Title: Lecture on Multi Access Communication
1Lecture on Multi Access Communication
- For many applications (e.g.,satellite, radio
broadcast, Ethernet), users share the same
channel. The received signal is the sum of the
transmitted signal from the source that is
intended, the transmitted signals from several
other sources that are not intended, and noises. - Data Link Control Layers job is to construct a
reliable virtual bit pipe. To accomplish that
job, we need another layer between the DLC Layer
and the Physical Layer. We call this Medium
Access Control (MAC) Layer.
DLC
Layer 2
MAC
Physical
Layer 1
2Queuing Problem in Multiple Access
- Each node has a queue of packets to be
transmitted and channel is a common and shared
resource (i.e., server). - In the above model,
- Information is distributed.
- The server does not know which nodes contain
packets. - Nodes are unaware of packets at other nodes.
Node 1
Node i1
Channel
Node 2
Node i2
. . .
. . .
Node i
Node m
3Extreme Solutions
- We may consider the following two extreme
solutions. The actual solution will be somewhere
in between. - Free for all multiple access.
- Nodes send packets whenever they need
to, hoping for no interference or collision. - An important question is how and when to
retransmit when collisions occur. - Scheduled (dynamically or not) multiple access.
- A certain schedule is given for packet
transmission in order to avoid a collision. An
important question here is how to fix the
scheduling. We must also consider how to transmit
to the nodes the information about the schedule.
4Example of Multiple Access Media
Satellite
- 1. Satellite Channel
- Separate antennas are needed for different
geographical areas. We may consider for one area,
TDM can be used while FDM can be used for others.
However, this is very inefficient use of the
expensive channel. We can reduce the delay and
increase utilization by sharing the medium on a
per demand basis. We, however, need a mechanism
of mediating the potential collisions.
Area 1
Area k
Area 1
Ground Stations
5- 2. Multi drop telephone lines.
- This is also known as party lines.
- 3.Multi tapped bus.
- Each node can receive signals sent by other
nodes. Simultaneous transmissions causes a
collision.
Primary
Secondaries
6- 4. Packet radio network
- Each node is in the reception range of some sub
network of nodes. For example, the nodes marked
with can transmit simultaneously. A mechanism
to mediate collisions is complex.
7Example of Multiple Access System Slotted Aloha
Network
- Basic Assumptions
- Each packet requires one time unit or slot for
transmission. - There are m nodes each generating packets
according to a Poisson process with rate ?/m. - Over the defined medium, there are only two
possibilities collision or perfect reception. - There is a mechanism for immediate feedback.
Immediately after any time slot, every node
learns the results of the previous time slot
(0,1,e) where 0 implies no packet was
transmitted, 1 implies one packet was
transmitted, and e implies there was a collision. - Each packet involved in a collision will be
retransmitted later until it is received
correctly. - 6. A node with packets for retransmission is said
to be back logged. One of the following two is
true - If a packet is waiting for transmission or
collided with another packet(s), all new arrivals
are lost. - There exists an infinite set of nodes and new
arrivals arrive a new node each time.
slot
t
8Slotted Aloha
- Each node sends its packet in the first slot
after the packet arrival. - Slotted Aloha will potentially reduce the delay.
- Slotted Aloha has a significant of collision
risk. - TDM has on the average m/2 slots of delay.
- When a collision occurs, the nodes involved will
know at the end of slot, and become backlogged. - Those collided nodes cannot re-send packets
immediately since it creates a certain
collision. - It is required to wait for a random number of
slots and retransmit.
9Analysis
- Assume the infinite node case, i.e., 6b.
- Consider the total number of packets transmitted
in the next time slot. - The combine new arrival is Poisson with rate ?.
- There are also retransmissions from backlogged
nodes. - Assume that the total number of packets to be
transmitted in the next time slot to be Poisson
with rate G (gt?). - The transmission is successful only if there is
exactly one packet transmitted in a time - slot, and therefore,
- because the transmission in the next time slot is
Poisson with rate G, i.e.,
10- At equilibrium,
- Arrival rate departure rate
- Maximum
throughout 1/e ? 0.368 - Problem with this approach is that G is a
function of the number of backlogged nodes, which
is not reflected in this model.
11More Precise Model
- Assume the no buffering case of 6a.
- Define
- qr probability that a backlogged node
retransmit in a time slot - X number of slots from collision until a
backlogged node retransmits - n number of backlogged nodes
- m total number of nodes generating packets
- m-n nodes are backlogged, and they will transmit
any fresh arrival takes place before the
beginning of the next time slot.
