Title: Electronic Configurations
1Electronic Configurations and the Periodic Table
5.1 Relative Energies of Orbitals 5.2 Electronic
Configurations of Elements 5.3 The Periodic
Table 5.4 Ionization Enthalpies of
Elements 5.5 Variation of Successive Ionization
Ethalpies with Atomic Numbers 5.4 Atomic
Size of Elements
2Relative Energies of Orbitals
3Relative energies of orbitals
5.1 Relative energies of orbitals (SB p.106)
4Building up of electronic configurations
5.1 Relative energies of orbitals (SB p.106)
55.1 Relative energies of orbitals (SB p.106)
Aufbau principle states that electrons will enter
the possible orbitals in the order of ascending
energy.
Paulis exclusion principle states that electrons
occupying the same orbital must have opposite
spins.
Hunds rule (Rule of maximum multiplicity) states
that electrons must occupy each energy level
singly before pairing takes place (because of
their mutual repulsion).
6Electronic Configurations of Elements
7Represented by notations
5.2 Electronic configurations of elements (SB
p.108)
85.2 Electronic configurations of elements (SB
p.109)
Represented by notations
95.2 Electronic configurations of elements (SB
p.109)
Represented by notations
10Represented by electrons-in-boxes diagrams
5.2 Electronic configurations of elements (SB
p.110)
115.2 Electronic configurations of elements (SB
p.110)
12The Periodic Table
13The Periodic Table
5.3 The Periodic Table (SB p.112)
145.3 The Periodic Table (SB p.112)
s-block
p-block
d-block
f-block
155.3 The Periodic Table (SB p.112)
Let's Think 1
16Ionization Enthalpies of Elements
17Ionization enthalpies of elements
5.4 Ionization enthalpies of elements (SB p.115)
The first ionization enthalpies of the first 36
elements
185.4 Ionization enthalpies of elements (SB p.116)
The first ionization enthalpies generally
decrease down a group and increases across a
period
19Ionization enthalpy across a period
5.4 Ionization enthalpies of elements (SB p.116)
205.4 Ionization enthalpies of elements (SB p.116)
Q Explain why there is a general increase in the
ionization energy across a period.
- Moving across a period, there is an increase in
the nuclear attraction due to the addition of
proton in the nucleus. - The added electron is placed in the same quantum
shell. It is only poorly shielded by other
electrons in that shell. - The nuclear attraction outweighs the increase in
the shielding effect between the electrons. This
leads to an increase in the effective nuclear
charge. - The increase in the effective nuclear charge
causes a decrease in the atomic radius.
215.4 Ionization enthalpies of elements (SB p.117)
225.4 Ionization enthalpies of elements (SB p.117)
Q Explain why there is a trough at Boron(B) in
Period 2.
- e.c. of Be 1s22s2e.c. of B 1s22s22p1
- It is easier to remove the less penetrating
p-electron from B than to remove a s electron
from a stable fully-filled 2s subshell in Be.
235.4 Ionization enthalpies of elements (SB p.117)
245.4 Ionization enthalpies of elements (SB p.117)
Q Explain why there is a trough at Oxygen(O) in
Period 2.
- e.c. of N 1s22s22p3e.c. of O
1s22s22p4 - It is more difficult to remove an electron from
the halfly-filled 2p subshell of P, which has
extra stability. - After the removal of a p electron, a stable
half-filled 2 p subshell can be obtained for Q.
255.4 Ionization enthalpies of elements (SB p.117)
265.4 Ionization enthalpies of elements (SB p.117)
Q Explain why there is large drop of I.E.
between periods.
- The element at the end of a period has a stable
octet structure. Much energy is required to
remove an electron from it as this will disturb
the stable structure. - The element at the beginning of the next period
has one extra s electron in an outer quantum
shell. Although there is also an increase in the
nuclear charge, it is offset very effectively by
the screening effect of the inner shell
electrons. - Thus the atomic radius increases, making the
nucleus less effective in holding the s electron
in the outer shell
275.4 Ionization enthalpies of elements (SB p.117)
285.4 Ionization enthalpies of elements (SB p.117)
Q Explain why there is drop of I.E. down a group.
- In moving down a group, although there is an
increase in the nuclear charge, it is offset very
effectively by the screening effect of the inner
shell electrons. - Thus the atomic radius increases, making the
nucleus less effective in holding the s electron
in the outer shell
295.4 Ionization enthalpies of elements (SB p.117)
Q Explain why successive ionization energies
increase.
- It is more difficult to remove electron(negatively
charged) from higher positively charged ions.
305.4 Ionization enthalpies of elements (SB p.117)
Q Explain why successive ionization energy curve
follows the same pattern as the last one, but is
shifted by one unit of atomic number to the right.
- It is because the electronic configuration of AZ
is the same as Az-1.
