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NETWORKS 2: 090920201

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applying our Net 1 knowledge about KVL in this loop we find: Vmax cos t = L(di/dt) Ri ... all that work in Net 1 will really begin to pay off. Phasor diagrams ... – PowerPoint PPT presentation

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Title: NETWORKS 2: 090920201


1
CHAPTER 10
  • NETWORKS 2 0909202-01
  • 1 November 2005 Lecture 2
  • ROWAN UNIVERSITY
  • College of Engineering
  • Dr Peter Mark Jansson, PP PE
  • DEPARTMENT OF ELECTRICAL COMPUTER ENGINEERING
  • Autumn Semester 2005 Quarter Two

2
Review Chapter 10 key concepts
  • Todays learning objectives
  • terminology for sinusoidal sources
  • Phase angles in progress
  • analyzing sinusoidal sources
  • steady-state response of an RL circuit to a
    sinusoidal forcing function
  • complex exponential forcing function
  • the phasor concept

3
Figure 10.3-4 Triangle for A and B -
Trigonometry is helpful here
sin ? B/C, cos ? A/C, tan ? sin/cos B/A
4
Phase angle (?)
  • if a current and voltage waveform are out of
    phase with each other this difference is referred
    to as a phase angle (leading or lagging).
  • It (?) can be expressed as a difference in
    degrees or radians
  • It can also be observed in the functions that
    represent these waveforms as a time difference

5
Circuit response to a forcing function
  • If we have a circuit which experiences a forcing
    function of vs V0cos?t
  • it will experience a forced response of the
    form
  • vf A cos ? t B sin ? t
  • this is equivalent to

6
Figure 10.3-5 The AB triangle
v(t) A cos?t B sin?t
7
LC 1
  • From the previous example, Find the current
    restated in the second form if it is equal to the
    value below in the first form?

8
Sinusoidal Sources
  • T period of oscillation
  • f 1/T (frequency)
  • Units of Hertz
  • Cycles per second
  • ? 2?f 2?/T
  • Angular frequency
  • Radians per second
  • ? phase angle
  • Offset from zero
  • May be degrees or rads

9
representing signals by equations
  • typical problem encountered by ECEs
  • solution is straightforward
  • 1. measure the amplitude (A)
  • 2. determine the period (T), calculate frequency
    ? 2?f
  • 3. Pick a time (t) and measure v (or i), observe
    ascending or descending and finally, calculate
    phase angle ?

When v(t) is ascending at time t1
When v(t) is descending at time t1
10
sample problem analytic representation of
sinusoidal voltage waveforms v1(t) and v2(t) of
the form v(t)Acos(?t?)
2A30V, T0.2 sec Determine Vm and ?
11
continuing sample problem
  • 2A 30V, A Vmax 15V
  • ? 2?/T 2?/0.2 10?
  • At circled point v1(t) is going up (ascending
    with time) and values are
  • v1(t) 10.6066V
  • t 0.15 sec
  • So

12
continuing sample problem
If you calculated this on your calculator you
should find that ?-5.4977873 radians is the
answer. This equates to how many degrees? -315o
45o
Write the final analytic equation for v1(t) in
this form as LC2
13
do the same for v2(t)
At circled point v2(t) is going down (descending
with time) and values are v2(t) 10.6066V t
0.15 sec
Write the final analytic equation for v2(t) in
this form as LC3
14
some practice problems
  • a voltage is v6cos(4t30o)
  • (a) find the period of oscillation
  • (b) find phase relation to associated current i
    8cos(4t-70o)
  • (a) T2?/? since ?4 T2?/4 ?/2
  • (b) write answer as LC4

15
more practice
  • a voltage is v3cos4t4sin4t
  • (a) find the voltage in the form below
  • REMEMBER

?tan-1(B/A) when Agt0 and ?180o tan-1(B/A) when
Alt0 Write your answer as LC5
16
steady-state response of circuit to sinusoidal
forcing function
When vs(t) Vm cos ?t, the complete response
looks like this i(t) Ke-t/? Imax cos (?t ?)
17
Over time the transient term dies out
  • the steady-state response that is left is
    i(t) Imax cos (?t ?)
  • applying our Net 1 knowledge about KVL in this
    loop we find
  • Vmax cos ?t L(di/dt) Ri
  • substituting i(t) above into this we find after
    many calculations

18
Example
If vs(t)10 cos 3t V and L1H, R4? what is
i(t)? Provide your answer as LC6
19
Net II and complex math
  • net I relied heavily on Algebra, some trig and
    1st order differential equations
  • net II requires complex math as well as 1st and
    2nd order differential equations
  • lets review some..

20
Complex numbers
21
Complex numbers
22
Rectangular, Exponential and Polar Notation
  • In the Complex Plane where x is the real part of
    the complex number and y is imaginary part of the
    complex number we can express the complex number
    c in three distinct ways
  • Rectangular c a jb
  • Exponential c rej?
  • Polar c r??

23
Lets express c in all forms
  • If c 4 j3
  • What is it in exponential form?
  • What is r?
  • r (a2 b2)1/2
  • r (42 32)1/2 (16 9)1/2 5
  • What is ??
  • ? tan-1(b/a) when agt0
  • ? tan-1(3/4) 36.9o
  • Write c rej? as LC7
  • Write c in polar form as LC8

24
Operations with complex numbers
  • on board
  • REMEMBER
  • Easiest to subtract and add complex numbers in
    rectangular form
  • Easiest to multiply and divide in polar form

25
practice notation examples
Find a and b if Provide your answer as
LC9 Find A and ? if Provide your answer as
LC10
26
How can we apply this?
  • to make solutions of net II problems easier
  • Well, first a bit of tougher learning then a
    greater simplification that will make our lives
    enormously easier.

