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Resonances

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Resonances decay by strong interactions (lifetimes about. 10-23 s) ... Since resonances have very short lifetimes, they can only ... – PowerPoint PPT presentation

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Title: Resonances


1
Resonances
  • - If cross section for muon pairs is
  • plotted one find the 1/s dependence
  • In the hadronic final state this trend
  • is broken by various strong peaks
  • Resonances short lived states with
  • fixed mass, and well defined quantum
  • numbers ? particles
  • -The exponential time dependence gives
  • the form of the resonance lineshape

r,w
J/Y
s (cm2)
1 10 100
2
  • Resonances decay by strong interactions
    (lifetimes about
  • 10-23 s)
  • If a ground state is a member of an isospin
    multiplet, then
  • resonant states will form a corresponing
    multiplet too
  • Since resonances have very short lifetimes, they
    can only
  • be detected through their decay products
  • p- p ?n X
  • A B

3
  • Invariant mass of the particle is measured via
    masses of its
  • decay products
  • A typical resonance peak
  • in KK- invariant mass
  • distribution

4
  • - The wave function describing a decaying state
    is
  • with ER resonance energy and t lifetime
  • - The Fourier transform gives
  • The amplitude as a function of E is then
  • K constant, ER central value of the energy of
    the state
  • But

5
  • Spin
  • Suppose the initial-state particles are
    unpolarised.
  • Total number of final spin substates available
    is
  • gf (2sc1)(2sd1)
  • Total number of initial spin substates gi
    (2sa1)(2sb1)
  • One has to average the transition probability
    over all possible
  • initial states, all equally probable, and sum
    over all final states
  • ? Multiply by factor gf /gi
  • All the so-called crossed reactions are
  • allowed as well, and described by the
  • same matrix-elements (but different
  • kinematic constraints)

6
  • The value of the peak cross-section smax can be
    found using
  • arguments from wave optics
  • With wavelenght of scattered/scattering
    particle in cms
  • Including spin multiplicity factors, one gets
    the Breit-Wigner
  • formula
  • sa and sb spin s of the incident and target
    particles
  • J spin of the resonant state

7
  • The resonant state c can decay in several modes.
  • Elastic channel c?ab (by which the resonance
    was formed)
  • If state is formed through channel i and decays
    through channel j
  • Mean value of the Breit-Wigner shape is the mass
    of the resonance
  • MER. G is the width of a resonance and is
    inverse mean lifetime of a particle at rest G
    1/t

To get cross-section for both formation and
decay, multiply Breit-Wigner by a factor (Gel/G)2
To get cross-section for both formation and
decay, multiply Breit-Wigner by a factor (Gi Gj
/G)2
8
  • Mean value of the Breit-Wigner shape is the mass
    of the resonance
  • MER. G is the width of a resonance and is
    inverse mean lifetime of a
  • particle at rest G 1/t

9
  • Internal quantum numbers of resonances are also
    derived
  • From their decay products
  • X0 ? p p-
  • And for X0 B 0 S C T 0 Q 0
    ? Y 0 and I3 0
  • To determine whether I 0, I 1 or I 2,
    searches for isospin
  • multiplets have to be done.
  • Example r0(769) and r0(1700) both decay to
    pp- pair and
  • have isospin partners r and r-
  • p? p ? p r?

p? p0
For X0, by measuring angular distribution of the
pp- pair, the relative orbital angular momentum
L can be determined ? JL P P2p(-1)L
(-1)L C (-1)L
10
Some excited states of pions Resonances
with B0 are meson resonances, and with B1
baryon resonances Many baryon resonances can
be produced in pion-nucleon scattering Forma
tion of a resonance R and its inclusive decay
into a nucleon N
11
Peaks in the observed total cross section of the
p?p reaction Corresponds to resonances formation
p? scattering on proton
12
All resonances produced in pion-nucleon
scattering have the same internal quantum
numbers as the initial state B 1 S C
T 0, and thus Y 1 and Q I3 1/2
Possible isospins are I ½ or I 3/2, since
for pion I 1 and for nucleon I ½ I ½ ?
N resonances (N0, N) I 3/2 ? D-resonances
(D-, D0, D, D) In the previous figure, the
peak at 1.2 GeV/c2 correspond to D0, D
resonances p p ? D ? p p p- p ?
D0 ? p- p
p0 n
13
  • Fits by the Breit-Wigner formula show that both
    D0 and D
  • have approximately same mass of 1232 MeV/c2 and
    width
  • 120 MeV/c2
  • Studies of angular distribution of decay
    products show that
  • I(JP) 3/2(3/2)
  • Remaining members of the multiplet are also
    observed
  • D-, D
  • There is no lighter state with these quantum
    numbers ? D is
  • a ground state, although a resonance

14
The Z0 resonance
The Z0 intermediate vector boson is responsible
for mediating the neutral weak current
interactions. MZ 91 GeV, G 2.5 GeV. The Z0,
can decay to hadrons via pairs, into charged
leptons ee-,mm-,tt- or into neutral lepton
pairs The total width is the sum of the partial
widths for each decay mode. The observed G gives
for the number of flavours
Z0

Nn 2.99 ? 0.01

15
Quark diagrams
  • Convenient way of showing strong interaction
    processes
  • Consider an example
  • D ? p p
  • The only 3-quark state consistent with D
    quantum number
  • is (uuu), while p (uud) and p (u )
  • Arrow pointing to the right particle,
  • to the left, anti-particle
  • Time flows from left to right

16
Allowed resonance formation process Formati
on and decay of D resonance in pp
scattering Hypothetical exotic resonance
Formation and decay of an exotic resonance Z in
Kp elastic scattering
17
Quantum numbers of such a particle Z are
exotic, moreover no resonance peaks in the
corresponding cross-section
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