Title: John A. Schreifels
1Chapter 14
2Overview
- Reaction Rates
- Definition of Reaction Rates
- Experimental Determination of Rate
- Dependence of Rate on Concentration
- Change of Concentration with Time
- Temperature and Rate Collision and
Transition-State Theories. - Arrhenius Equation
- Reaction Mechanisms
- Elementary Reactions
- Rate Law and the Mechanism
- Catalysis
3Reaction Rates
- Deal with the speed of a reaction and controlled
by - Proportional to concentrations of reactants
- Proportional to catalyst concentration catalyst
a substance that increases the rate of reaction
without being consumed in the reaction. - Larger surface area of catalyst means higher
reaction rate (more sites for reaction to take
place). - Temperature Higher temperature of reaction means
faster.
4Definition of Reaction Rate
- Reaction rate increase in concentration of
product of a reaction as a function of time or
decrease in concentration of reaction as a
function of time. - Thus the rate of a reaction is
- Rates are expressed as positive numbers. For the
reaction in the graph we have
5Reaction Rates and Stoichiometry
- A B ? C RC RA RB.
- A 2B ? 3C
- E.g.Calculate the rate of decomposition of HI in
the reaction 2HI(g) ? H2(g) I2(g). Given
After a reaction time of 100 secs. the
concentration of HI decreased by 0.500 M. - For the general reaction aA bB ? cC dD
-
- E.g. For the reaction 2A 3B ? 4C 2D
determine the rates of B, C and D if the rate of
consumption of A is 0.100 M/s.
6Rate Laws and Reaction Order
- Rate Law an equation that tells how the
reaction rate depends on the concentration of
each reaction. - Reaction order the value of the exponents of
concentration terms in the rate law. - For the reaction aA bB ? cC dD, the initial
rate of reaction is related to the concentration
of reactants. - Varying the initial concentration of one reactant
at a time produces rates, which will lead to the
order of each reactant. - The rate law describes this dependence R
kAmBn where k rate constant and m and n are
the orders of A and B respectively. - m 1 (A varied, B held constant) gives R
kA. Rate is directly proportional to A.
Doubling A doubles R - m 2 (A varied, B held constant) gives R
kA2. The rate is proportional to A2.
Doubling A quadruples R. - E.g. Determine order of each reactant
- HCOOH(aq) Br2(aq) ? 2H(aq) 2Br?(aq)
CO2(g) R kBr2 - E.g. The formation of HI gas has the following
rate law R kH2I2. What is the order of
each reactant?
7Experimental Determination of a Rate Law First
Order
- Varying initial concentration of reactants
changes the initial rate (usually all but one
held constant) like one with two unknowns. - Initial rate is the initial slope of the graph
shown. - As the initial concentration of that compound
increases so does the rate. - Initial rate vs. Ao plotted.
- If straight line then reaction is first order and
slope is rate constant. - Second order rate law determined in like manner.
8Rate Law for All Reactants
- Order for all components done same way.
- E.g. Determine the reaction order for each
reactant from the table. - (aq)5Br?(aq)6H(aq)?3Br2(aq)3H2O(l)
Eg. 2 Determine the reaction orders for the
reaction indicated from the data provided. A
2B C ? Products.
9Integrated Rate Law FirstOrder Reaction
- For a first order reaction, Rate ??A/?t
kA or RA ?dA/dt kA. - Use of calculus leads to
or - Allows one to calculate the A at any time after
the start of the reaction. - E.g. Calculate the concentration of N2O
remaining after its decomposition according to
2N2O(g) ? 2N2(g) O2(g) if its rate is first
order and N2Oo 0.20M, k 3.4 s?1 and T
780C. Find its concentration after 100 ms. - Linearized forms
or - Plot lnA vs t.
- Slope of straight line leads to rate constant, k.
- E.g. When cyclohexane(let's call it C) is heated
to 500 oC, it changes into propene. Using the
following data from one experiment, determine the
first order rate constant.
10Half-Life First Order Reaction
- Half-life of First order reaction, t1/2
0.693/k. the time required for the concentration
of the reactant to change to ½ of its initial
value. - i.e. at t1/2 , A ½ Ao
- E.g. For the decomposition of N2O5 at 65 C, the
half-life was found to be 130 s. Determine the
rate constant for this reaction.
- For n half-lives t nt1/2 A 2-n Ao
11SecondOrder Reactions Integrated Rate Law
- Rate law R kA2 and the integrated rate
equation is - Plot of vs. t gives a straight line with a
slope of k. - Half-life is
- E.g. At 330C, the rate constant for the
decomposition of NO2 is 0.775 L/(mols). If the
reaction is second-order, what is the
concentration of NO2 after 2.5x102 s if the
starting of concentration was 0.050 M?
