Title: Welcome to PreCalculus today we will
1Welcome to Pre-Calculustoday we will
- Review/Discuss Syllabus and Schedule
- Cover sections 2.5 and 4.1
- Cover electronic resources available to assist
you in the course
2Chapter 2
- Section 2.5 Piecewise-Defined Functions
32.5 Piecewise-Defined Functions
- Piecewise-defined function is a function defined
by different rules over different subsets of its
domain. -
- Book Example Find each function value given
the piecewise-defined function - Solution
- (a)
- (b)
- (c)
4- Book example continued
- (d) The graph of
- Graph the ray choosing x
so that with a solid - endpoint (filled in circle) at (0,2). The
ray has slope 1 and - y-intercept 2. Then, graph for
This graph will be - half of a parabola with an open endpoint (open
circle) at (0,0).
Figure 51 pg 2-117
52.5 Graphing a Piecewise-Defined Function with
a Graphing Calculator
- Use the test feature
- Returns 1 if true, 0 if false when plotting the
value of x - In general, it is best to graph piecewise-defined
functions in dot mode, especially when the graph
exhibits discontinuities. Otherwise, the
calculator may attempt to connect portions of the
graph that are actually separate from one another.
62.5 Graphing a Piecewise-Defined Function
- Sketch the graph of and give f(7) and f(0)
- Solution
- (will do on calculator)
- f(7)
- f(0)
- Now lets try number 20 on page 145 graph by hand
then check on calculator
72.5 The Greatest Integer (Step) Function
-
- Example Evaluate for (a) 5, (b) 2.46,
and (c) 6.5 - Solution (a)
- (b)
- (c)
- Using the Graphing Calculator
- The command int is used by many graphing
calculators for the greatest integer function.
82.5 The Graph of the Greatest Integer Function
- Domain
- Range
- If using a graphing calculator, put the
calculator in dot mode.
Figure 58 pg 2-124
92.5 Graphing a Step Function
- Graph the function defined by
Give the domain and range. - Solution
- Try some values of x.
-
102.5 Application of a Piecewise-Defined Function
- Downtown Parking charges a 5 base fee for
parking through 1 hour, and - 1 for each additional hour or fraction thereof.
The maximum fee for 24 - hours is 15. Sketch a graph of the function that
describes this pricing - scheme.
- Solution
- Sample of ordered pairs (hours,price)
(.25,5), (.75,5), (1,5), (1.5,6), (1.75,6). -
- During the 1st hour price 5
- During the 2nd hour price 6
- During the 3rd hour price 7
-
- During the 11th hour price 15
-
- It remains at 15 for the rest of
- the 24-hour period.
- Plot the graph on the interval (0,24.
Figure 62 pg 2-127
112.5 Using a Piecewise-Defined Function to
Analyze Data
- Due to acid rain, The percentage of lakes in
Scandinavia that lost their - population of brown trout increased dramatically
between 1940 and 1975. - Based on a sample of 2850 lakes, this percentage
can be approximated by - the piecewise-defined function f .
- Graph f .
- Determine the percentage of lakes that had lost
brown trout by 1972.
122.5 Using a Piecewise-Defined Function to
Analyze Data
- Solution
- (a) Analytic Solution Plot the two endpoints
and draw the line - segment of each rule.
- Note Even though there is an open
- circle at the point (1960,18)
- from the first rule, the second
- rule closes it. Therefore, the
- point (1960,18) is closed.
-
Figure 63 pg 2-128
132.5 Using a Piecewise-Defined Function to
Analyze Data
- Graphing Calculator Solution
- (b) Use the second rule with x 1972.
-
By 1972, about 44 of the lakes had lost their
population of brown trout.
14Chapter 4
- Section 4.1 Rational Functions and Graphs
- Quick note here is it may be helpful to review
sections 2.1, 2.2 and 2.3 basics of graphing
functions and transformations.
