RAD2'ppt Heat Transfer by Both Radiation - PowerPoint PPT Presentation

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RAD2'ppt Heat Transfer by Both Radiation

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Heat will flow from the gas to the thermocouple by convection, but ... power of thermocouple = 5.67 x 10 ... Nett radiative heat flux from thermocouple to walls ... – PowerPoint PPT presentation

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Title: RAD2'ppt Heat Transfer by Both Radiation


1
RAD2.pptHeat Transfer by Both Radiation
Convection
2
Components of Course What Stage are We Up To?
  • Types of exchangers, revision of OHTCs, fouling
    factors.
  • Heat exchanger selection.
  • Thermal performance analysis (NTUs) for co-
    counter-current exchangers.
  • Multi-pass exchangers (ST).
  • Condensation boiling.
  • Radiation.

3
Applications
  • Temperature measurement of a hot fluid when walls
    are at a different temperature to gas
  • Heat losses from hot surfaces into air or other
    fluids at high temperatures (gt200oC) when
    radiation also becomes significant

4
Application
  • If hot gas is at a temperature of 500 K and the
    walls of a pipe are at 300 K, then what will be
    the temperature measured by a thermocouple or
    other temperature measurement device which is in
    the pipe?

5
Need to Know...
  • Emissivity of thermocouple 0.1
  • Convective heat-transfer coefficient 50 W
    m-2 K-1

6
What Will Happen?
  • Heat will flow from the gas to the thermocouple
    by convection, but
  • Heat will flow from the thermocouple to the walls
    by radiation

7
What Do We Want to Happen?
  • Thermocouple should read gas temperature,
    uninfluenced by walls
  • Only perfectly true if
  • walls at gas temperature
  • infinite (very high) convective heat-transfer
    coefficient
  • zero (very low) emissivity

8
Heat Transfer by Radiation
9
(No Transcript)
10
Calculations
  • Eb1 emissive power of thermocouple 5.67
    x 10-8 T4
  • Eb2 emissive power of walls 5.67 x 10-8 3004
    459 W m-2

11
Nett Radiative Heat Flux From Thermocouple to
Walls
12
Heat Transfer by Convection
Nett convective heat transfer flowrate between
two temperatures T1 and T2 h
A (T1 - T2) Nett convective heat transfer flux
h (T1 - T2)
13
Nett Convective Heat Flux From Gas to Thermocouple
  • 50 (500 - T)

14
At Steady State
  • Nett convective heat flux from gas to
    thermocouple
  • Nett radiative heat flux from thermocouple to
    walls

15
Solution
  • Solve (Excel) to get T 494 K (cf. gas
    temperature 500 K)
  • Little error here because of relatively low
    temperatures (around 200oC)

16
Conclusions
  • Can combine any / all mechanisms of heat transfer
  • Applications in measurements of high temperatures
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