Title: Physics 101: Lecture 15 Rolling Objects
1Physics 101 Lecture 15Rolling Objects
- Todays lecture will cover Textbook Chapter
8.5-8.7
- James Scholars
- Outline due April 14
- Final paper due April 28
- Details http//online.physics.uiuc.edu/courses/ph
ys101/spring08/honors_101.html - Need another volunteer!
2Overview
- Review
- Krotation ½ I w2
- Torque Force that causes rotation
- t F r sin q
- Equilibrium
- S F 0
- S t 0
- Today N2L for rotation
- S t I a
- Energy conservation revisited
3Linear and Angular
- Linear Angular
- Displacement x q
- Velocity v w
- Acceleration a a
- Inertia m I
- KE ½ m v2 ½ I w2
- N2L F ma t Ia
- Momentum p mv
Today
4Rotational Form Newtons 2nd Law
- S t I a
- Torque is amount of twist provide by a force
- Signs positive CCW
- Moment of Inertia like mass. Large I means hard
to start or stop from spinning. - Problems Solved Like N2L
- Draw FBD
- Write N2L
5Work Done by Torque
- Recall W F d cos q
- For a wheel
- W Ftangential d
- Ftangential r q (q in radians)
- t q
- P W/t t q/t
- t w
6The Hammer!
- You want to balance a hammer on the tip of your
finger, which way is easier? - A) Head up
- B) Head down
- C) Same
23 71 6
hammer demo
Because the center of gravity would be closer to
your hand making it easier to handle and balance.
Because angular acceleration decreases with R,
the larger the R the easier it is to balance.
15
7The Hammer!
- You want to balance a hammer on the tip of your
finger, which way is easier? - A) Head up
- B) Head down
- C) Same
23 71 6
t I a m g R sin(q) mR2 a
Angular acceleration decreases with R!, so large
R is easier to balance.
Torque increases with R
Inertia increases as R2
g sin(q) / R a
8Example Falling weight pulley
- A mass m is hung by a string that is wrapped
around a pulley of radius R attached to a heavy
flywheel. The moment of inertia of the pulley
flywheel is I. The string does not slip on the
pulley.Starting at rest, how long does it take
for the mass to fall a distance L. - (no numbers ?? algebra)
I
?
R
T
m
- What method should we use to solve this problem?
- Conservation of Energy (including rotational)
- St Ia and then use kinematics
mg
a
L
Either would work, but since it asks for time, we
will use B.
9Falling weight pulley...
- For the hanging mass use SF ma
- mg - T ma
- For the flywheel use St I?
- TR sin(90) I?
- Realize that a ?R
- Now solve for a using the above equations.
I
?
R
T
m
mg
a
L
10Falling weight pulley...
- Using 1-D kinematics we can solve for the time
required for the weight to fall a distance L
I
?
R
T
m
mg
a
L
11Rolling on a surface ACT
bike wheel
y
- A wheel is spinning clockwise such that the speed
of the outer rim is 2 m/s. - What is the velocity of the top of the wheel
relative to the ground? - What is the velocity of the bottom of the wheel
relative to the ground?
x
2 m/s
2 m/s
You now roll the wheel to the right at 2 m/s.
What is the velocity of the top of the wheel
relative to the ground? A) -4 m/s B) -2 m/s C)
0 m/s D) 2m/s E) 4 m/s What is the velocity
of the bottom of the wheel relative to the
ground? A) -4 m/s B) -2 m/s C) 0 m/s D) 2m/s
E) 4 m/s
12Example Rolling down a plane
- An object with mass M, radius R, and moment of
inertia I rolls without slipping down a plane
inclined at an angle ? with respect to
horizontal. What is its acceleration? - Consider CM motion and rotation about the CM
separately when solving this problem
I
R
M
?
13Example Rolling down a plane
- Static friction f causes turning. It is an
unknown, so we must solve for it. - First consider the free body diagram of the
object and use SF Ma - In the x direction Mg sin ? - f Ma
- Now consider rotation about the CMand use S?
I? realizing that - ? Rf and a ?R
M
R
?
14Example Rolling down a plane...
Mg sin ? - f Ma
- We have two equations
- We can combine these to eliminate f
I
A
R
M
?
15Energy Conservation!
- Friction causes object to roll, but if it rolls
w/o slipping friction does NO work! - W F d cos q d is zero for point in contact
- No dissipated work, energy is conserved
- Need to include both translation and rotation
kinetic energy. - K ½ m v2 ½ I w2
16Translational Rotational KE
- Consider a solid cylinder with radius R and mass
M, rolling w/o slipping down a ramp. Determine
the ratio of the translational to rotational KE.
Translational KT ½ M v2 Rotational
KR ½ I w2
Rotational KR ½ (½ M R2) (V/R)2
¼ M
v2
½ KT
KT / KR 2
H
17Rolling ACT
ramp demo
- Two uniform cylinders are machined out of solid
aluminum. One has twice the radius of the other. - If both are placed at the top of the same ramp
and released, which is moving faster at the
bottom?
(a) bigger one (b) smaller one
(c) same
Ki Ui Kf Uf
does not depend on R or M!
18Summary
- t I a
- Energy is Conserved
- Need to include translational and rotational
- P t w
19Tension ACT
F
m3
Compare the tensions T1 and T2 as the blocks are
accelerated to the right by the force F. A) T1 lt
T2 B) T1 T2 C) T1 gt T2
T1 lt T2 since T2 T1 m2 a. It takes force
to accelerate block 2.
T2 gt T1 since RT1 RT2 I2 a. It takes force
(torque) to accelerate the pulley.