154.1 Rational Functions and Graphs
- Rational function quotient of two polynomials
- p(x) and q(x), with q(x) ? 0.
- Examples
164.1 The Reciprocal Function
- The simplest rational function the reciprocal
function
174.1 The Reciprocal Function
184.1 Transformations of the Reciprocal Function
- The graph of can be shifted, translated,
and reflected. - Example Graph
- Solution The expression
- can be written as
- Stretch vertically by a
- factor of 2 and reflect across
- the y-axis (or x-axis).
194.1 Graphing a Rational Function
- Example Graph
- Solution Rewrite y
- The graph is shifted left 1 unit and
stretched - vertically by a factor of 2.
20Practice Problem
- Lets try problem 26 page 277
214.1 The Rational Function f (x) 1/x2
224.1 Graphing a Rational Function
Vertical Asymptote x 2 Horizontal
Asymptote y 1.
23Practice Problem
- Lets try problem 32 page 277
244.1 Mode and Window Choices for Calculator
Graphs
- Non-decimal vs. Decimal Window
- A non-decimal window (or connected mode) connects
plotted points. - A decimal window (or dot mode) plots points
without connecting the dots. - Use a decimal window when plotting rational
functions such as - If y is plotted using a non-decimal window, there
would be a vertical line at x 1, which is not
part of the graph.
254.1 Mode and Window Choices for Calculator
Graphs
- Illustration
- Note See Table for the y-value at x 1 y1
ERROR.
26In Pre-Calculustoday we will
- Review/Discuss Homework from 2.5 and 4.1
- Cover section 4.2
27Chapter 4
- Section 4.2 More on Graphs of Rational Functions
- Graphing rational functions beyond transformation
of the rational - function or the function
- Graphing rational functions involves several
stepsthe first of which is graphing asymptotes.
284.2 More on Graphs of Rational Functions
Vertical and Horizontal Asymptotes
If the function itself (thats the Ys) goes to
either positive or negative infinity (shoots up
or down) at a point along the x-axis then the
value at that point represents a vertical
asymptote x a If the function itself begins to
flatten out to a specific value as x goes to
infinity in either direction (basically it
becomes almost horizontal at y-value) then the
value is a horizontal asymptote y a
294.2 More on Graphs of Rational Functions
- So how do you find horizontal and vertical
asymptotes without going straight to the
calculator and graphing it? - Vertical is straight forward, set the denominator
equal to zero and solve for x.the solutions are
the x values where there are vertical asymptotes - Horizontal and Oblique asymptotes are a bit more
complicated there are three possible cases which
we will cover. - Numerator lesser degree than denominator
- Numerator and denominator same degree
- Numerator of one higher degree than denominator
304.2 Finding Asymptotes Example 1
- Example 1 Find the asymptotes of the graph of
- Solution Vertical asymptotes set denominator
- equal to 0 and solve.
314.2 Finding Asymptotes Example 1
- Horizontal asymptote divide each term by the
- variable factor of greatest degree, in this case
x2. - Therefore, the line y 0 is the horizontal
asymptote.
324.2 Finding Asymptotes Example 2
- Example 2 Find the asymptotes of the graph of
- Solution
- Vertical asymptote solve the equation x 3
0. - Horizontal asymptote divide each term by x.
334.2 Finding Asymptotes Example 3
- Example 3 Find the asymptotes of the graph of
- Solution
- Vertical asymptote
- Horizontal asymptote
344.2 Finding Asymptotes Example 3
- Rewrite f using synthetic division as follows
- For very large values of is close
to 0, and - the graph approaches the line y x 2. This line
is an - oblique asymptote (neither vertical nor
horizontal) - for the graph of the function.
354.2 Determining Asymptotes
- To find asymptotes of a rational function defined
by a rational - expression in lowest terms, use the following
procedures. - Vertical Asymptotes
- Set the denominator equal to 0 and solve for x.
