Title: FUN WITH PYTHAGORAS
1FUN WITH PYTHAGORAS
Once upon a time (about 500B.C.) in a land far
away (Greece) lived a wise and learned man called
PYTHAGORAS
who said....
2FUN WITH PYTHAGORAS
- In a right-angled triangle,
- the SQUARE on the HYPOTENEUSE is equal to
- the SUM of the SQUARES on the OTHER TWO SIDES
OR
A
A B C
B
C
SO WHAT?
And the people all said....
3FUN WITH PYTHAGORAS
Well, it must be important or we wouldnt still
be talking about it after more than 2,500
years! And it doesnt take a genius to see that,
if you know the length of two sides of a
right-angled triangle, you can calculate the
length of the third side by using Pythagorass
theorem. This has uses in navigation, cartography
(map making), astronomy, design and construction,
etc. And it is fundamental in the development of
trigonometry and geometry. The thing is that,
before we can just accept it, we really ought to
prove that it works...
4FUN WITH PYTHAGORAS
Firstly, lets check what we mean by a
right-angled triangle...
HYPOTENEUSE
ONE ANGLE IN THE TRIANGLE MUST BE 90 THE SIDE
OPPOSITE THE RIGHT ANGLE IS CALLED THE HYPOTENEUSE
NOW LETS SEE IF WE CAN PROVE WHAT PYTHAGORAS
SAID ABOUT THE SQUARES...
90
5FUN WITH PYTHAGORAS
DRAW A SQUARE
6FUN WITH PYTHAGORAS
DRAW A SECOND SMALLER SQUARE INSIDE THE FIRST AND
HAVING THE SAME CENTRE.
7FUN WITH PYTHAGORAS
NOW ROTATE THE SMALLER SQUARE ABOUT ITS CENTRE
UNTIL ITS CORNERS TOUCH THE SIDES OF THE LARGER
SQUARE
8FUN WITH PYTHAGORAS
9FUN WITH PYTHAGORAS
10FUN WITH PYTHAGORAS
11FUN WITH PYTHAGORAS
12FUN WITH PYTHAGORAS
AS YOU CAN SEE, WE HAVE CREATED 4 TRIANGLES AND,
BECAUSE THE CORNERS OF THE SQUARES ARE RIGHT
ANGLES, THE TRIANGLES ARE ALSO RIGHT-ANGLED.
13FUN WITH PYTHAGORAS
LETS LABEL THE SIDES OF THE TRIANGLES a, b AND c
WHERE, FROM OUR DEFINITION, c IS THE HYPOTENEUSE
c
b
a
14FUN WITH PYTHAGORAS
IN FACT, WE CAN LABEL THE SIDES OF ALL 4 TRIANGLES
b
a
b
c
a
c
c
a
c
b
a
b
15FUN WITH PYTHAGORAS
SIDE OF LARGE SQUARE a b AREA OF LARGE SQUARE
(a b) x ( a b) a² 2ab b²
b
a
b
c
a
c
c
a
c
b
a
b
16FUN WITH PYTHAGORAS
AREA OF TRIANGLE abc ½ x a x b 1/2ab AREA OF
SMALLER SQUARE c x c c² TOTAL AREA OF 4
TRIANGLES SMALLER SQUARE 4 x 1/2ab c²
2ab c²
a
b
b
c
a
c
c
a
c
b
a
b
17FUN WITH PYTHAGORAS
FROM PREVIOUS TWO SLIDES TOTAL AREA OF LARGE
SQUARE a² 2ab b² 2ab c² REMOVING 2ab
FROM BOTH SIDES, a² b² c²
a
b
b
c
a
c
c
a
c
b
a
b
18FUN WITH PYTHAGORAS
BUT c² IS THE SQUARE ON THE HYPOTENEUSE AND a²
AND b² ARE THE SQUARES ON THE OTHER TWO SIDES
JUST AS PYTHAGORAS SAID!
a
b
b
c
a
c
c
a
c
b
a
b
19FUN WITH PYTHAGORAS
BELIEVE IT NOT, SINCE PYTHAGORAS POSTULATED HIS
THEOREM, OTHER PEOPLE HAVE DEVISED IN EXCESS OF
500 PROOFS.
HERES THE NEXT ONE...
20FUN WITH PYTHAGORAS
DRAW A RIGHT-ANGLED TRIANGLE
21FUN WITH PYTHAGORAS
CONSTRUCT THE SQUARE ON ONE SIDE
22FUN WITH PYTHAGORAS
THEN ANOTHER
23FUN WITH PYTHAGORAS
AND FINALLY THE THIRD
24FUN WITH PYTHAGORAS
CONSTRUCT A LINE PARALLEL TO ONE SIDE OF THE
HYPOTENEUSE (BLUE) SQUARE SO THAT IT PASSES
THROUGH THE CENTRE OF THE SECOND (RED) SQUARE
25FUN WITH PYTHAGORAS
THEN A SECOND LINE PARALLEL TO THE OTHER SIDE OF
THE BLUE SQUARE ALSO PASSING THROUGH THE CENTRE
OF THE RED SQUARE
26FUN WITH PYTHAGORAS
CUT THE RED SQUARE INTO FOUR AS INDICATED BY THE
LINES JUST DRAWN
1
27FUN WITH PYTHAGORAS
CUT THE RED SQUARE INTO FOUR AS INDICATED BY THE
LINES JUST DRAWN
2
28FUN WITH PYTHAGORAS
CUT THE RED SQUARE INTO FOUR AS INDICATED BY THE
LINES JUST DRAWN
3
29FUN WITH PYTHAGORAS
CUT THE RED SQUARE INTO FOUR AS INDICATED BY THE
LINES JUST DRAWN
4
30FUN WITH PYTHAGORAS
SLIDE THE SECTIONS INTO THE BLUE SQUARE
31FUN WITH PYTHAGORAS
32FUN WITH PYTHAGORAS
33FUN WITH PYTHAGORAS
34FUN WITH PYTHAGORAS
AND FINALLY SLIDE THE SMALLEST SQUARE INTO THE
HOLE REMAINING IN THE LARGEST SQUARE
WE HAVE NOW TRANSFERRED THE SQUARES FROM THE
SMALLER TWO SIDES ONTO THE SQUARE ON THE
HYPOTENEUSE, ONCE AGAIN PROVING THAT...
35FUN WITH PYTHAGORAS
- In a right-angled triangle,
- the SQUARE on the HYPOTENEUSE is equal to
- the SUM of the SQUARES on the OTHER TWO SIDES
36FUN WITH PYTHAGORAS
- In a right-angled triangle,
- the SQUARE on the HYPOTENEUSE is equal to
- the SUM of the SQUARES on the OTHER TWO SIDES