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Empirical Examples of the Central Limit Theorem

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... random variables with the same characteristic function are distributed the same. ... Then, for any r 0 ... Given this we can compute ... – PowerPoint PPT presentation

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Title: Empirical Examples of the Central Limit Theorem


1
Empirical Examples of the Central Limit Theorem
  • Lecture XVI

2
Back to Asymptotic Normality
  • The characteristic function of a random variable
    X is defined as
  • Note that this definition parallels the
    definition of the moment-generating function

3
  • Like the moment-generating function there is a
    one-to-one correspondence between the
    characteristic function and the distribution of
    random variable.
  • Two random variables with the same characteristic
    function are distributed the same.

4
  • The characteristic function of the uniform
    distribution function of the uniform distribution
    function is
  • The characteristic function of the Normal
    distribution function is

5
  • The Gamma distribution function
  • which implies the characteristic function

6
  • Taking a Taylor series expansion of around the
    point t 0 yields

7
  • To work with this expression we note that
  • For any random variable X, and

8
  • Putting these two results into the second-order
    Taylor series expansion

9
  • Thus

10
Wrapping Up Loose Ends.
  • Application of Holders Inequality.
  • Holders Inequality
  • Example 4.7.1 If X and Y have means mX, mY and
    variances sX2, sY2, respectively, we can apply
    the Cauchy-Schwartz Inequality (Holders
    inequality with pq1/2) to get

11
  • Squaring both sides and substituting for
    variances and covariances yields
  • Which implies that the absolute value of the
    correlation coefficient is less than one.

12
Application of Chebychevs Inequality
  • Chebychevs Inequality Let X be a random
    variable and let g(x) be a nonnegative function.
    Then, for any rgt0

13
  • Example 4.7.3 The most widespread use of
    Chebychevs Inequality involves means and
    variances. Let g(x)(x-m)2/s2, where mE X
    and s2V (X ). Let rt2.

14
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15
  • Letting t2, this becomes
  • However, this inequality may not say much, since
    for the normal distribution

16
  • Casella and Berger offer a proof of the Central
    Limit Theorem (Theorem 5.3.3) based on the moment
    generating function instead of the characteristic
    function. However, they note that the proof
    using the characteristic function is a stronger
    result.

17
Normal Approximation of the Binomial
  • Starting from the Binomial distribution function

18
  • First, assume that n10 and p.5. The
    probability of r ? 3 is
  • Note that this distribution has a mean of 5 and a
    variance of 2.5. Given this we can compute

19
  • Integrating the standard normal distribution
    function from negative infinity to 1.265 yields

20
  • Expanding the sample size to 20 and examining the
    probability that r ? 6 yields
  • This time the mean of the distribution is 10 and
    the variance is 5. The resulting z-1.7889.
    PZ.0368.

21
  • As the sample size declines the binomial
    probability approaches the normal probability.
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