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NE 455555 Nuclear Reactor Analysis II

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Or, neutrons can scatter downward at most one group at a time. ... At each step in the scheme, we only need to solve a one-group diffusion equation. ... – PowerPoint PPT presentation

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Title: NE 455555 Nuclear Reactor Analysis II


1
NE 455/555Nuclear Reactor Analysis II
  • Lecture 5Structure of , power
    iteration

2
Remarks about the derivation of the multigroup
equations
  • Remark 1
  • We can use our multigroup derivation procedure
    (Lecture 4) to perform a group collapse.
  • Start from the multigroup equations with a large
    number (G1) groups.
  • Result is a similar system with fewer (G2)
    groups.
  • Need a spectral function defined on the
    fine group structure.
  • Trade-off loss of accuracy, but less expensive
    computationally.
  • Remark 2
  • Our multigroup derivation will be exact if
  • and
    are constants for E and
    E in each energy group, OR

3
What is the structure of our scattering transfer
matrix?
  • In scattering processes, high-energy neutrons
    lose energy and thermal neutrons gain or lose
    energy.
  • If we have only one thermal energy group, then
    sincethen

Upscattering
Downscattering
4
It is also possible to have direct coupling of
our energy groups.
  • Or, neutrons can scatter downward at most one
    group at a time.

5
We now assume that there is no upscatter.
  • We can define the removal cross-section
  • Then, with no upscatter, our multigroup equations
    become
  • These are the multigroup diffusion equations with
    fission and downscattering (but no upscattering).

6
How do we solve these equations numerically?
  • If we write out the steady-state, fixed source
    multigroup equations we getwhere

7
This suggests the following iteration scheme
  • and
  • The boundary conditions are vacuum

8
When do we stop iterating?
  • A couple of remarks are in order
  • At each step in the scheme, we only need to solve
    a one-group diffusion equation.
  • In one-dimensional problems, each 1-group
    diffusion problem can be solved directly
    (Gaussian elimination).
  • 2- or 3-d problems require an iterative solver in
    each group. These are the inner iterations.
  • A single sweep through all the groups is called
    an outer iteration.

where typically e 10-5
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