12 - Let the probability that an unbacklogged node has
a packet be qa. -
-
- Since n is the number of backlogged nodes of the
system (i.e., the state), from one to next time
slot, n is increased by the number of new
arrivals and is decreased by at most one if one
packet is transmitted successfully.
13- We can solve the above equations for pn where pn
is the steady state probability of being in state
n.
0
1
2
3
14- We want to determine whether or not the system is
stable. - (The term stability will be defined later.)
- We want qr to be large to avoid unnecessary
delays. - If nqr gtgt1, then collision will occur in every
slot and the system remains heavily - backlogged.
- Determining qr involves tradeoffs.
- Define
- Dn expected changes in the number of backlogged
node in one slot - Psucc expected number of successful
transmissions in one slot - Then, since
(m-n)qa is the expected number of new arrivals in
one time slot. Therefore, Dn can be viewed as
the expected drift of the state from n in one
time slot.
15- Let G(n) be the packet transmission attempt rate,
i.e., at state n, the sum of new arrival rate and
the retransmission rate from the backlogged
nodes. - G(n) expected number of attempted
transmissions in a time slot - when the system is
in state n. - (m-n)qa nqr ()
- Using () and () together, Psucc G(n)e-G(n).
- In the above, we used the fact that
for small x. - Then, Probability of idle slot .
16- One desired stable state, one unstable state, and
one undesired stable state. - Maximum Psucc maximum departure rate 1/e
17- If we use assumption 6b instead,
- One desired stable state, and one undesired
stable state.
18Stability Problem with Slotted Aloha
- If qr is increased, retransmission delay is
reduced. - Attempt rate G(n)(m-n)qa nqr increases with n
faster for a larger qr . - G(n) scale is contracted.
- Fewer packets are required to exceed unstable
equilibrium. - If qr is decreased, retransmission delay
increases. - ?G(n) scale is expanded.
- Only one stable point remains.
- Backlog is a large fraction of m.
- Large delay
- Many packets may be discarded.
19Definitions
- Definition
- A multi access system is stable for a given
arrival rate if the average delay per packet is
finite. - Definition
- Maximum throughput is the least upper bound of
arrival rates for which system is stable. - Slotted Aloha is unstable for any rate greater
than zero,. Therefore, the maximum throughput of
Slotted Aloha is zero.
20Stabilizing Slotted Aloha Pseudo-Bayesian
Algorithm
- New arrivals are considered backlogged upon
arrival. If there are n backlogged packets, the
attempt rate is . - Probability of successful transmission
- Algorithm keeps as estimate of backlog n in
the beginning of each slot. - Backlogged packets are then transmitted with
probability - This makes Gnqr to be near 1.
- Updating
- estimated backlog in beginning of kth slot.
21Note
- Adding ? to previous backlog is due to new
arrivals. - max is to ensure the estimate is never less
than the number of new arrivals. - For successful transmission 1 is subtracted from
previous backlog due to successful departure. - Subtract 1 for idle to avoid too many idle
slots. - Add (e-2)-1 on collision to avoid too many
collisions. - For large , if n, each of n backlogged
nodes retransmits with probability -
- By Poisson approximation
22Delay Analysis
- Define Wi be the delay from the arrival of ith
packet until the beginning of ith successful
transmission. In FIFO, Wi is the queuing delay of
ith arrival. - Average of Wi over all i is the average delay.
- Ri residual time to the beginning of next slot.
- ni number of backlogged packets just before ith
arrival. - tj time interval from end of (j-1) successful
transmission to end of jth success. - yi time until beginning of next successful
transmission after those ni transmissions. - For each interval tj, backlog is at least two
(i.e., ni ith arrival) - Thus each slot is successful with probability
1/e. - (Assume that Psucc 1/e for n ? 2 and Psucc 1
for n1)
23 24(No Transcript)
25Splitting Algorithms
- Most often collision is between two users.
- It is advantageous to inhibit new arrivals from
transmission until a collision is resolved. - To resolve a collision, each node involved in
the collision would retransmit in the next - slot with probability 1/2.
- Collision is resolved in
- Two slots with probability 1/2.
- Three slots with probability 1/4.
- Four slots with probability 1/8.
- i slot with probability 2-(i-1).
- Expected number of slots for sending two packets
equals 3 - throughout for this period 2/3.
- In essence, the set of colliding nodes are split
into two sets those that transmit - in the next slot and those that do not.
- Splitting Algorithms
26Tree Algorithm
- Splitting algorithm has a tree structure when
collision occurs. - All nodes not involved in collision go into
waiting mode. - The first subnet transmits in the next slot.
- If this transmission is successful or idle, the
second subject transmits in the following slot. - If collision occurs in the retransmission, then
the subset is split and so on.