If a is a zero of the denominator but not the
numerator, then the line x a is a vertical
asymptote. - Other Asymptotes Consider three possibilities
- If the numerator has lower degree than the
denominator, there is a horizontal asymptote, y
0 (x-axis). - If the numerator and denominator have the same
degree, and f is -
364.2 Determining Asymptotes
- Other Asymptotes (continued)
- If the numerator is of degree exactly one greater
than the denominator, there may be an oblique
asymptote. To find it, divide the numerator by
the denominator and disregard any remainder. Set
the rest of the quotient equal to y to get the
equation of the asymptote. - Notes
- The graph of a rational function may have more
than one vertical asymptote, but can not
intersect them. - The graph of a rational function may have only
one other non-vertical asymptote, and may
intersect it.
374.2 Graphing Rational Functions
- Let define a rational
expression in lowest terms. - To sketch its graph, follow these steps.
- Find all asymptotes.
- Find the x- and y-intercepts.
- Determine whether the graph will intersect its
non-vertical asymptote by solving f (x) k
where y k is the horizontal asymptote, or f (x)
mx b where - y mx b is the equation of the oblique
asymptote. - Plot a few selected points, as necessary. Choose
an x-value between the vertical asymptotes and
x-intercepts. - Complete the sketch.
384.2 Comprehensive Graph Criteria for a Rational
Function
- A comprehensive graph of a rational function will
- exhibits these features
- all intercepts, both x and y
- location of all asymptotes vertical, horizontal,
and/or oblique - the point at which the graph intersects its
non-vertical asymptote (if there is such a
point) - enough of the graph to exhibit the correct end
behavior (i.e. behavior as the graph approaches
its nonvertical asymptote).
394.2 Graphing a Rational Function
- Example Graph
- Solution
- Step 1
- Step 2 x-intercept solve f (x) 0
404.2 Graphing a Rational Function
- y-intercept evaluate f (0)
- Step 3 To determine if the graph intersects the
- horizontal asymptote, solve
- Since the horizontal asymptote is the x-axis,
- the graph intersects it at the point (1,0).
414.2 Graphing a Rational Function
- Step 4 Plot a point in each of the intervals
determined - by the x-intercepts and vertical asymptotes,
- to get an
- idea of how the graph behaves in each region.
- Step 5 Complete the sketch. The graph approaches
- its asymptotes as the points become farther
- away from the origin.
424.2 Graphing a Rational Function That Does Not
Intersect Its Horizontal Asymptote
- Example Graph
- Solution Vertical Asymptote
- Horizontal Asymptote
-
- x-intercept
- y-intercept
- Does the graph intersect the horizontal
asymptote?
434.2 Graphing a Rational Function That Does Not
Intersect Its Horizontal Asymptote
-
- To complete the graph of
choose - points (4,1) and .
444.2 Graphing a Rational Function with an
Oblique Asymptote
- Example Graph
- Solution Vertical asymptote
- Oblique asymptote
-
- x-intercept None since x2 1 has no real
solutions. - y-intercept
454.2 Graphing a Rational Function with an
Oblique Asymptote
- Does the graph intersect the oblique
asymptote? -
- To complete the graph, choose the points
464.2 Graphing a Rational Function with a Hole
- Example Graph
- Solution Notice the domain of the function
cannot include 2. - Rewrite f in lowest terms by factoring the
numerator.
The graph of f is the graph of the line y x
2 with the exception of the point with x-value 2.
47In Pre-Calculustoday we will
- Review/Discuss Homework from previous sections
- Cover section 4.3
48Chapter 4
- Section 4.3 - Rational Equations, inequalities,
Applications and Models - Here we will deal with equations (and
inequalities) that contain one or more rational
expressions. - Again there will be multiple steps to solving the
rational equation or inequality. - We will look at equations first, then
inequalities, applications are mixed.
