Title: Chapter 4 Chemical Reactions
1Chapter 4Chemical Reactions
- Online Homework
- Assignment 2 (Ch 34)
- Note This is the longest of the homework
assignments you must start early. Due Thurs,
July 6.
2I. Solubility
- - Many Ionic compounds will dissolve in water and
produce ions These are soluble and are called
electrolytes because they conduct electricity. - - Driving force is that water will be attracted
to the ions, form weak bonds, and release energy. - 1) Nonelectrolyte dissolves but does not
produce ions such as methanol CH3OH or acetone. - 2) Strong Electrolyte (100 ionization)
- NH4Cl(s) -----) NH4(aq) Cl-(aq)
(Conducts Well) - 3) Weak Electrolyte (few ionization in water)
- NH3 H2O (-----) NH4 OH- ( 1
ionized) - HC2H3O2 --------) H C2H3O2- (1
ionized)
3Svante Arrhenius
Nonelectrolyte No Current
Electrolyte Much Current
4I. Solubility Continued
- - Some ionic compounds will not dissolve in water
- insoluble. - - Know solubility rules in text (pg 128) below
- 1) All group IA ammonium acetate nitrate
compounds are soluble No exceptions. - 2) Halides are soluble except Ag Pb2
Hg22 - 3) Sulfates are soluble except for Ca2
Ba2 - Sr2 Ag Pb2 Hg2 2
-
- 4) Hydroxides are insoluble except for rule 1
Ca2 Sr 2 Ba 2 - 5) Most carbonates, phosphates, and sulfides
are insoluble except for rule 1
5II. Writing Reactions
- - Ways to write reactions Example
- Silver(I)nitrate sodium chloride -----)
silver(I)chloride sodium nitrate - 1) Molecular Equation (ME) Write all as
molecules -
- AgNO3 NaCl -----) AgCl(s) NaNO3
- 2) Complete Ionic Equation (CIE) Write soluble
- ionic compounds as ions show all ions
charges. - Ag NO3- Na Cl- ----) AgCl(s) Na
NO3- - 3) Net Ionic Equation (NIE) Eliminate Spectator
Ions -
- Ag Cl- -----) AgCl(s)
6III. Reaction Types A. Precipitation Reactions
- - If reaction produces new insoluble product,
then can be classified as a precipitation
reaction. - - Can predict a product from the solubility
rules. - Method Write soluble ionic reactants as ions.
Check to see if insoluble product can form. If
can, then this is a product a driving force for
the reaction. - Example Predict product when mix K2SO4
- BaCl2 and write CIE and NIE
- 2K SO42- Ba2 2Cl- -----) BaSO4(s) 2K
2Cl- - Ba2 SO42- -----) BaSO4(s) (NIE)
7III. Reaction Types B. Acid-Base Rxns
- 1. Definitions
- Arrhenius Acid substance which releases H in
water. - Base substance which releases OH- in
water. - Examples HCl -----) H Cl-
- NaOH -----) Na OH-
- Bronsted-Lowry Acid Proton Donor
- Base Proton Acceptor
- Example NH3 HCl -----) NH4 Cl-
8III. Reaction Types B. Acid-Base Rxns
- 2. Properties
- Acids Sour taste
- Turn Indicator dyes a specific color
- (Phenolphthalein colorless Litmus red)
- React with bases to yield salt H2O
- Bases Bitter Taste, Feel Slippery
- Turn Indicator dyes a specific color
- (Phenolphthalein red Litmus blue)
- React with acids to yield salt H2O
- Strong Acids/Bases ionize 100 in water
- Weak Acids/Bases ionize lt lt 100 in water
9III. Reaction Types B. Acid-Base Rxns
- 3. Examples
- Strong Acids Bases HCl HBr HI HNO3
H2SO4 - NaOH KOH Ba(OH)2
- HCl -----) H Cl- 100 to the right
- Weak Acids Bases HF HC2H3O2 HCN
- NH3 (NH4OH) NaHCO3
- NH3 H2O (-----) NH4 OH- 1 to the
right - HC2H3O2 (-----) H C2H3O2- 1 to the
right
10III. Reaction Types B. Acid-Base Rxns
- 4. Acid-Base or Neutralization Reactions
- - Most Acids react with bases to give a salt
H2O - - Driving force is to produce very stable H2O and
sometimes a gas. -
- - Examples NaOH HF -----) NaF H2O
- 2KOH H2SO4 ---) K2SO4 2H2O
- - Some Neutralization Rxns produce a gas
(memorize) - 2H CO32- or H HCO3- -----) CO2 H2O
(H2CO3) - 2H SO32- -----) SO2 H2O (H2SO3)
- 2H S2- -----) H2S
- H CN- -----) HCN Gases are
in green - NH4 OH- -----) NH3 H2O
11III. Reaction Types B. Acid-Base Rxns
- 5. ME, CEI and NIE for reaction of potassium
hydroxide with hydrochloric acid - ME KOH HCl -----) KCl H2O
- CIE K OH- H Cl- -----) K
Cl- H2O - NIE H OH- -----) H2O
- Note 1) The above net ionic equation is common
for most acid-base reactions. The production of
stable H2O is a driving force for the reaction. - 2) H in water better represented by H3O
(hydronium ion) Memorize this name.
