - We want all 3 successes P(x3)
- This can happen only one way 111
- Which we represent as ppp
- Which simplifies to p3
10Binomial distribution - formula
- Lets figure out a binomial probability function
in summary, for n 3, we have - P(x)
- (Where x is the number of successes ex. of
heads)
The sum of these expressions is the binomial
distribution for n3. The resulting equation is
an example of the Binomial Theorem.
11Binomial distribution - formula
- A quick review of the Binomial Theorem
- If we use q for (1 p), then
- which is an example of the formula
- (a b)n ____________________
- (if you forget it, check it in your text)
12Binomial distribution - formula
- Lets figure out a binomial r.v.s probability
function (the quick way to compute the sum of the
terms on the previous slide) - now heres the
formula - In general, for a binomial
(the of x successes with probability p in n
trials)
13Binomial distribution - formula
or P(x) nCx px(1 p)n-x
- This formula is often called the general
term of the binomial distribution.
14Expected Value
- The expected value of a binomial distribu-tion
equals the probability of success (p) for n
trials
- E(X) also equals the sum of the probabilities in
the binomial distribution.
15Binomial distribution - Graph
- Typical shape of a binomial distribution
- Symmetric, with total P(x) 1
Note this is a theoretical graph how would an
experimental one be different?
P
x
16Binomial distribution - example
- A realtor claims that he closes the deal on a
house sale 40 of the time. - This month, he closed 1 out of 10 deals.
- How likely is his claim of 40 if he only
completed 1/10 of his deals this month?
17Binomial distribution - example
- By using the binomial distribution function, its
possible to check if his assessment of his
abilities (i.e. 40 closes) is likely
P(0 deals)
18Binomial distribution - example
- So it seems pretty unlikely that his assess-ment
of his abilities is right - The probability of closing 1 or fewer deals out
of 10 if (as he claims) he closes deals 40 of
the time is less than 5 or less than 1/20. - What of closes do you think would have the
highest probability in this distribution, if his
claim was right?
19Binomial distribution - example
- Now see if you can determine the expected number
of closings if he had 12 deals this month,
assuming 40 success.
- We need the values of n ( ___) and of p (
____).
- E(X) np ______ - this means that we would
expect him to close about _____ deals, if his
claim is correct. End of first example.
20Binomial Distribution ex. 2
- Alex Rios has a batting average of 0.310 for the
season. In last nights game, he had 4 at bats.
What are the chances he had 2 hits? - You try this one! First ask 3 questions
21Binomial Distribution ex. 2
- Is getting a hit a discrete random variable?
- Is this a Bernoulli trial? How would you
- define a success and a failure?
- Is each time at bat an independent event?
- If you can answer yes to the three questions
above, then you can use the binomial distribution
formula to answer the problem.
22Binomial Distribution ex. 2
- First determine the following values
- The number of trials (Alex is at bat __ times)
this is the value of n - The probability of success (Alexs average is
___) this is p - The probability of failure 1 p ___
- The of successes asked for (his chances of
getting ___ hits) this is x
- Now you can use the formula
23Binomial Distribution ex. 2
- Put in the values from the previous screen, and
discuss your answers. pause here
- Did you get P(2) 0.275?
- Is 2 the most likely number of hits for Alex
last night? How about 1 or 3?
- P(0 or 1 or 2 or 3 or 4 hits) _____?
24Hypergeometric distribution
- What happens if you have a situation in which the
trials are not independent (this most often
happens due to not replacing a selected item). - Each trial must result in success or failure, but
the probability of success changes with each
trial.
25Hypergeometric distribution
- Consider taking a sample from a population, and
testing each member of the sample for defects. - Do this sampling without replacement.
- As long as the sample is small compared to the
population, this is close to binomial. - But if the sample is large compared to the
population, this is a hypergeometric dist.
26Hypergeometric dist. - formula
- A hypergeometric distribution differs from
binomial ones since it has dependent trials. - Probability of x successes in r dependent trials,
with number of successes a out of a total of n
possible outcomes
27Hypergeometric dist. - formula
- The full version of this formula is
- Expected Value the average probability of a
success is the ratio of success overall (a/n)
times r trials