494.3 Solving Equations Involving Rational
Functions
- Determine all values for which the rational
function is undefined. - Multiply both sides of the equation by the least
common denominator of the entire equation. - Solve the resulting equation.
- Reject any values that were determined in Step 1.
- These steps are the analytic (by hand) approach,
it can also be solved graphically
504.3 Solving a Rational Equation Analytically
- Example Solve
- Analytic Solution Notice that the expression is
- undefined for
Multiply both sides by 2x 1.
Solve for x.
The solution set is 1.
514.3 Solving a Rational Equation Graphically
- Graphical Solution Rewrite the equation as
- and define Y1 Using
the - x-intercept method shows that the zero of the
function - is 1.
524.3 Solving Inequalities Involving Rational
Functions
- Move all terms to the right side and combine to
get a single rational expression, a zero will
remain on the left side. - Determine values for which the new rational
function is undefined (denom. Equals zero) or
zero (numer. Equals zero). - Use the values from step 2 to develop a truth or
sign table using test values for each interval. - Use the results of the table to identify where
the function satisfies the inequality from step 1 - These steps are the analytic (by hand) approach,
it can also be solved graphically
534.3 Solving a Rational Inequality Analytically
- Example Solve the rational inequality
- Analytic Solution We cant multiply both sides
- by 2x 1 since it may be negative. Start by
- subtracting 1 from both sides.
Common denominator is 2x 1.
544.3 Solving a Rational Inequality Analytically
- To determine the sign graph, solve the equations
- to get x 1 and
Rewrite as a single fraction.
554.3 Solving a Rational Inequality Analytically
- Complete the sign graph and determine the
intervals - where the quotient is negative.
- The quotient is zero or negative when x is in
- Cant include it makes the denominator 0.
- The book shows a truth table on page293, either
is fine.
564.3 Solving a Rational Inequality Graphically
- Graphical Solution Let Y1
We use the - graph to find the intervals where Y1 is below the
- x-axis, including the x-intercepts, where Y1 0.
- The solution set is
574.3 Solving a Rational Equation one more
example
- Example Solve
- Solution For this equation,
584.3 Solving a Rational Equation
- But, x 2 is not in the domain of the original
- equation and, therefore, must be rejected. The
- solution set is 5.
- Lets Try 38 and 66 on page 302 Analytically and
check graphically
594.3 Applications and Models of Rational
Functions Traffic Intensity
- Example Vehicles arrive randomly at a parking
ramp at an - average rate of 2.6 vehicles per minute. The
parking attendant - can admit 3.2 cars per minute. However, since
arrivals are - random, lines form at various times.
- Traffic intensity x is the ratio of the average
arrival rate to the average admittance rate.
Determine x for this parking ramp. - The average number of vehicles waiting in line to
enter the ramp is modeled by f (x)
where 0 ? x lt1 is the traffic intensity. Compute
f (x) for this parking ramp. - Graph y f (x). What happens to the number of
vehicles waiting as the traffic intensity
approaches 1? - (This problem is similar to 77 in your
homework)
604.3 Applications and Models of Rational
Functions Traffic Intensity
- Solution
- Average arrival rate 2.6 vehicles/min,
- average admittance rate 3.2 vehicles/min, so
- (b) From part (a), the average number of vehicles
waiting in line is f (.8125).
614.3 Applications and Models of Rational
Functions Traffic Intensity
- (c) From the graph below, we see that as x
approaches 1, y f (x) gets very large, that
is, the number of waiting vehicles gets very
large.
624.3 Applications and Models of Rational
Functions Optimization Problem
- Example A manufacturer wants to construct
cylindrical - aluminum cans with volume 2000 cm3 (2 liters).
What radius - and height will minimize the amount of aluminum
used? - What will this amount be?
- Solution Two unknowns radius x
- and height h. To minimize the amount
- of aluminum, we minimize the surface
- area. Volume V is
- (like problem73 on page 303)
634.3 Applications and Models of Rational
Functions Optimization Problem
- Surface area S 2?xh 2?x2, x gt 0 (since x is
the radius), can - now be written as a function of x.