LRRL success
success LRRR
idle LRL
- Mechanics
- A counter is set to 0 or 1 at the beginning of a
collision for each packet. - If it is 0, packet is transmitted.
- If it is non zero, it is incremented by 1 for
each collision, and decreased by 1 for each
success or idle.
collision
LRR
success
collision
LL
LR
idle
collision
R
L
collision
27Issue
- What do we do with packets that arrived while
collision was being resolved? - A Collision Resolution Period (CRP) starts as
soon as one ends. If many packets arrived in the
meantime, they will collide immediately and have
to be split and so on. - Solution At the end of a CRP, split the set of
nodes with new arrivals into j subjects with j
such that the expected number of packets in each
subsets is slightly larger than 1. - These new packets are now transmitted via a tree
structure. - Maximum throughput for optimized j 0.43 packets
per slot.
28Improvement for Tree Algorithm
- The splitting at node A creates two subsets one
of which is empty (i.e, left subset). - This causes another collision in the next time
slot (at right subset). - 1st Improvement
- Omit transmission of the 2nd subset after an idle
time slot, preceded by a collision. Split the 2nd
subset before transmission. Throughput 0.46
packets per slot
idle
collision
success
collision
collision
node A
idle
collision
292nd Improvement
- Suppose one collision follows another. Let
- x number of packets in the first collision
- xr number of packets in the right subset
- xl number of packets in the left subset
- Assume x xr xl is Poisson.
2nd Improvement When there is a collision,
regard the 2nd subset as new arrivals that have
not been involved in collision previously.
30Unslotted Aloha
- There is no slot for timing.
- Packets are transmitted as they arrive.
- Collided packets are re-transmitted a random
time later. - Assume infinite number of nodes (6b Assumption).
- Let ? time until attempted retransmission.
- Suppose ? is exponential with probability density
function xe-?x where x is node retransmission
attempt rate. - Let ? overall Poisson arrival rate.
- If n nodes are backlogged, there is also an
arrival of rate nx from backlogged nodes - which we assume to be Poisson.
- Total attempted transmission is Poisson with rate
G(n) ? nx.
31Let ?i duration of interval between ith and
(i1)st transmissions. The ith transmission is
successful if ti-1 gt 1 and ti gt 1.
32- Maximum throughput 1/2e at G1/2.
- Pure Aloha (i.e., Unslotted Aloha) is unstable.
33Carrier Sensing Multi Access (CSMA)
- In some multi-access systems, a node can hear
when other nodes are transmitting. - Detection is possible after a propagating and
detection delay which is small compared to - packet transmission time.
- Detection delay is the time it takes for the
node to determine if other nodes are
transmitting. - ? propagation and detection delay in seconds
- C bits per second rate in the channel
- L average number of bits per packet
- Feedback is not instantaneous, but it is with a
maximum delay of ß in packet transmission - unit.
- If a slot is idle, then the slot terminates
after ß time units and a new slot begins. - ? ? ?C/L
- Slots are not of equal length.
- Idle slots have length ?.
- Other slots have length 1.
34CSMA Slotted Aloha
- Idle slot duration ?
- If a packet arrives at a node while a
transmission is in progress in the channel (by
any node), the packet is regarded as backlogged. - Backlogged packets begin transmission with
probability qr after each subsequent idle slot. - Non Persistent CSMA Packets arriving during
idle slots are transmitted in the next slot - Persistent CSMA All arrivals during a busy
period transmit at the end of that slot. - P-Persistent CSMA Collided packets and new
packets use different probabilities for
transmission.
35Analysis of CSMA Slotted Aloha
- Each busy slot (success or collision) is
followed by an idle slot. - Node can only transmit after an idle slot.
- We want to evaluate the maximum throughput such
that the drift is negative. - Drift ? Dn
- expected number of arrivals
expected number of departures - E(number of arrivals) Psucc
- Define
- State number of backlogged packets
- State transition time end of idle slot
- We want to evaluate the drift at the state
transition times. - Time between state transitions
- ? if the slot is idle
-
- 1 ? if a busy slot is followed by idle
slot
36- Suppose the system is in state n.
Expected number of departures between state
transitions from state n where
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38- CSMA Slotted Aloha is unstable.
- It can be stabilized for all rates
. - Stability is not as a severe problem as in
ordinary Aloha - Expected idle time a backlogged node must wait
before transmission is ?/qr as oppose to 1/qr
for ordinary aloha. - For small ? ,qr can be very small without
causing much delay. - n must very large before backlog appears.
39Satellite Reservation Systems
Amv
- Round trip delay 2?
- Duration of reservation slot v
- Reservation period A mv
- 2? is many times larger than A.
