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Defining Probabilities: Random Variables

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Title: Defining Probabilities: Random Variables


1
Defining Probabilities Random Variables
  • Examples
  • Out of 100 heart catheterization procedures
    performed at a local hospital each year, the
    probability that more than five of them will
    result in complications is
  • __________
  • Drywall anchors are sold in packs of 50 at the
    local hardware store. The probability that no
    more than 3 will be defective is
  • __________
  • In general, ___________

2
Discrete Random Variables
  • Example
  • Look back at problem 3, page 46. Assume someone
    spends 75 to buy 3 envelopes. The sample space
    describing the presence of 10 bills (H) vs bills
    that are not 10 (N) is
  • _____________________________
  • The random variable associated with this
    situation, X, reflects the outcome of the choice
    and can take on the values
  • _____________________________

3
Discrete Probability Distributions
  • The probability that there are no 10 in the
    group is
  • P(X 0) ___________________
  • (recall results from last time)
  • The probability distribution associated with the
    number of 10 bills is given by

x 0 1 2 3
P(X x)
4
Another Example
  • Example 3.3, pg 66
  • P(X 0)
  • _____________________

5
Discrete Probability Distributions
  • The discrete probability distribution function
    (pdf)
  • f(x) P(X x) 0
  • Sx f(x) 1
  • The cumulative distribution, F(x)
  • F(x) P(X x) St x f(t)

6
Probability Distributions
  • From our example, the probability that no more
    than 2 of the envelopes contain 10 bills is
  • P(X 2) F(2) _________________
  • The probability that no fewer than 2 envelopes
    contain 10 bills is
  • P(X 2) 1 - P(X 1) 1 - F(1)
    ________________

7
Another View
  • The probability histogram

8
Your Turn
  • The output of the same type of circuit board from
    two assembly lines is mixed into one storage
    tray. In a tray of 10 circuit boards, 6 are from
    line A and 4 from line B. If the inspector
    chooses 2 boards from the tray, show the
    probability distribution function associated with
    the selected boards being from line A.

x P(x)
0 1 2
9
Continuous Probability Distributions
  • Examples
  • The probability that the average daily
    temperature in Georgia during the month of August
    falls between 90 and 95 degrees is
  • __________
  • The probability that a given part will fail
    before 1000 hours of use is
  • __________
  • In general, __________

10
Understanding Continuous Distributions
  • The probability that the average daily
    temperature in Georgia during the month of August
    falls between 90 and 95 degrees is
  • The probability that a given part will fail
    before 1000 hours of use is

11
Continuous Probability Distributions
  • The continuous probability density function (pdf)
  • f(x) 0, for all x ? R
  • The cumulative distribution, F(x)

12
Probability Distributions
  • Example Problem 7, pg. 73
  • x, 0 lt x lt 1
  • f(x) 2-x, 1 x lt 2
  • 0, elsewhere
  • 1st what does the function look like?
  • P(X lt 120) ___________________
  • P(50 lt X lt 100) ___________________


13
Your turn
  • Problem 14, pg. 73

14
Additional useful information
  • Joint probability distributions
  • Example 1 (discrete) the joint probability mass
    function (see defn. 3.8, pg. 75)
  • In the development of a new receiver for a
    digital communication system, each received bit
    is rated as acceptable, suspect, or unacceptable,
    depending on the quality of the received signal,
    with the following probabilities
  • P(acceptable) P(x) 0.9
  • P(suspect) P(y) 0.08
  • P(unacceptable) P(z) 0.02

Section 3.4 in your book (Optional)
15
  • If we let X denote the number of acceptable bits
    and Y denote the number of suspect bits, then the
    joint probability associated with the number of
    acceptable and suspect bits in 4 transmitted bits
    is denoted by
  • fXY(x, y), where fXY(x, y) 0
  • ?x ?y fXY(x, y) 1
  • fXY(x, y) P(X x, Y y)
  • So, the probability of exactly two acceptable
    bits and exactly 1 suspect bit in the first 4
    bits is
  • fXY(2, 1) P(X 2, Y 1)
  • Assuming independence, we can determine the
    probability of a particular combination, say
    aasu, as
  • P(aasu) P(a)P(a)P(s)P(u)
    0.90.90.080.02
  • 0.0013

16
  • Recognizing that aasu is just one of several
    possible combinations of 4 bits, we next need to
    determine the number of possible permutations of
    2 acceptable and 1 suspect bit in 4 tested bits.
    That is (from theorem 2.6, pg. 36),
  • So,
  • fXY(2, 1) P(X 2, Y 1) 12(0.0013)
    0.0156

17
Joint probability distributions
  • Example 2 (continuous) the joint density
    function (see definition 3.9, pg. 76)
  • If X denotes the time until a computer server
    connects to your machine (in milliseconds) and Y
    denotes the time until the server authorizes you
    as a valid user (in milliseconds.) Each measures
    the wait from a common starting time and X lt Y.
    Assume that the joint probability density
    function for X and Y is given as
  • fXY(x, y) 6 x 10-6exp(-0.001x 0.002y) for x
    lt y

18
  • The probability that X lt 1000 and Y lt 2000 is

19
  • Note we can verify that this density function
    integrates to 1 as follows

20
For further study
  • Read section 3.4
  • Solve selected problems on pp. 84-86
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