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Worked problems for standard scores, percentiles, and stanines

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Right now he is trying to place the two students in math and English. ... The two girl's standardized test scores were obtained from different norm groups ... – PowerPoint PPT presentation

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Title: Worked problems for standard scores, percentiles, and stanines


1
Worked problems for standard scores, percentiles,
and stanines
  • The problems are given in pairs. The first slide
    presents the problem, the second slide gives the
    answer.

2
Item 1
  • Rosemary and Angela are new 10th-grade students
    to Lincoln High School. They have just moved in
    to the area from different states, Rosemary from
    Virginia and Angela from Texas. Both states have
    statewide standardized testing programs. The
    Lincoln High counselor is trying to place the
    students in appropriate classes. Right now he is
    trying to place the two students in math and
    English.
  • He notes that Rosemarys standard scores on her
    previous states math and English tests were .25
    and 1.2, respectively. Angelas scores on her
    previous states math and English tests were .75
    and .95, respectively.
  • Which of the following statements is true?
  • A. Angela should be placed in higher level math
    and English Classes.
  • B. The students should be placed in the same
    level math and English classes.
  • C. Both should be placed in higher than average
    level classes in math and English.
  • D. Not enough information is given to determine
    placements.

3
  • The answer is D Not enough information is given.
  • The two girls standardized test scores were
    obtained from different norm groups and are,
    hence, not comparable. In order to be able to
    compare two individuals norm-referenced scores
    (standard scores, percentiles, grade equivalent
    scores, etc.) the scores have to be compared to
    the same norm group. Rosemarys scores are from a
    test normed in Virginia Angelas from a test
    normed in Texas. It is possible that an
    above-average performance on, say, a math test in
    Texas would be equivalent to a below-average
    performance on a similar test in Virginia.

4
Item 2
  • Recall that Rosemarys standard scores on her
    previous states math and English tests were .25
    and 1.2, respectively, and that Angelas scores
    on her previous states math and English tests
    were .75 and .95, respectively.
  • Which of the following interpretations can most
    easily be supported?
  • Rosemary and Angela both perform better in
    English than in Math.
  • Only Rosemary is clearly better at English than
    at Math.
  • C. While Rosemary is clearly better than Angela
    in English, Angela is better in math.

5
  • The correct answer is B Only Rosemary is clearly
    better at English than at math.
  • The difference between Rosemarys standard scores
    in math and English (.25 and 1.2) correspond,
    roughly, to a difference in percentiles of 51
    tile for math and the 90th tile for English.
    The difference in Angelas standard scores for
    math and English, on the other hand, correspond,
    again roughly, to a difference between the the
    79th tile and the 83ed tile.
  • Choice C is incorrect for reasons given for the
    previous item. The girls test scores come from
    test normed on different populations and, hence,
    are not comparable.

6
Item 3
  • Tom, Dick, and Harry reported their scores on the
    same science test to their mothers. Each reported
    his score as 70.
  • In Harrys case, his score was actually 70 of
    the items correct.
  • Toms score really referred to the 70th
    percentile.
  • Dick was actually reporting the number of items
    he got correct.
  • The test, which contained 75 items, had a mean of
    60 and a standard deviation of 10. Who, if any,
    had the best performance on the test?
  • A. Tom C. Harry
  • B. Dick D. Cant tell

7
  • The correct answer is B. Dick, who scored 70 of
    75 items correct did best on the test. His score
    is clearly better than Harrys. Harry, who got
    70 of the items correct only got 52 or 53 items
    correct.
  • The only thing we have to check is whether Dick
    scored above or below Toms 70th percentile. To
    check this we first have to calculate his
    standard score. A simple calculation reveals that
    Dicks standard score is 1. He scored one
    standard deviations above the mean. Since one
    standard deviation above the mean equates to the
    84th percentile, Dick clearly outscored Tom.

8
Item 4
  • Picabo came in at a speed of 100 mph on the
    downhill. Tommy, on a bad day, came in at the
    same speed. The average female speed on the
    downhill is 80 mph with a SD of 5. The average
    male speed on the downhill is 110 with a SD of
    10. Just how much better than Tommy is Picabo?

9
  • Tommy is coming in a the 16th percentile. He
    needs to stop that partying.
  • Picabo is at the 99percentile. She needs to
    watch those steroids.
  • Picabo is definitely better than Tommy. Whoa!
    Actually, they are the samethey both skied at
    the same speed, 100 mph.
  • Only when compared to the norms for their gender
    do we see a difference in their performance.
  • In this case, however, there is an absolute
    standard of comparison. This is a case of
    criterion-referenced measurement.
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