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Impulse

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(1) the objects stick together after collision (2) kinetic energy is lost and turned into ... See active figure 9.13 at pse6.com. mAvA = mAvAx' mBvBx' 0 ... – PowerPoint PPT presentation

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Title: Impulse


1
Impulse
  • J FDt
  • Unit N-s kg-m/s

2
Momentum
p mv Unit kg-m/s
3
Impulse-Momentum Thm.
FDt maDt
4
CONSERVATION OF MOMENTUM
  • Assuming an isolated system where no
  • Outside forces are acting on the system,
  • Total momentum of the system will be a constant
    that is, total momentum before will equal total
    momentum after.

5
Derivation of Cons. of Momentum
F21 mAvA mAvA F12 -F21 mBvB
mBvB mAvA mAvA mBvB mBvB
mAvA mBvB mAvA mBvB
6
Example of Conservation of Momentum Newtons
Experiment
7
Conservation of Momentum
  • mAvA mBvB mAvA mBvB
  • mA mass of object A
  • mB mass of object B
  • vA velocity of object A before collision
  • vB velocity of object B before collision

vA velocity of object A after collision vB
velocity of object B after collision
8
Inelastic Collisions
  • Inelastic Collisions have the following
  • properties
  • (1) the objects stick together after collision
  • (2) kinetic energy is lost and turned into
  • heat energy
  • (3) momentum is conserved

9
Inelastic Collisions 2
  • mAvA mBvB mAv mBv

10
Special cases of inelastic collisions
  • Case 1 mA lt mB
  • v
  • V 0
  • Case 2 mA gt mB
  • V VA

11
Elastic Collisions
  • Elastic collisions have the below properties
  • (1) the objects bounce off each other
  • (2) no kinetic energy is lost and no heat is
    produced
  • (3) momentum is conserved

12
Elastic Collisions 2
13
Special Cases of Elastic Collisions
  • Case 1 mA mB vA 0 , vB vA
  • Case 2 mA lt mB
  • VA -VA
  • Case 3 mA gt mB
  • vA vA

14
Fraction of K.E. transferred in elastic collisions
  • ftransferred 4b/(1b) 2
  • mA/mB
  • Case 1 mA mB ,b 1, f 4(1)/(11)2 1
  • Case 2 mAltmB , b 0 , f 0
  • Case 3 mAgtmB , b infinity , f 4/b 0

15
Collisions in 2-dimensions
16
2-dim. Collisions (2)
  • See active figure 9.13 at pse6.com
  • mAvA mAvAx mBvBx
  • 0 mAvAy mBvBy
  • mAvA mAvAcosqA mBvBcosqB
  • 0 mAvAsinqA mBvBsinqB

17
Ballistic Pendulum
vB mAvA/(mAmB) Mgh (1/2)MvB2
18
Recoil momentum
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