- Minimum radius is approximately 6.83 cm and the
height - associated with that is ?13.65 cm,
giving a minimum - amount of aluminum of 878.76 cm3.
644.3 Applications and Models of Rational
Functions Variation
- There are several types of variation
- Direct y varies directly as x
- Inverse y varies inversely as x
- Jointly y varies jointly as x and z
- All three forms may also include a power i.e. y
varies directly as the second power of x or y is
inversely proportional to x cubed -
654.3 Modeling the Intensity of Light
- The intensity of light, I is inversely
proportional to the second power of the distance
d. The equation - models this phenomenon. At a distance of 3
meters, a 100-watt bulb produces an intensity of
.88 watt per square meter. Find the constant of
variation k, and then determine the intensity of
the light at a distance of 2 meters. - Substitute d 3, and I .88 into the variation
equation, and solve for k.
664.3 Solving a Combined Variation Problem in
Photography
- In the photography formula
- the luminance L (in foot-candles) varies directly
as the square of the F-stop F and inversely as
the product of the file ASA number s and the
shutter speed t. The constant of variation is 25. - Suppose we want to use 200 ASA file and a shutter
speed of 1/250 when 500 foot candles of light are
available. What would be an appropriate F-stop?
An F-stop of 4 would be appropriate.
67In Pre-Calculustoday we will
- Cover section 4.4 and 4.5
- Review/Discuss Homework from previous sections
68Chapter 4
- Section 4.4 Functions Defined by Powers and
Roots
694.4 Functions Defined by Powers and Roots
-
- f (x) xp/q, p/q in lowest terms
- if q is odd, the domain is all real numbers
- if q is even, the domain is all nonnegative real
numbers
Power and Root Functions A function f given by
f (x) xb, where b is a constant, is a power
function. If , for some integer n ? 2,
then f is a root function given by f (x)
x1/n, or equivalently, f (x)
704.4 Graphing Power Functions
- Example Graph f (x) xb, b .3, 1, and 1.7,
for - x ? 0.
- Solution The larger values of b cause the graph
of - f to increase faster.
714.4 Modeling Wing Size of a Bird
- Example Heavier birds have larger wings with
more surface - area. For some species of birds, this
relationship can be - modeled by S (x) .2x2/3, where x is the weight
of the bird in - kilograms and S is the surface area of the wings
in square - meters. Approximate S(.5) and interpret the
result. - Solution
- The wings of a bird that weighs .5 kilogram have
a surface - area of about .126 square meter.
724.4 Modeling the Length of a Birds Wing
- Example The table lists the weight W and the
- wingspan L for birds of a particular species.
- Use power regression to model the data with
- L aWb. Graph the data and the equation.
- (b) Approximate the wingspan for a bird weighing
3.2 kilograms.
W (in kilograms)
L (in meters)
734.4 Modeling the Length of a Birds Wing
- Solution
- (a) Let x be the weight W and y be the length L.
Enter the data, and then select power regression - (PwrReg), as shown in the following figures.
744.4 Modeling the Length of a Birds Wing
- The resulting equation and graph can be seen in
the figures below. - (b) If a bird weighs 3.2 kg, this model predicts
the wingspan to be
754.4 Graphs of Root Functions Even Roots
764.4 Graphs of Root Functions Odd Roots
774.4 Finding Domains of Root Functions
- Example Find the domain of each function.
- (a) (b)
- Solution
- 4x 12 must be greater than or equal to 0 since
the root, n 2, is even. - (b) Since the root, n 3, is odd, the domain of
g is all real numbers.
The domain of f is 3,?).
784.4 Transforming Graphs of Root Functions
- Example Explain how the graph of
- can be obtained from the graph of
- Solution
Shift left 3 units and stretch
vertically by a factor of 2.
