Title: Domains%20and%20Inverse%20Functions
1DomainsandInverse Functions
2Objectives
- Determine the domain and range (where possible)
of a function given as an equation. - Determine if a function given as an equation is
one-to-one. - Determine if a function given as a graph is
one-to-one. - Algebraically find the inverse of a one-to-one
function given as an equation.
3Objectives
- State the domain and range of a function and it
inverse. - State the relationships between the domain and
range of a function and its inverse - Restrict the domain of a function that is not
one-to-one so that an inverse function can be
found. - Draw the graph of the inverse function given the
graph of the function.
4Vocabulary
- inverse function
- horizontal line test
- function composition
- one-to-one function
5Domain Questions
- Does the function have a denominator?
- Does the function have a square or even root?
- Does the function have a log or ln in it?
- Did the function arise from finding an inverse?
- Is this a real world problem?
6Find the domain of the function
7Find the domain of the function
8Find the domain of the function
9Find the domain of the function
10Given the functions and
find each of the following
11Determine if the function is one-to-one.
12Steps for finding an inverse function.
- Change the function notation f(x) to y.
- Change all the xs to ys and ys to xs.
- Solve for y.
- Replace y with f -1(x).
13Find the inverse of the function
Find the domains of the function and its inverse.
14Find the inverse of the function
Find the domains of the function and its inverse.
15Find the inverse of the function
Find the domains of the function and its inverse.
16Find the inverse of the function
Find the domains of the function and its inverse.
17Draw the graph of the inverse function for the
graph of f(x) shown below.
18The function is not one-to-one. Choose
the largest possible domain containing the number
100 so that the function restricted to the domain
is one-to-one. Find the inverse function for
that restricted function.