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IV

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... the same thing which is valid for a rod which makes a translation movement in a ... appears, if we run current I through a rod of the length L which can rotate ... – PowerPoint PPT presentation

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Title: IV


1
IV2 Inductance
2
Main Topics
  • Transporting Energy.
  • Counter Torque, EMF and Eddy Currents.
  • Self Inductance
  • Mutual Inductance

3
Transporting Energy I
  • The electromagnetic induction is a basis of
    generating and transporting electric energy.
  • The trick is that power is delivered at power
    stations, transported by means of electric energy
    (which is easy) and used elsewhere, perhaps in a
    very distant place.
  • To show the principle lets revisit our rod.

4
Moving Conductive Rod VIII
  • If the rails are not connected (or there are no
    rails), no work in necessary on the rod after the
    equilibrium ? is reached since there is no
    current.
  • If we dont move the rod but there is a current I
    flowing through it, there will be a force
    pointing to the left acting on it. We have
    already shown that F BIL.

5
Moving Conductive Rod IX
  • If we move the rod and connect the rails by a
    resistor R, there will be current I ?/R from
    Ohms law. Since the principle of superposition
    is valid, there will also be the force due to the
    current and we have to deliver power to move the
    rod against this force P Fv BILv ?I, which
    is exactly the power dissipated on the resistor R.

6
Counter Torque I
  • We can expect that the same thing which is valid
    for a rod which makes a translation movement in a
    magnetic field is also true for rotation
    movement.
  • We can show this on rotating conductive rod. We
    have to change the translation qualities to the
    rotation ones
  • P Fv T?

7
Counter Torque II
  • First let us show that torque appears, if we run
    current I through a rod of the length L which can
    rotate around one of its ends in homogeneous
    magnetic field B.
  • There is clearly a force on every dr of the rod.
    But to calculate the torque also r the distance
    from the rotation center must be taken into
    account, so we must integrate.

8
Counter Torque III
  • If we rotate the rod and connect a circular rail
    with the center by a resistor R, there will be
    current I ?/R. Due to the principle of
    superposition, there will be the torque due to
    the current and we have to deliver power to
    rotate the rod against this torque P T?
    BIL2?/2 ?I, which is again the power dissipated
    on the resistor R.

9
Counter EMF I
  • From the previous we know that the same is valid
    for linear as well as for rotating movement. So
    we can return to our rod, moving on rails for
    simplicity.
  • Let us connect some input voltage to the rails.
    There will be current given by this voltage and
    resistance in the circuit and there will be some
    force due to it.

10
Counter EMF II
  • After the rod moves also EMF appears in the
    circuit. It depends on the velocity and it has
    opposite polarity that the input voltage since
    the current due to this EMF must, according to
    the Lenzs law, oppose the initial current. We
    call this counter EMF.
  • The result current is superposition of the
    original current and that due to this EMF.

11
Counter EMF III
  • Before the rod (or any other electro motor) moves
    the current the greatest I0 V/R.
  • When the rod moves the current is given from the
    Kirchhofs law by the difference of the voltages
    in the circuit and resistance
  • I (V - ?)/R (V vBL)/R
  • The current apparently depends on the velocity of
    the rod.

12
Counter EMF IV
  • If the rod was without any load, if would
    accelerate until the induced EMF equals to the
    input voltage. At this point the current
    disappears and so does the force on the rod so
    there is no further acceleration.
  • Now, we also understand that an over-loaded
    motor, when it slows too much or stops, can
    burn-out due to large current.

13
Eddy Currents I
  • So far we dealt with one-dimensional rods totally
    immersed in the uniform magnetic field. But if
    the conductor is two or three dimensional and it
    is not completely immersed in the field or the
    field is non- uniform a new effect, called eddy
    currents appears.

14
Eddy Currents II
  • The change is that now the induced currents can
    flow within the conductor. They cause a forces
    opposing the movement so the movement is
    attenuated or power has to be delivered to
    maintain it.
  • Eddy currents can be used for some purposes e.g.
    smooth braking of some movements.

15
Eddy Currents III
  • Eddy currents produce heat so they are source of
    power loses and usually have to be eliminated as
    much as possible by special construction of
    electromotor frames or transformer cores e.g.
    laminating.

16
The Self Inductance I
  • We have shown that if we connect some input
    voltage to a free conductive rod immersed in
    external magnetic field an EMF appears which has
    the opposite polarity then the input voltage.
  • But even a piece of conducting wire without any
    external field will behave qualitatively the very
    same way.

17
The Self Inductance II
  • If we have such a wire and some current already
    flows through it, the wire is actually immersed
    in the magnetic field produced by this current.
  • If we now try e.g. to increase the current we are
    changing this magnetic field and thereby the flux
    and so an EMF is induced in a direction opposing
    the change.

18
The Self Inductance III
  • We can expect that the induced EMF in this
    general case depends on the
  • geometry of the wire and material properties of
    the surrounding space
  • rate of the change of the current
  • It is convenient to separate these effects and
    concentrate the former into one parameter called
    the (self) inductance L.

19
The Self Inductance IV
  • Then we can simply write
  • ? - L dI/dt
  • We are in a similar situation as we were in
    electrostatics. We used capacitors to set up
    known electric field in a given region of space.
    Now we use coils or inductors to set up known
    magnetic field in a specified region. As a
    prototype coil we usually use a solenoid (part
    near its center) or a toroid.

20
The Self Inductance V
  • If we have a solenoid with N loops and a flux ?
    passing through each loop, we can define the
    inductance and induced EMF as
  • L N?/I
  • ? - N d?/dt - L dI/dt
  • The unit for the inductance is 1 henry
  • 1H Vs/A Tm2/A (Tm2 1 Wb)

21
The Self Inductance VI
  • The flux through the loops of a solenoid depend
    on the current and the field produced by it and
    the geometry. In the case of a solenoid of the
    length L and cross section A and core material
    with ?r
  • L ?r?0N2A /L
  • In electronics parts having inductance inductors
    are needed and are produced.

22
The Mutual Inductance I
  • In a similar way we can describe mutual influence
    of two inductances more accurately total flux in
    one as a function of current on the other.
  • Let us have two coils Ni, Ii on a common core or
    close to each other.
  • Let ?21 be the flux in each loop of coil 2 due to
    the current in the coil 1.

23
The Mutual Inductance II
  • Then we define the mutual inductance M21 as total
    flux in all loops in the coil 2 per the unit of
    current (1 ampere) in the coil 1
  • M21 N2?21/I1
  • EMF in the coil 2 from the Faradays law
  • ?2 - N2d?21/dt - M21 dI1/dt
  • M21 depends on geometry of both coils.

24
The Mutual Inductance III
  • It can be shown that the mutual inductance of
    both coils is the same M21 M12 .
  • The fact that current in one loop induces EMF in
    other loop or loops has practical applications.
    It is e.g. used to power supply pacemakers so it
    is not necessary to lead wires through human
    tissue. But the most important use is in
    transformers.

25
Homework
  • No homework today!

26
Things to read and learn
  • Chapter 29 5, 6 30 1, 2

27
Rotating Conductive Rod
  • Torque on a piece dr which is in a distance r
    from the center of rotation of a conductive rod L
    with a current I in magnetic field B is
  • The total torque is

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