- TDM is used to make reservations.
- Duration of data packet has general distribution
with mean and second moment
reservation interval
Data intervals
arrival
Wait for reservation
Wait for assigned data slot
40Delay Analysis of Satellite Reservation System
- Consider the ith packet arriving into system.
- The ith packet must wait for
- residual time Ri (for the transmission or
reservation currently in progress), - transmission time of Ni packets already in
queue for which reservations have been made - two reservation periods.
41- Satellite reservation system is an M/G/1 queue
with vacation where reservations correspond to
vacations.
42- As v ? 0, the same queuing delay as M/G/1.
- W is finite for ? lt1.
- Every packet must be delayed by at lest 2? (gtgtA)
in order for the reservations to be made. - We need W gt 2?. ? This formula is only valid
for ? ? 1. - NoteThe use of variable frame size is
undesirable. - If the frame length is variable, errors made
during a reservation period requires
resynchronization on the next reservation period.
This is not easy. - Busy nodes can lock out less frequent nodes.
- ? Fixed frame length should be used.
- Since all nodes are aware of all reservations,
any queuing discipline can be used as long as - a packet is sent whenever the queue (which is
common) is not empty.
43Approximate Analysis of Delay
- Consider the following scheme
- A fraction ? of bandwidth is set aside for making
reservations. - TDM is used within this bandwidth.
- Each node gets one reservation slot in each round
trip delay which is 2?.
44- The arrival process of packets (with
reservations) to the common queue is
approximately - Poisson.
- Number of arrivals in different reservation
slots are independent and have Poisson - distribution.
- A packet in common queue has the service time
- Where is the service time with full
bandwidth. - The common queue is M/G/1 with
1-r
r
frame
45- Assume
- The total queuing delay
- For small ?, large and needless delay for making
reservation takes place. - To reduce the number of data slots wasted in
each frame, use an unscheduled contention - mode. If a packet gets through before the
reservation time, cancel its reservation.
46Local Area networks Ethernet
nodes
- Model
- Propagation delay is very small.
- Nodes are connected to a common cable.
- When one node transmits all other nodes (which
are silent) can hear that transmission. - It is possible for a node to listen while
transmitting. - If two nodes start transmit almost
simultaneously, they will shortly detect a
collision and - stop transmitting (CSMA/CD).
- If one node starts transmission and during the
propagation delay and no other node starts - transmission, then no other node will start
transmission and the node transmitting is
guaranteed the transmission without collision.
Ethernet cable
47Slotted CSMA/CD
- Visualize Ethernet in terms of slots and
mini-slots. - ? Slots have duration of 1.
- ? Mini-slots have duration of ?.
- ? ? is the maximum propagation delay time in
slot unit. - Nodes are synchronized into mini-slots.
- If only one node starts transmitting, the other
nodes can hear and will not transmit until - the transmitting node has finished the
transmission. - If two nodes or more start transmission, they
will detect a collision by the end of the - mini-slot and both will stop transmission.
- Mini-slots are used in a contention mode and
when a successful transmission occurs, - the transmitting node reserves the channel
for the slot for the completion of the packet.
48Analysis
- Assumptions
- Each backlogged node will transmit with
probability qr after an idle mini-slot. - n number of backlogged node.
- Number of nodes transmitting after an idle slot
is Poisson with parameter G(n) ?? nqr - Consider state transitions after each idle
mini-slot. - No transmission idle slot ends after ? .
- One transmission next idle slot ends after 1?
. - More than one transmission next slot ends
after 2?.
idle
idle
?
?
State transition
Packet transmission
idle
idle
1
?
?
State transition
idle
idle
idle
?
?
?
State transition
State transition
49 50- ? is usually very small in LAN.
- It is very difficult to synchronize all nodes on
short mini-slots - Unslotted CSMA/CD makes more sense.
51Token Ring
1
nodes
9
2
Interface units
3
8
4
7
5
6
52- A collection of ring interfaces are connected in
a ring topology. - Nodes are connected to the ring through the
interfaces. Token ring is more like a collection
of point-to-point links. - There is uni-directional transmission around the
ring. - Each bit arriving at an interface is copied into
a one-bit buffer and then copied out into the
ring again. - The arrived bit can be inspected and modified
before being written out. - There is a one-bit delay at each interface.
53Model
- A special bit pattern called token circulates
around the ring whenever all nodes are idle. - Token can be a flag indicating the end of
packets, e.g., 01111110. (We need bit stuffing.) - A node that does not have any packet to transmit
simply passes the token to the next - node with one bit delay.
