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ENGR 112

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Engineering economy adjusts for the time value of money to balance current and ... Voice Recognition for Construction Inspection ... – PowerPoint PPT presentation

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Title: ENGR 112


1
ENGR 112
  • Economic Analysis II

2
Engineering Economic Analysis
  • Time Value of Money
  • 1 today is more valuable than 1 a year later
  • Engineering economy adjusts for the time value of
    money to balance current and future revenues and
    cost

0
5
10
Years
3
Recap
  • Capital vs. Interest
  • Types of Interest
  • Simple vs. Compound
  • Cash Flow Diagrams
  • Calculate a Future given a Principal and vice
    versa
  • P/F and F/P ? F P(1 i)N
  • Frequency of Compounding
  • Quarterly, monthly, daily
  • n m x N ? F P(1 i/m)mN

4
Annuity
  • A series of uniform cash flows
  • Begins at end of period one
  • Continues through the end of period N
  • Annuity given a Principal (A/P)
  • Annuity given a Future (A/F)

5
IDDI Company Case
  • The I Dint Do It (IDDI) Company plans to borrow
    150,000 from the Trust Me Bank (TMB) at an
    interest rate of 9 per year, compounded
    quarterly, in order to finance the installation
    of pollution reduction equipment. The TMB will
    agree to the loan only if IDDI makes quarterly
    payments during the next 4 years. Use the A/P
    formula to determine the quarterly payment.

P 150,000
i 9 per year, compounded quarterly
m 4
N 4
6
IDDI Company Case Solution
Quarterly compounding ? i/4 0.09/4 0.0225
7
IDDI Company Cash Flow Diagram
8
In Class Problem
  • What is the total amount of interest paid over
    the 4 years of the loan period?

9
Analyzing a Project
  • Present Worth
  • Internal Rate of Return (IRR)

10
Analyzing a Project
  • Present Worth
  • Value at time zero (e.g., today) that is
    equivalent to the cash flow series of a proposed
    project or alternative
  • Easy to understand and use
  • Matches our intuitive understanding of money
  • PW gt 0 ? Desired Value!!
  • PW 0 ? Economic indifference
  • PW lt 0 ? Should be avoided, if possible

11
Present Worth
  • Useful when
  • Setting a price to buy or sell a project
  • Evaluating an investment or project when the
    price to invest or the first cost is given
  • Calculating and equivalent value for an irregular
    series of cash flows

12
Present Worth
  • Assumptions
  • 1. Cash flows occur at the end of the period,
    except for first costs and pre-payments
  • i.e., insurance, leases
  • 2. Cash flows are known, certain values
  • 3. The interest rate (i) is given
  • 4. The problems horizon (N) is given

13
Voice Recognition for Construction Inspection
  • A large construction job will take 4 years to
    complete. The costs of the many required
    inspections can be reduced by purchasing a voice
    recognition system to act as the front end for
    a word processor. Then inspectors can be trained
    to record their comments and revise the written
    output of an automated form.
  • The firm interest rate is 12. What is the PW
    of the cash flows for the voice recognition
    system? The first cost for purchase and training
    is 100K. Savings are estimated at 30K, 40K,
    65K, and 35K for the 4 years of construction.

14
VR Project Cash Flow Diagram
15
VR Project Solution
PW -100K 30K(P/F,0.12,1) 40K(P/F,0.12,2)
65K(P/F,0.12,3) 35K(P/F,0.12,4)
PW 27,182
16
In Class Problem
  • Find the present worth of the 4 different years
    using formulas in Excel.
  • Find the present worth of the 4 different years
    using Excel financial functions.

17
Analyzing a Project
  • Internal Rate of Return (IRR)
  • Interest rate that makes the PW equal zero
  • Firms, government agencies and individuals must
    compute the cost of financial projects
  • Solution
  • Calculate the IRR for a project or for a
    financial source
  • Then, compare the resulting IRR with an interest
    rate for the time value of money

18
Golden Valley Manufacturing
  • By replacing its assembly line conveyor with an
    asynchronous conveyor, Golden Valley
    Manufacturing will save 50,000 per year in
    rework, inspection, and labor costs. The
    asynchronous conveyor will cost 275,000, and its
    life is 15 years (when its salvage value equals
    0). If Golden Valley uses a 10 interest rate,
    should the asynchronous conveyor be installed?

19
GVM Cash Flow Diagram
20
GVM Solution
  • PW 0 -275K 50K(P/A, IRR, 15)
  • (P/A, IRR, 15) 275K / 50K 5.500
  • From tables
  • (P/A, 0.16, 15) 5.575
  • (P/A, IRR, 15) 5.500
  • (P/A, 0.17, 15) 5.324



21
In Class Problem 4
  • Use Excel to find the value of IRR of return
    using interpolation

22
GVM Solution
16.30 gt 10 GOOD INVESTMENT!!
23
In Class Problem 5
  • Use Excel to find IRR

24
Internal Rate of Return
PW
Present Worth PW
0
-PW
i
Interest rate i
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