12III. Reaction Types B. Acid-Base Rxns
- 5. ME, CEI and NIE
- - Write the ME, CIE NIE for Rxn of HCl NaHCO3
- ME HCl NaHCO3 -----) NaCl H2O CO2
- CIE H Cl- Na HCO3- ---) Na Cl-
H2O CO2 - NIE H HCO3- -----) H2O CO2
- 6. Titration - Process of adding known amount of
known concentration of Base (or Acid) in a
burette to an unknown concentration of Acid (or
Base). End point is determined with an indicator
or a pH meter. Can determine the concentration
of the unknown (quantitative analysis).
13III. Reaction Types B. Acid-Base Rxns
14III. Reaction Types C. Predicting products
- Driving forces in reactions - production of
- 1) precipitate, 2) gas, 3) a stable molecule.
- Predicting products write ionic reactants as
ions and look to see if a precipitate can form
(solubility rules), a gas can form (6 gas
equations), or if a stable molecule like H2O H
OH- ---) H2O form. Then write NIE balance. - Examples 1) BaI2 AgNO3 2) NaCN HCl
- 1) Ba2 I- Ag NO3- -----) AgI(s) Ba2
NO3- - Ag I- -----) AgI(s) (NIE)
- 2) Na CN- H Cl- -----) HCN(g) Na
Cl- - H CN- -----) HCN(g) (NIE)
15III. Reaction Types D. Redox Rxns
- 1. Definitions Introduction
- - Oxidation Reduction Reaction (Redox Rxn) is
one in which electrons are transferred. - - Oxidation Loss of Electrons
- - Reduction Gain of Electrons
- 2. Examples
- 2Mg O2 -----) 2MgO
- 2Mg ---) 2Mg2 4e- Oxidation Half
Rxn - O2 4e- -----) 2O2- Reduction
Half Rxn - 2Na 2H2O -----) 2NaOH H2
- 2Na -----) 2Na 2e- Oxidation Half
Rxn - 2H 2e- -----) H2 Reduction
Half Rxn
16III. Reaction Types D. Redox Rxns
- Note Oxidizing agent causes oxidation
- Reducing agent causes reduction
- 3. Uses of Redox Rxns a) Create new chemicals
- b) Theoretical Importance (chem 123)
- c) Batteries - force transferred electrons
through a wire and use them to do work - 4. Identification (Oxidation Numbers - ON)
- Definition ON the charge that an atom or
group of atoms would have if they were ionic. - Uses 1) If a substance changes ON in a rxn,
then the rxn is redox 2) Nomenclature
Variable charged metals example FeI2
Iron(II)Iodide - Rules Use following rules Order gives
priority
17III. Reaction Types D. Redox Rxns
- 5. Rules for Determining ON (Different from pg
147) - Note When there is a conflict, the first
rule - takes priority.
