DC Circuits Lab - PowerPoint PPT Presentation

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DC Circuits Lab

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Battery or Lab power supply' is an example. DC voltage is supplied across ... Since this 'node' is at GND (OV) this node. must be 1.5Volts higher. 1.5V .5 O. 0V ... – PowerPoint PPT presentation

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Title: DC Circuits Lab


1
DC Circuits Lab
  • ECE 002
  • Professor Ahmadi

2
Outline
  • Basic Components of a Circuit
  • Series Circuit
  • Parallel Circuit
  • Ohms Law
  • Lab Overview

3
Basic Circuit Components
We represent real electrical components with
symbols
A Battery
can be represented with this symbol
called a DC voltage source
  • A DC Voltage Source
  • Provides Power for our circuit
  • Battery or Lab power supply is an example
  • DC voltage is supplied across the two terminals
  • Its voltage is VOLTS (V)

4
Basic Circuit Components
We represent real electrical components with
symbols
can be represented with this symbol
called a resistor
5
Basic Circuit Components
We represent real electrical components with
symbols
The Earth
can be represented with this symbol
called the ground symbol
6
Building a Circuit
  • We wish to power our flashlights light bulb
  • We need a battery
  • We need to attach the light bulb to the battery
  • We use wires to connect the light bulb to the
    battery

Insteadlet's represent the real components with
their symbols
7
Building a Circuit
creating a schematic
  • Replace the battery with a DC Voltage Source
    symbol
  • Replace the light bulb with a Resistor symbol

.5 O
  • Mark the symbols values (V, R, etc.)

Since this node is at GND (OV) this node
must be 1.5Volts higher
  • Add the Ground reference

0V
Insteadlet's represent the real components with
their symbols
8
Analyzing the Circuitusing Ohms Law
  • When we attach the resistor to the DC voltage
    source, current begins to flow
  • How much current will flow?

.5 O
  • Ohms Law (VIR)
  • -gtDescribes the relationship between the voltage
    (V), current (I), and resistance (R) in a circuit
  • Using Ohms Law, we can determine how much
    current is flowing through our circuit

0V
9
Analyzing the Circuitusing Ohms Law
  • How much current will flow?
  • Use Ohms Law
  • V I x R
  • 1.5V I x .5 O
  • Solve for I
  • I 1.5V / .5 O 3 Amps

.5 O
0V
So, 3 Amps will flow through the .5 Ohm resistor,
when 1.5 Volts are across it
10
Resistors in Series
  • Resistors connected by only 1 terminal,
    back-to-back, are considered to be in series

R1 .5 O
  • We can replace the two series resistors with 1
    single resistor, we call Req
  • The value of Req is the SUM of R1 R2
  • ReqR1R2.5 O .5 O 1O

R2 .5 O
Req 1 O
0V
11
Resistors in Series
  • Now we can find the current through the circuit
    using Ohms Law
  • Use Ohms Law
  • V I x Req
  • 1.5V I x 1 O
  • Solve for I
  • I 1.5V / 1 O 1.5 Amps

Req 1 O
0V
The bigger the resistance in the circuit, the
harder it is for current to flow
12
Resistors in Series
  • Back to our original series circuit, with R1 and
    R2
  • The current is the SAME through each resistor

R1 .5 O
  • Current flows like water through the circuit,
    notice how the 1.5 Amp stream of current flows
    through both resistors equally

R2 .5 O
  • Ohms Law shows us voltage across each resistor
  • V(R1) 1.5Amps x .5 O .75V
  • V(R2) 1.5Amps x .5 O .75V

0V
13
Resistors in Parallel
  • Resistors connected at 2 terminals, sharing the
    same node on each side, are considered to be in
    parallel
  • Unlike before, we cannot just add them. We must
    add their inverses to find Req

R1 .5 O
R2 .5 O
0V
14
Resistors in Parallel
  • This is the equivalent circuit
  • Use Ohms Law, we find the current through Req
  • V I x Req
  • 1.5V I x .25 O
  • Solve for I
  • I 1.5V / .25 O 6 Amps

Req .25 O
0V
The small the resistance in the circuit, the
easier it is for current to flow
15
Resistors in Parallel
  • Back to our original series circuit, with R1 and
    R2
  • The current is NOT the SAME through all parts of
    the circuit
  • Current flows like water through the circuit,
    notice how the 6 Amp stream of current splits
    to flow into the two resistors

R1 .5 O
R2 .5 O
  • The Voltage across each resistor is equal when
    they are in parallel

0V
16
Resistors in Parallel
  • The voltage is 1.5 V across each resistor
  • Ohms Law tells us the current through each
  • I(R1) V / R 1.5V / .5 O 3A
  • I(R2) V / R 1.5V / .5 O 3A
  • The 6Amps of current has split down the two legs
    of our circuit
  • It split equally between the two legs, because
    the resistors have the same value

R1 .5 O
R2 .5 O
0V
The current will split differently if the
resistors are not equal
17
In Summary
  • Ohms Law VIR
  • Describes the relationship between the voltage
    (V), current (I), and resistance (R) in a circuit
  • Current is equal through two resistors in series
  • Voltage drops across each resistor
  • Req R1 R2 . . .
  • Voltage is equal across two resistors in parallel
  • Current splits through branches of parallel
    circuits
  • 1/Req 1/R1 1/R2

18
In Lab Today
  • You will build series circuits
  • Build parallel circuits
  • Work with a breadboard
  • Verify Ohms Law by measuring voltage using a
    multimeter
  • And yes, there is HW!
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