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Linear Difference Equations

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If is the zero sequence, the equation is homogeneous; otherwise, it is nonhomogeneous. ... The Fibonacci sequence. Consider the difference equation ... – PowerPoint PPT presentation

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Title: Linear Difference Equations


1
Linear Difference Equations
  • We consider the vector space S of discrete time
    signals. A signal is a function defined only on
    the integers and is visualized as a sequence of
    numbers, say,
  • To add two signals in S, simply add the values at
    k. Thus,
  • If c is a scalar, then we define scalar
    multiplication in S by
  • In S, the zero vector is the signal which is zero
    for every k.

2
Linear difference equations defined for third
order or less
  • First order, where
  • Second order, where
  • Third order, where
  • Here, is unknown and is a known
    signal. If is the zero sequence, the
    equation is homogeneous otherwise, it is
    nonhomogeneous. Once, we have obtained ,
    it is called a solution of the difference
    equation.

3
Linear Independence in S
  • To simplify notation, we consider only three
    signals, but the concepts are easily generalized
    to n signals.
  • Three signals,
    are linearly independent when
  • Since k is arbitrary, it can be replaced by k1
    and k 2, so that
  • The coefficient matrix is called the Casorati
    matrix.

4
Example for linear independence
  • Example. Verify that
    are linearly independent signals. We put k
    equal 0 in the Casorati matrix
  • Since the Casorati matrix is invertible for k
    0, it follows that
  • In general, if the Casorati matrix is not
    invertible, the associated signals may or may not
    be independent. However, if the Casorati matrix
    is not invertible, and the associated signals are
    solutions of the same homogeneous difference
    equation, then the solutions are linearly
    dependent (see Study Guide).

5
S is infinite dimensional
  • Consider the following signals
  • It is readily verified that any finite set of
    these signals is linearly independent.
    Therefore, S is infinite dimensional.

k0
6
A linear mapping on the space of signals
  • Let a and b be real numbers. Define the mapping
    TS?S by
  • It is easily shown (Theoretical Exercise) that T
    is a linear map.
  • The solutions of the homogeneous equation
  • form the kernel of T. Therefore, the
    solutions form a subspace H of S.
  • Theorem. The dimension of H is 2.
  • Proof See next slide.

7
The dimension of H from previous slide is two
  • For the second order difference equation, we may
    specify two initial values
    These initial values may be arbitrarily chosen
    from Once these values are fixed, there
    is a unique solution of the difference
    equation determined (Theorem 16 from the text,
    and also see next slide)
  • Define the mapping by
    That is, map a solution
    to its values at k 0 and k 1. It is easily
    shown that the mapping F is linear. By Theorem
    16 from the text, it follows that F is
    one-to-one. In other words, F is an isomorphism.
  • Since the space of initial values, is
    2-dimensional, it follows that H is also
    2-dimensional.

8
Existence and Uniqueness for Difference Equations
  • Example. Given the Fibonacci problem

    generate the values of the solution for k
    2, 3,
  • Simply rewrite the difference equation
    as Now, we plug in the
    initial conditions to obtain Next,
    use the values for to obtain
    and so on.
  • Likewise, values of with k negative could
    also be generated.

9
Solving a homogenous equationan example
  • Example. Consider the second order equation
  • Assume a solution of the form Upon
    substituting this signal into the equation, we
    have
  • The equation is called the
    auxiliary equation. Its roots are r 1 and r
    1. Therefore, two solutions are It is easy
    to verify that these two solutions are linearly
    independent in S. Since the solution space has
    dimension 2, these solutions span the space, and
    all solutions are linear combinations of these
    two solutions.

10
Solving a nonhomogenous equationan example
  • Example. Consider the second order equation
  • We guess that might work. Indeed, we
    have so that
    is a particular solution of the
    equation.
  • As in Section 1.5 of the text, the general
    solution of the equation is the sum of the
    particular solution plus the general solution of
    the homogeneous equation
    If two values of are
    known, then can be determined.
    For example, if
    then

11
The Fibonacci sequence
  • Consider the difference equation
  • The general solution to this homogeneous equation
    is
  • Upon applying the initial conditions, we obtain
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