27
Complex exponential forcing function
  • the process
  • 1. write the excitation (the forcing function) as
    a cosine waveform with a phase angle
  • 2. introduce complex excitation (Eulers
    identity)
  • e j? cos ? j sin ? (where ? ?t ?)
  • 3. use the complex excitation and circuit
    differential equation along with assumed response
  • 4. determine the constant A Be-j? so that
    desired response is achieved
  • xe Ae j(?t ?) Be j(?t ? - ?)

28
steady-state response of circuit to complex
exponential forcing function
An EXAMPLE assume R 2?, L 1H, and vs 10
sin 3t V
step 1) write source as cosine waveform with
phase angle sovs 10 sin 3t V 10 cos
(3t90o), step 2) introduce complex excitation,
so ve 10 e j(3t-90o)
29
continuing our solution
  • step 3) introduce complex excitation into
    circuits diff. equation
  • ve L(die/dt) Rie
  • obtaining
  • 10 e j(3t-90o) die/dt 2Rie
  • assuming our response is of the form ie Ae
    j(3t-90o)
  • step 4) substitute, take the derivative and find
    the constant
  • j3Ae j(3t-90o) 2Ae j(3t-90o) 10 e j(3t-90o)

30
hw problem 10.5-6
  • Find the steady state response if vs(t) cos 2t
    V

0.1F
5?
31
Steinmetz observed this process
  • and it led to the phasor concept
  • the phasor concept may be used when the circuit
    is linear, the steady-state response is sought
    and all independent sources are sinusoids of the
    same frequency
  • a transform is a change in the mathematical
    description of a physical variable to facilitate
    computation
  • a phasor is a transformed version of a sinusoidal
    voltage or current waveform and consists of the
    magnitude and phase angle information of the
    sinusoid

32
remember
33
Transforming from the Time Domain ?
to the Frequency Domain
  • Write time domain function, y(t) as a cosine
    waveform with phase angle
  • Express cosine waveform as complex quantity using
    Eulers identity
  • Drop the real part notation
  • Suppress the ej?t while noting ? for future use

34
example
  • i 5 sin(100t120o)
  • Lets convert to the frequency domain
  • I Im??

Provide your answer as LC3
35
LC 4
  • i 4 cos(20t - 80o)
  • Lets convert to the frequency domain
  • I Im??

36
Transforming from the Frequency Domain ?
to the Time Domain
  • Write the phasor in exponential form
  • Reinsert the factor ej?t
  • Reinsert the real part operator Re
  • Use Eulers identity to obtain the time function

37
example
  • V 24?125o
  • Lets convert to the time domain
  • v(t) Vm cos(?t ?)

38
LC 5
  • V 10?-140o
  • Lets convert to the frequency domain
  • I Im??

39
Why use Phasors?
  • The phasor method uses the transformation from
    the time domain to the frequency domain to more
    easily obtain the sinusoidal steady-state
    solution of the differential equation

RC circuit example
RL circuit example
40
RL example solution on board
vs(t) Vm cos 100t V , R 200?, L 2H
41
RC example solution below
i(t) 10 cos 100t A, R1?, C 0.01F
42
hw problem 10.6-1
  • v(t) 15 cos 4t V, R6?, L2H
  • find v(t) for inductor, steady-state

v(t) -
43
Phasor representation
  • transformation from time domain to the frequency
    domain
  • converts solution of a differential equation to
    an algebraic one
  • we must now learn the phasor relations on R,L
    C elements

44
Resistors
  • V RI
  • if V 10?0o, (v10 cos 30 t) and R 5
  • what does I ?
  • I V/R v/R2 cos 30 t

45
R time domain vs. frequency domain
46
LC 6
  • current in a resistor is
  • i 2 cos 100t A
  • Find the steady-state voltage across the resistor
    if its resistance is 10?

47
Inductors
  • V j?LI
  • In a purely inductive circuit the voltage leads
    the current by exactly 90o (or current lags by
    90o)
  • if V 10?50o, and L2,?100 rads/s
  • what does I ?
  • I V/ j?L V/ j200 10?50o/200?90o
  • I 0.05 ?-40o

48
L time domain vs. frequency domain
49
LC 7
  • current in an inductor is
  • i 2 cos 100t A
  • Find the steady-state voltage across the inductor
    if its inductance is 10 mH

REMEMBER voltage leads the current by exactly
90o
50
Capacitors
  • V (1/j?C)I
  • In a purely capacitive circuit the current leads
    the voltage by exactly 90o (or voltage lags by
    90o)
  • if V 10?50o, and L2,?100 rads/s
  • what does I ?
  • I V/ j?L V/ j200 10?50o/200?90o
  • I 0.05 ?-40o

51
C time domain vs. frequency domain
52
LC 8
  • current in a capacitor is
  • i 2 cos 100t A
  • Find the steady-state voltage across the
    capacitor if its capacitance is 1 mF

REMEMBER current leads the voltage by exactly
90o
53
Why use Phasors?
  • Lets compare algebra to diff-eqs
  • Example 10.7-1

54
Table 10.7-1 Time Domain and Frequency Domain
Relationships.
55
Impedance (Z) and Reactance (X)
Z V/I
56
Impedance (Z) and Reactance (X)
  • Z (impedance) of an element is the ratio of the
    phasor voltage V to the phasor current I

57
KCL/KVL in the time frequency domains
58
Current and voltage division
  • current divider and voltage divider rules hold
    for phasor currents and voltages
  • we substitute Impedance (Z) for Resistance (R)
    in the frequency domain

59
Node voltage, mesh current, supernodes, Thevenin
and Norton all work in the frequency domain
  • all that work in Net 1 will really begin to pay
    off

60
Phasor diagrams
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