Bessels Inequality and Parsevals Equality - PowerPoint PPT Presentation

1 / 17
About This Presentation
Title:

Bessels Inequality and Parsevals Equality

Description:

MATH C241 Prepared by MSR. Multiplying both ... MATH C241 Prepared by MSR. Hence the previous calculations show that, Bessel's inequality becomes an equality ... – PowerPoint PPT presentation

Number of Views:302
Avg rating:3.0/5.0
Slides: 18
Provided by: discovery5
Category:

less

Transcript and Presenter's Notes

Title: Bessels Inequality and Parsevals Equality


1
Bessels Inequality and Parsevals Equality
- Mean Convergence of Fourier Series
2
BESSELS INEQUALITY
Let f(x) be piecewise continuous on the interval
If the Fourier series of f(x) is given by
then
3
The above inequality is called Bessels
inequality.
Proof Let n ? 1.
Define
(sn(x) is often referred to as the sum to n
terms of the Fourier series of f(x).)
Multiplying both sides by
and
and
integrating between
we get
4
(using the definitions of ans and bns) that
We note that
5
Multiplying both sides by and integrating between
and we get
(using the orthogonality of trigonometric
functions).

6
Now
7
Since
we get
Letting
we get the Bessels inequality.
Corollary
The Fourier coefficients
as
8
Mean convergence of Fourier series PARSEVALS
EQUALITY
it can be
If f(x)2 is integrable on
shown that
We thus say
in the mean
and write
9
Hence the previous calculations show that,
Bessels inequality becomes an equality
called PARSEVALS EQUALITY.
Application 1
The Fourier series of f(x) x is given by
10
Thus
(and an 0 for all n )
and
Hence Parsevals equality gives
11
Application 2 The Fourier series of f(x) x2 is
given by
Thus
for all n 1,2,3,..
Hence, Parsevals equality gives
12
or
Application 3 Let f(x) x2. The Fourier Sine
series for f(x) x2
is
in
13
where
14
(No Transcript)
15
(No Transcript)
16
Also
Hence we get
17
Thus
END OF FOURIER SERIES
Write a Comment
User Comments (0)
About PowerShow.com