31Variation of Successive Ionization Enthalpies
with Atomic Numbers
32Successive Ionization Enthalpies of the first 20
elements
5.5 Variation of successive ionization enthalpies
with atomic numbers (p. 119)
335.5 Variation of successive ionization enthalpies
with atomic numbers (p. 119)
345.5 Variation of successive ionization enthalpies
with atomic numbers (p. 120)
Variation of the first, second and third
ionization enthalpies of the first 20 elements
35Atomic Size of Elements
36Atomic size of elements
5.6 Atomic size of elements (p. 122)
375.6 Atomic size of elements (p. 122)
Q Explain why the atomic radius decreases across
a period.
- Moving across a period, there is an increase in
the nuclear attraction due to the addition of
proton in the nucleus. - The added electron is placed in the same quantum
shell. It is only poorly shielded/screened by
other electrons in that shell. - The nuclear attraction outweighs the increase in
the shielding effect between the electrons. This
leads to an increase in the effective nuclear
charge.
385.6 Atomic size of elements (p. 122)
11
Sodium atom Na (2,8,1)
395.6 Atomic size of elements (p. 122)
9
Sodium atom Na (2,8,1)
405.6 Atomic size of elements (p. 122)
1
Effective nuclear charge 1
Sodium atom Na (2,8,1)
415.6 Atomic size of elements (p. 122)
12
Magnesium atom Mg (2,8,2)
425.6 Atomic size of elements (p. 122)
10
Magnesium atom Mg (2,8,2)
435.6 Atomic size of elements (p. 122)
By similar argument, effective nuclear charge
2 for a Mg atom.
2
Magnesium atom Mg (2,8,2)
Thus effective nuclear charge increases across a
period.
445.6 Atomic size of elements (p. 122)
455.6 Atomic size of elements (p. 122)
Q Explain why the atomic radius increases down a
group.
- Moving down a group, although there is an
increase in the nuclear charge, it is offset very
effectively by the screening effect of the inner
shell electrons. - Moving down a group, an atom would have one more
electron shell occupied which lies at a greater
distance from the nucleus.
465.6 Atomic size of elements (p. 122)
Remarks
Effective nuclear charge can only be applied to
make comparison between atoms in the same period.
Never apply effective nuclear charge to atoms in
the same group.
47The END
485.1 Relative energies of orbitals (SB p.108)
Back
Check Point 5-1
- Write the electronic configurations and draw
electrons-in boxes diagrams for - (a) nitrogen and
- (b) sodium.
Answer
495.2 Electronic configurations of elements (SB
p.110)
Back
Check Point 5-2
- Give the electronic configuration by notations
and electrons-in-boxes diagrams in the
abbreviated form for the following elements. - silicon and
- copper.
Answer
505.3 The Periodic Table (SB p.113)
Back
Let's Think 1
If you look at the Periodic Table in Fig. 5-5
closely, you will find that hydrogen is separated
from the rest of the elements. Even though it has
only one electron in its outermost shell, it
cannot be called an alkali metal, why?
Answer
Hydrogen has one electron shell only, with n 1.
This shell can hold a maximum of two electrons.
Hydrogen is the only element with core electrons.
This gives it some unusual properties. Hydrogen
can lose one electron to form H, or gain an
electron to become H-. Therefore, it does not
belong to the alkali metals and halogens.
Hydrogen is usually assigned in the space above
the rest of the elements in the Periodic Table
the element without a family.
515.3 The Periodic Table (SB p.114)
Check Point 5-3
Outline the modern Periodic Table and label the
table with the following terms representative
elements, d-transition elements, f-transition
elements, lanthanide series, actinide series,
alkali metals, alkaline earth metals, halogens
and noble gases.
Answer
525.3 The Periodic Table (SB p.114)
Back
Check Point 5-3
535.4 Ionization enthalpies of elements (SB p.118)
Check Point 5-4
- Give four main factors that affect the magnitude
of ionization enthalpy of an atom.
Answer
- The four main factors that affect the magnitude
of the ionization enthalpy of an atom are - (1) the electronic configuration of the atom
- (2) the nuclear charge
- (3) the screening effect and
- (4) the atomic radius.
545.4 Ionization enthalpies of elements (SB p.118)
Check Point 5-4
- Explain why Group 0 elements have extra high
first ionization enthalpies and their decreasing
trend down the group.
Answer
- The first ionization enthalpies of Group 0
elements are extra high. It is because Group 0
elements have very stable electronic
configurations since their orbitals are
completely filled. That means, a large amount of
energy is required to remove an electron from a
completely filled electron shell of ns2np6
configuration. - Going down the group, the first ionization
enthalpies of Group 0 elements decreases. It is
because there is an increase in atomic radius
down the group, the outermost shell electrons
experience less attraction from the nucleus.