- a) The sum of the ON must add up to give the
charge - b) The ON of a neutral element by itself is 0
- c) Group I, II, III ions are 1, 2 3
respectively - (H -1 when combined with active metal)
- d) F is -1
- e) O is -2 (O is -1 when found as a
peroxide, O22-) - f) Cl, Br, I are -1 (When 2 together, most
electronegative -1)
18III. Reaction Types D. Redox Rxns
- Examples Determine the ON of single N in each
- N2 Na3N NF3 NO3-1 N2O NO
NO21- - 0 -3 3 5 1 2
3 - - Which of the above forms of N can explosively
react with organics? Why? - - Determine ON of each atom in FeSO3
- 2 4 -2
- - Which of the following are redox
- 1) Mg Cl2 -----) MgCl2
- 2) CH4 2 O2 -----) CO2 2 H2O
- 3) HCl NaOH -----) H2O NaCl
19III. Reaction Types D. Redox Rxns
- 6. Reaction Types
- Combination 2Al 3F2 -----) 2AlF3
- Decomposition 2HgO -----) 2Hg O2
- Combustion CH4 2O2 -----) CO2 2H2O
- Displacement Mg 2HCl -----) MgCl2 H2
- Can predict reaction from table 4.6, Pg 151
- The more active metal will replace the cation
- 7. Balancing Can become difficult so, rules
were generated. Will cover in Chem 123, Chapter
20.
20IV. Quantitative Aspects of Solutions
- A. Molarity, M
- - Many reactions take place in solution we
need - a way to measure concentration M is one way.
-
- - M moles of Solute/L Solution m/L
- solvent substance present in largest amount
solute substance(s) dissolved in
solvent solution solute solvent - B. Molarity Calculations
- 1) Calculate the M if 4.5 moles of HCl are
dissolved in a total volume of 0.50 L - M m/L 4.5 moles / 0.50 L 9.0 m/L HCl
9.0 M HCl 9.0 molar HCl
21IV. Quantitative Aspects of Solutions
- 2) Calculate M if 20. g of CaCO3 are dissolved in
4.0 L - 20. g CaCO3 x 1 mole CaCO3/100. g CaCO3
0.20 mol CaCO3 - M moles/L 0.20 moles / 4.0 L 0.050 M
CaCO3 - 3) How many moles of HCl are present in 2.0 L of
0.30 M HCl? - M moles/L moles M x L (0.30 m/L) x
(2.0L) 0.60 moles - 4) How many L of 12 M HCl are needed to get 1.0
moles of HCl? - M m/L L m/M 1.0 moles HCl / (12 mole/L)
0.083 L
22IV. Quant. Aspects of Solutions C. Dilution
Problems
- - Frequently we are given a concentrated solution
and we need to dilute it with water to get a more
dilute solution dilution problem. - Mi x Vi Mf x Vf Note Initial moles Final
moles - Ci x Vi Cf x Vf
- Example How many mL of 12 M HCl are needed to
make 100. mL of 3.0 M? - Vi Mf x Vf / Mi (3.0 M x 100.mL)/12 M 25
mL - Take 25 mL of 12 M HCl and add enough water to
make 100 mL.
23IV. Quantitative Aspects of Solutions
- D. Gravimetric Analysis
- - A type of analysis where one converts the
analyte to an insoluble compound which is then
purified, dried weighed. - Example 0.10 L of water containing Ag is mixed
with NaCl. 0.260 g of dry insoluble AgCl is
collected on a filter. Calculate the g of Ag
present in the water. -
- NIE 1 Ag 1 Cl- -----) 1 AgCl(s)
- 0.260 g AgCl x 1 mole AgCl x 1 mole Ag
x 108 g Ag - 143 g AgCl 1 mole AgCl 1 mole
Ag -
- 0.196 g Ag
24IV. Quantitative Aspects of Solutions
- E. Volumetric Analysis
- - An analysis technique where the M and volume of
a reagent is used to calculate the amount of an
unknown. - Example 0.0250 L of HCl is titrated with 0.0455
L of 0.433 - M NaOH. Calculate the M of the HCl
- M moles HCl / 0.0250 L
- 1 HCl 1 NaOH -----) 1 NaCl 1 H2O
- (0.433 m/L NaOH) x 0.0455 L 0.0197 m NaOH
----) 0.0197 m HCl - M 0.0197 m HCl / 0.0250 L 0.788 M
HCl
25V. Suggested Homework 165 - 174
- 1-10 23 25 27 33 37 45
- 49 51 53 55 61 73 (odd)
- 73 79 83 87 99 115
- Online Homework - Assignment 2
- Note This is the longest assignment start
early. Due Thurs, July 6.