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12'4 Probability of Compound Events

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To find P(A or B) you must consider what outcomes, if any, are in the intersection of A and B. ... Fourteen out of 15 students took French or math. ... – PowerPoint PPT presentation

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Title: 12'4 Probability of Compound Events


1
12.4 Probability of Compound Events
  • P. 724

2
Mutually Exclusive Events
3
Intersection of A B
4
  • To find P(A or B) you must consider what
    outcomes, if any, are in the intersection of A
    and B.
  • If there are none, then A and B are mutually
    exclusive events and P(A or B) P(A)P(B)
  • If A and B are not mutually exclusive, then the
    outcomes in the intersection or A B are counted
    twice when P(A) P(B) are added.
  • So P(A B) must be subtracted once from the sum

5
EXAMPLE 1
  • One six-sided die is rolled.
  • What is the probability of rolling a multiple of
    3 or 5?
  • P(A or B) P(A) P(B) 2/6 1/6 1/2
  • 0.5

6
EXAMPLE 2
  • One six-sided die is rolled. What is the
    probability of rolling a multiple of 3 or a
    multiple of 2?
  • A Mult 3 2 outcomes
  • B mult 2 3 outcomes
  • P(A or B) P(A) P(B) P(AB)
  • P(A or B) 2/6 3/6 1/6
  • 2/3 0.67

7
EXAMPLE 3
  • In a poll of high school juniors, 6 out of 15
    took a French class and 11 out of 15 took a math
    class.
  • Fourteen out of 15 students took French or math.
  • What is the probability that a student took both
    French and math?

8
  • A French
  • B Math
  • P(A) 6/15, P(B) 11/15, P(AorB) 14/15
  • P(A or B) P(A) P(B) P(AB)
  • 14/15 6/15 11/15 P(A B)
  • P(A B) 6/15 11/15 14/15
  • P(A B) 3/15 1/5 .20

9
Using complements to find Probability
  • The event A, called the complement of event A,
    consists of all outcomes that are not in A.
  • The notation A is read A prime.

10
Probability of the complement of an event
  • The probability of the complement of A is
  • P(A) 1 - P(A)

11
EXAMPLE 4
  • A card is randomly selected from a standard deck
    of 52 cards.
  • Find the probability of the given event.
  • a. The card is not a king.
  • P(K) 4/52 so P(K)
  • 48/52 0.923

12
  • b. The card is not an ace or a jack.
  • P(not ace or Jack) 1-(P(4/52 4/52))
  • 1- 8/52
  • 44/52 0.846

13
  • In a survey of 200 pet owners, 103 owned dogs, 88
    owned cats, 25 owned birds, and 18 owned
    reptiles.
  • 1. None of the respondents owned both a cat and a
    bird.
  • What is the probability that they owned a cat or
    a bird?
  • 113/200
  • 0.565
  • 2. Of the respondents, 52 owned both a cat and a
    dog.
  • What is the probability that a respondent owned a
    cat or a dog?
  • 139/200
  • 0.695

14
  • 3. Of the respondents, 119 owned a dog or a
    reptile.
  • What is the probability that they owned a dog and
    a reptile?
  • 1/100 0.010

15
Assignment
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