Further, as there is an increase in the number of
inner electron shells, the outermost shell
electrons of the atoms are better shielded from
the attraction of the nucleus (greater screening
effect). Consequently, though the nuclear charge
increases down the group, the outermost shell
electrons would experience less attraction from
the positively charged nucleus. That is why the
first ionization enthalpies decrease down the
group.
555.4 Ionization enthalpies of elements (SB p.118)
Back
Check Point 5-4
- Predict the trend of the first ionization
enthalpies of the transition elements.
Answer
(c) The first ionization enthalpies of the
transition elements do not show much variation.
The reason is that the first electron of these
atoms to be removed is in the 4s orbital. As the
energy levels of the 4s orbitals of these atoms
are more or less the same, the amount of energy
required to remove these electrons are similar.
565.5 Variation of successive ionization enthalpies
with atomic numbers (p. 121)
Example 5-5
- For the element 126C,
- (i) write its electronic configuration by
notation. - (ii) write its electronic configuration by
electrons-in- boxes diagram.
Answer
575.5 Variation of successive ionization enthalpies
with atomic numbers (p. 121)
Example 5-5
- The table below gives the successive ionization
enthalpies of carbon. -
- (i) Plot a graph of log ionization enthalpy
against number of electrons removed. - (ii) Explain the graph obtained.
Answer
585.5 Variation of successive ionization enthalpies
with atomic numbers (p. 121)
Example 5-5
595.5 Variation of successive ionization enthalpies
with atomic numbers (p. 121)
Back
Example 5-5
(ii) The ionization enthalpy increases with
increasing number of electrons removed. It is
because the effective nuclear charge increases
after an electron is removed, and more energy is
required to remove an electron from a positively
charged ion. Besides, there is a sudden rise
from the fourth to the fifth ionization
enthalpy. This is because the fifth ionization
enthalpy involves the removal of an electron
from a completely filled 1s orbital which is
very stable.
605.5 Variation of successive ionization enthalpies
with atomic numbers (p. 122)
Check Point 5-5
- Give the electrons-in-boxes diagram of 26Fe.
- Fe2 and Fe3 have 2 and 3 electrons less than Fe
respectively. If the electrons are removed from
the 4s orbital and then 3d orbitals, give the
electronic configurations of Fe2 and Fe3.
Answer
615.5 Variation of successive ionization enthalpies
with atomic numbers (p. 122)
Check Point 5-5
- (c) Which ion is more stable, Fe2 or Fe3?
Explain briefly.
(c) Fe3 ion is more stable because the 3d
orbital is exactly half-filled which gives the
electronic configuration extra stability.
Answer
625.5 Variation of successive ionization enthalpies
with atomic numbers (p. 122)
Check Point 5-5
- Given the successive ionization enthalpies of Fe
- (i) plot a graph of successive ionization
enthalpies in logarithm scale against the
number of electrons removed - (ii) state the difference of the plot from that
of carbon as shown in P. 121.
Answer
635.5 Variation of successive ionization enthalpies
with atomic numbers (p. 122)
Check Point 5-5
645.5 Variation of successive ionization enthalpies
with atomic numbers (p. 122)
Check Point 5-5
(ii) The ionization enthalpy increases with
increasing number of electrons removed. This is
because it requires more energy to remove an
electron from a higher positively charged ion. In
other words, higher successive ionization
enthalpies will have higher magnitudes. However
, the sudden increase from the fourth to the
fifth ionization enthalpies occurs in carbon but
not in iron. This indicates that when electrons
are removed from the 4s and 4d orbitals, there
is no disruption of a completely filled electron
shell. Hence, there are no irregularities for
the first six successive ionization enthalpies
of iron.
Back
655.6 Atomic size of elements (p. 123)
Check Point 5-6
- Explain the following
- (a) The atomic radius decreases across the
period from Li to Ne.
Answer
(a) When moving across the period from Li to Ne,
the atomic sizes progressively decrease with
increasing atomic numbers. This is because an
increase in atomic number by one means one more
electron and one more proton in atoms. The
additional electron would cause an increase in
repulsion between the electrons in the outermost
shell. However, since each additional electron
goes to the same quantum shell and is at
approximately the same distance from the nucleus,
the repulsion between electrons is relatively
ineffective to cause an increase in the atomic
radius. On the other hand, as there is an
additional proton added to the nucleus, the
electrons will experience a greater attractive
force from the nucleus (increased effective
nuclear charge). Hence, the atomic radii of atoms
decrease across the period from Li to Ne.
665.6 Atomic size of elements (p. 123)
Back
Check Point 5-6
- Explain the following
- (b) The atomic radius increases down Group I
metals.
Answer
(b) Moving down Group I metals, the atoms have
more electron shells occupied. The outermost
electron shells become further away from the
nucleus. Besides, the inner shell electrons will
shield the outer shell electrons more effectively
from the nuclear charge. This results in a
decrease in the attractive force between the
nucleus and the outer shell electrons. Therefore,
the atomic radii of Group I atoms increase down
the group.