12Reaction Mechanisms
- Give insight into sequence of reaction events
leading to product (reaction mechanism). - Each of the steps leading to product is called an
elementary reaction or elementary step. - Consider the reaction of nitrogen dioxide with
carbon dioxide which is second order on NO2 - NO2(g) CO(g) ? NO(g) CO2(g) Rate kNO22.
- Rate law suggests at least two steps.
- A proposed mechanism for this reaction involves
two steps. -
- NO3 is a reaction intermediate a substance that
is produced and consumed in the reaction so that
none is detected when the reaction is finished. - The elementary reactions are often described in
terms of their molecularity. - Unimolecular One particle in elementary.
- Bimolecular 2 particles and
- Termolecular 3 particles
13Rate Laws and Reaction Mechanisms
- Overall reaction order is often determined by the
rate determining step. - Use rate law of limiting step No intermediates!
2NO2(g) ? NO3(g) NO(g), R1 k1NO22 Slow
NO3(g) CO(g) ?NO2(g) CO2(g) R2 k2NO3CO Fast
NO2 CO ? NO CO2 Robs kNO22
E.g. Determine the rate law for the following
mechanism
14Reaction Rates and Temperature The Arrhenius
Equation
- Rate (rate constant) increases exponentially with
temperature. - Collision theory indicates collisions every 10?9s
10?10s at 25C and 1 atm. - i.e. only a small fraction of the colliding
molecules actually react. - Collision theory assumes
- Reaction can only occur if collision takes place.
- Colliding molecules must have correct orientation
and energy. - Collision rate is directing proportional to the
concentration of colliding particles. - A B ? Products Rc ZAB
- 2A B ? Products Rc ZA2B, etc.
- Only a fraction of the molecules, p (steric
factor), have correct orientation multiply
collision rate by p. - Particle must have enough energy. Fraction of
those with correct energy follows Boltzmann
equation where Ea
activation energy, R gas constant and T temp.
(Kelvin scale only please). - This gives k Zpf
15Transition State Theory
- Explains the reaction resulting from the
collision of molecules to form an activated
complex. - Activated complex is unstable and can break to
form product.
16The Arrhenius Equation
- Summary
where A frequency factor. - Linear form .
- Plot ln k vs. 1/T the slope gives Ea/R.
- E.g. determine the activation energy for the
decomposition of N2O5 from the temperature
dependence of the rate constant. - Two point equation sometimes used also
- E.g.2 Determine the rate constant at 35C for
the hydrolysis of sucrose, given that at 37C it
is 0.91mL/(molsec). The activation energy of
this reaction is 108 kJ/mol. - Rate constant increases when T2gtT1
k, s?1 Temp., C Temp., K
4.8x10?4 45.0 318.15
8.8x10?4 50.0 323.15
1.6x10?3 55.0 328.15
2.8x10?3 60.0 333.15
17Catalysis
- Catalysts a substance that increases the rate of
a reaction without being consumed in the
reaction. - Catalyst provides an alternative pathway from
reactant to product which has a rate determining
step that has a lower activation energy than that
of the original pathway. - E.g. Hydrogen peroxide and bromine
- 2H2O2(aq) ? 2H2O(l) O2(g).
- Mechanism is believed to be
1. Br2 red Br2(aq) H2O2(aq) ? 2Br?(aq) 2H(aq)O2(g)
2. Br? oxid 2H(aq)2Br?(aq)H2O2(aq) ? Br2(aq) 2H2O(l).
Overall 2H2O2(aq) ? 2H2O(l)O2(g)
- Notice that bromine is not consumed, even though
it has participated in the reaction.
18Homogeneous and Heterogeneous Catalysts
- Homogeneous catalyst catalyst existing in the
same phase as the reactants. - Heterogeneous catalysis catalyst existing in a
different phase than the reactants. - The previous section gave an example of a
homogeneous catalyst since the catalyst Br2 was
in the same phase as the hydrogen peroxide. - The catalytic hydrogenation of ethylene is an
example of a heterogeneous catalysis reaction - ENZYMES (biological catalysts)
- They are proteins (large organic molecules that
are composed of amino acids). - Slotlike active sites. The molecule fits into
this slot and reaction proceeds. Poisons can
block active site or reduce activity by
distorting the active site.
19Steric Factor
- Molecules must have the correct orientation
before a reaction can take place.
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