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Substrate analogues: checking the role of functional groups

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Identification of intermediates in the reaction path: ... Loss of the S (thioester) does not affect binding (and radical formation and catalysis) ... – PowerPoint PPT presentation

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Title: Substrate analogues: checking the role of functional groups


1
  • Substrate analogues checking the role of
    functional groups
  • Identification of intermediates in the reaction
    path
  • Wrong substrates undergo unexpected side
    reactions
  • Inhibitors form stable intermediates or stable
    covalent side products
  • Stereochemistry of the substrate and product
    discern possible paths
  • Trapping of intermediates direct visualization

2
  • Substrate analogues

H
3
  • Substrate analogues

Loss of the S (thioester) does not affect binding
(and radical formation and catalysis), but loss
of the carbonyl group does.
4
  • Substrate analogues

Loss of the S (thioester) does not affect binding
(and radical formation and catalysis), but loss
of the carbonyl group does. The carbonyl group
binds tightly and provides the energy.
5
  • Wrong substrates bromopyruvate with
    transaminase

Inhibition by covalent modification
1.
2.
non-enzymatic
6
  • Wrong substrates bromopyruvate with
    transaminase

wrong reaction that explains the product
pyruvate
make quinone
stabilize tetrahedral intermediate
unexpected reaction
7
  • Inhibitors Kinetic analysis shows, that another
    observed pathway (to the covalently inhibited
    enzyme) must have the same intermediate

The base can react with the common intermediate,
an enamine.
8
  • Stereochemistry of the substrate and product

9
  • Stereochemistry of the substrate and product

10
  • Stereochemistry of the substrate and product

L-haloacid dehalogenase direct attack by H2O or
via a covalent intermediate?
11
  • Trapping of intermediates

L-haloacid dehalogenase has a pH optimum of 9.5.
At pH 5 the reaction is trapped at an
intermediate. This stable intermediate can be
characterized in a crystal structure.
12
  • Trapping of intermediates

13
  • Trapping of intermediates
  • Why is the intermediate trapped at pH 5?
  • In the structure at pH 5, no water molecule is
    close to Asp 8 and available for hydrolysis.
  • At pH 9.5 (the pH optimum) a structural change
    must occur and a water molecule enters the active
    site. Moreover, at higher pH, water is more
    likely to deprotonate and then more nucleophilic.
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