- When a node wants to transmit, it seizes the
token and inverts the last bit of the token - and transmits. The token now becomes
01111111 (i.e., busy token). After this busy
token, the packet follows. - Since there is only one token, the channel
access problem is resolved. - Ring interface has two modes
- Listen
- Transmit
- If the packet length is longer than the round
trip delay, then when the busy token bits - propagated around the ring, they are removed
from the ring. - IEEE 802.5 Standard 24 bit token, 4 or 10 Mbps
54Notes
- Ring is susceptible to failures
- Ring breaks down if cable or any interface
breaks down. - Use a star configuration.
- Nodes can be by passed or added from the central
site
55Delay Analysis
- Assumptions
- This is called the exhaustive multi user
reservation system.
56- If each node can only transmit one packet at a
time, then, - This is called the partially gated multi user
reservation system.
57Fiber Distributed Data Interface(FDDI)
2 fiber rings
58- Defined by American National Standard Institute
(ANSI) - Dual ring is constructed on optical fibers.
- Transmission rate 100Mbps.
- Uses 4 bits to 5 bits encoding.
- A group of 4 bits is encoded into a character
which is 5 bits long. - 16 characters represent 4 bits of data each.
- Other characters are special communication or
control characters. - 5-bit long characters contain at most 2
successive 0s. - To provide guaranteed service for high priority
traffic (e.g., digitalized speech, video), - we need to impose constraints on traffic.
- Question How much of high priority traffic can
each node send per received token?
59Model
- There are m nodes labeled as 0,1,2,,m-1.
- ?i for i 0,1,2,, m-1, is the amount of time
node i can send high priority traffic, including
delay to reach the next node. - If a token is received at time t by node i, and
node i sends ?i high priority traffic, and token
reaches node i1 at t ?i. - When the ring is initialized, there is a
parameter ?, called target token rotation time. - ? is used by nodes in deciding when to send low
priority traffic. - ? is the upper bound on the time average
inter-token arrival time.
60Distributed Queue Dual Bus (DQDB)
bus A
- Standardized as IEEE 802.6
- There are two buses running.
- Uses 53 byte long ATM frames.
- Frames contain two special bits.
- Busy bit B
- Request bit R
- B 1 if frame is busy.
- B 0 if frame is idle.
- Slots are used.
- Left most node on bus A generates slots for
transmission on bus A. - Right most node on bus B generates slots for
transmission on bus B.
nodes
bus B
61Packet Radio Networks
- This is a multiple access network where not all
nodes can hear transmissions of other nodes. - Network topology is represented by a graph
containing nodes and links. - Nodes are the sources and destinations of
packets. - Links are ordered pair of nodes (i, j) indicating
transmission from i can be heard at j. - Packets from i will be correctly received by j if
- There is a link between i and j.
- j or js neighbors are not transmitting.
- In the above diagram, if nodes 2 and 3 are
transmitting simultaneously, nodes 1 and 5 will
receive correctly, but node 6 will not. - More links does not necessarily imply greater
throughput.
62- Definition Collision Free Set is a set of links
that can carry packet simultaneously - without collision at the end of the link.
- Example) In the previous diagram, (1,2), (4,5),
(4,6) and (2,1),(5,3),(5,4) are collision free
sets. - Definition Collision Free Vector (CFV) is a
vector of 0s and 1s where the ith component is
1 iff the ith link is in the collision free set. - (1,2) (2,1) (2,6) (3,5) (3,6) (4,5) (4,6) (5,3)
(5,4) (6,2) (6,3) (6,4) - 1 0 0 1 1 0
0 0 0 0 0 0 - 1 0 0 0 0 1
1 0 0 0 0 0 - 1 0 0 0 0 0
0 1 1 0 0 0 - Once a collection of the collision free sets are
known, we can assign a time slot for each set and
cycle through like TDM. In the ith slot of TDM,
all links in the ith collision free set can carry
packets.
63- f is a convex combination of CFVs.
- Any convex combination can be achieved by TDM.
- Any link utilization achievable by other
allocation algorithms (e.g., collision resolution
algorithms) can be achieved by TDM. - TDM has an issue of long delay.
- A more difficult problem with TDM is for
dynamic networks (i.e., one with changing
topology like mobile networks). - FDM can be used in stead of TDM.
64Collision Resolution (Aloha)
- When an unbacklogged node receives a packet to
transmit (from outside or other nodes), - it sends the packets in the next slot.
- If no acknowledgement is received within a time
out period, the node is backlogged and - will retransmit after a random time.
- Consider heavy loading
65- We can get through from qij.
- In design, we have a set of desired throughputs
and want to find qij. - Suppose fs are the desired throughputs.
- Algorithm for design