794.4 Transforming Graphs of Root Functions
- Example Explain how the graph of
- can be obtained from the graph of
- Solution
Shift right 1 unit, stretch
vertically by a factor of 2, and reflect across
the x-axis.
804.4 Graphing Circles Using Root Functions
- The equation of a circle centered at the origin
with radius r is found by finding the distance
from the origin to a point (x,y) on the circle. - The circle is not a function, so imagine a
semicircle on top and another on the bottom.
814.4 Graphing Circles Using Root Functions
- Solve for y
- Since y2 y1, the bottom semicircle is a
reflection of the top semicircle.
824.4 Graphing a Circle
- Example Use a calculator in function mode to
- graph the circle
- Solution This graph can be obtained by graphing
- in the same
- window.
Technology Note Graphs may not connect when
using a non-decimal window.
834.5 Equations, Inequalities, and Applications
Involving Root Functions
- Note This property does not say that the two
- equations are equivalent. The new equation may
- have more solutions than the original.
- e.g.
Power Property If P and Q are algebraic
expressions, then every solution of the equation
P Q is also a solution of the equation Pn Qn,
for any positive integer n.
844.5 Solving Equations Involving Root Functions
- Isolate a term involving a root on one side of
the equation. - Raise both sides of the equation to a power that
will eliminate the radical or rational exponent. - Solve the resulting equation. (If a root is still
present after Step 2, repeat Steps 1 and 2.) - Check each proposed solution in the original
equation.
854.5 Solving an Equation Involving Square Roots
- Example Solve
- Analytic Solution
Isolate the radical.
Square both sides.
Write in standard form and solve.
864.5 Solving an Equation Involving Square Roots
- These solutions must be checked in the original
- equation.
874.5 Solving an Equation Involving Square Roots
- Graphical Solution The equation in the second
step - of the analytic solution has the same solution
set as - the original equation. Graph
- and solve y1 y2.
- The only solution is at x 2.
884.5 Solving an Equation Involving Cube Roots
894.5 Solving an Equation Involving Roots
(Squaring Twice)
Isolate radical.
Square both sides.
Isolate radical.
Square both sides.
Write in standard quadratic form and solve.
A check shows that 1 and 3 are solutions of the
original equation.
904.5 Solving Inequalities Involving Rational
Exponents
- Example Solve the inequality
- Solution The associated equation solution in
the - previous example was
- Let
Use the x-intercept method to solve this
inequality and determine the interval where the
graph lies below the x-axis. The solution is the
interval .
914.5 Application Solving a Cable Installation
Problem
- A company wishes to run a utility cable from
point A on the - shore to an installation at point B on the island
(see figure). - The island is 6 miles from shore. It costs 400
per mile to run - cable on land and 500 per mile underwater.
Assume that the - cable starts at point A and runs along the
shoreline, then - angles and runs underwater
- to the island. Let x represent
- the distance from C at which
- the underwater portion of the
- cable run begins, and the
- distance between A and C be
- 9 miles.
924.5 Application Solving a Cable Installation
Problem
- What are the possible values of x in this
problem? - Express the cost of laying the cable as a
function of x. - Find the total cost if three miles of cable are
on land. - Find the point at which the line should begin to
angle in order to minimize the total cost. What
is this total cost? - Solution
- The value of x must be real where
- Let k be the length underwater. Using the
Pythagorean theorem,
934.5 Application Solving a Cable Installation
Problem
- The cost of running cable is price ? miles. If
C is the total cost (in dollars) of laying cable
across land and underwater, then - If 3 miles of cable are on land, then 3 9 x,
giving - x 6.
944.5 Application Solving a Cable Installation
Problem
- Using the graphing calculator, find the minimum
value of y1 C(x) on the interval (0,9. - The minimum value of the function occurs when x
8. So 9 8 1 mile should be along land, and - miles underwater. The cost is