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Chapter 16: Chemical Equilibrium General Concepts

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Title: Chapter 16: Chemical Equilibrium General Concepts


1
Chapter 16 Chemical Equilibrium- General Concepts
  • When a system is at equilibrium, the forward and
    reverse reaction are proceeding at the same rate
  • The concentrations of all species remains
    constant over time, but both the forward and
    reverse reaction never cease
  • Equilibrium is signified with double arrows or
    the equal sign

2

The decomposition of N2O4(g) into NO2(g). The
concentrations of N2O4 and NO2 change relatively
quickly at first, but eventually stop changing
with time when equilibrium is reached.
3
  • The equilibrium mixture is independent of whether
    we start on the reactant side or the product
    side

The equilibrium between N2O4 and NO2.
4

The same equilibrium composition is reached from
either the forward or reverse direction, provided
the overall system composition is the same. Pure
NO2 is brown and pure N2O4 is colorless. The
amber color of the equilibrium mixture indicates
that both species are present at equilibrium.
5
  • There is a simple relationship among the
    concentrations of the reactants and products for
    any chemical system at equilibrium
  • It is called the mass action expression, and is
    derived from thermodynamics (discussed in Chapter
    20)
  • Consider the equilibrium

6
Four experiments to study the equilibrium among
H2, I2, and HI gases. Different amounts of the
reactants and products are placed in a 10.0 L
reaction vessel at 440oC where the gases
establish equilibrium. When equilibrium is
reached, different amounts of reactants and
products remain.

7
  • The numerical value of the mass action expression
    is called the reaction quotient, Q

8
  • The reaction can be evaluated at any
    concentrations
  • At equilibrium (and 440oC) for this reaction the
    reaction quotient has the value 49.5 (a unitless
    number)
  • This relationship is called the equilibrium law
    for the system

9
  • The value 49.5 is called the equilibrium
    constant, Kc, and characterizes the system
  • For chemical equilibrium to exist, the reaction
    quotient Q must be equal to the equilibrium
    constant Kc
  • Consider the general chemical equation

10
  • The exponents in the mass action expression are
    the same as the stoichiometric coefficients
  • At equilibrium
  • The form is always products over reactants
    raised to the appropriate powers

11
  • Various operations can be performed on
    equilibrium expressions
  • Changing the direction of equilibrium when the
    direction of an equilibrium is reversed, the new
    equilibrium constant is the reciprocal of the
    original

12
  • Multiplying the coefficients by a factor when
    the coefficients in an equation are multiplied by
    a factor, the equilibrium constant is raised to a
    power equal to that factor

13
  • Adding chemical equilibria when chemical
    equilibria are added, their equilibrium constants
    are multiplied

14
  • The gas law can be used to write the equilibrium
    constant in terms of partial pressures
  • Equilibrium constants written in terms of partial
    pressures are given the symbol Kp

15
  • The size of the equilibrium constant gives a
    measure of how the reaction proceeds
  • General statements can be made about the
    equilibrium constant (either Kc or KP)

16

The magnitude of K and the position of
equilibrium. A large amount of product and very
little reactant at equilibrium gives Kgtgt1 (large
K). When , approximately equal amounts
of reactant and product are present at
equilibrium. When Kltlt1, mostly reactant and very
little product are present at equilibrium.
17
  • The two different forms of the equilibrium
    constants can be related

18
  • In a homogeneous reactions, all the reactants and
    products are in the same phase
  • Heterogeneous reactions involve more than one
    phase
  • For example the thermal decomposition of sodium
    bicarbonate (baking soda)
  • Heterogeneous reactions can come to equilibrium
    just like homogeneous systems

19
  • If NaHCO3 is placed in a sealed container,
    homogeneous equilibrium is established
  • The equilibrium law involving pure liquids and
    pure solids can be simplified

20
  • For a pure liquid or solid, the ratio of amount
    of substance to volume of substance is constant

The concentration of a substance in a solid is
constant. Doubling the number of moles doubles
the volume, but the ratio of moles to volume
remains the same.
21
  • The equilibrium law for a heterogeneous reaction
    is written without concentrations terms for pure
    solids or pure liquids.
  • The equilibrium constants found in tables
    represent all the constants combined

22
  • According to Le Châteliers principle
  • If an outside influence upsets an equilibrium,
    the system undergoes a change in the direction
    that counteracts the disturbing influence and, if
    possible, returns the system to equilibrium
  • We can consider some common stresses
  • Adding or removing a product or reactant
  • The equilibrium shifts to remove reactants or
    products that have been added
  • The equilibrium shifts to replace reactants or
    products that have been removed

23
  • Changing the volume
  • Reducing the volume of a gaseous reaction causes
    the reaction to decreases the number of molecules
    of gas, if it can
  • Moderate pressure changes have a negligible
    effect on reactions involving only liquids or
    solids
  • Changing the temperature
  • Increasing the temperature shifts a reaction in a
    direction that produces an endothermic
    (heat-absorbing) change
  • Decreasing the temperature shifts a reaction in a
    direction that produces an exothermic
    (heat-releasing) change

24
  • Catalysts have no effect on the position of
    equilibrium
  • Catalysts change how fast a system achieves
    equilibrium, not the relative distribution of
    reactants and products
  • Adding an inert gas at constant volume
  • If the added gas cannot react with any reactants
    or products it is inert towards the substances in
    the equilibrium
  • No concentration changes occur, so Q still equals
    K and no shift in equilibrium occurs

25
  • Equilibrium calculations can be divided into two
    main categories
  • Calculating equilibrium constants from known
    equilibrium concentrations or partial pressures
  • Calculating one or more equilibrium
    concentrations or partial pressures using the
    known value of Kc or KP
  • Consider the decomposition of N2O4

26
  • Calculating the equilibrium constant this way is
    easy

27
  • More commonly, you will have a set of initial
    conditions and an equilibrium constant
  • If a KP describes the system, equilibrium will
    usually be described in terms of partial
    pressures
  • If a Kc describes the system, equilibrium will
    usually be describe in terms of concentration
    (molarity, mol/L)
  • The Initial, Change, Equilibrium or ICE table
    is a useful way to summarize the problem

28
  • Example Ethyl acetate, CH3CO2C2H5, is produced
    from acetic acid and ethanol by the reaction
  • At 25oC, Kc4.10 for this reaction. Suppose
    0.100 mol of ethyl acetate and 0.150 mol of water
    are placed in a 1.00 L reaction vessel. What are
    the concentrations of all species at equilibrium?
  • ANALYSIS Use an ICE table and the equilibrium
    constant to find the concentrations.

29

30
  • This can be solved by putting it in quadratic
    form

31
  • Negative concentrations are not allowed, so
  • A similar procedure can be used to calculate
    partial pressures using KP

32
  • Sometime simplifications can be made
  • Example Nitrogen and oxygen react to form
    nitrogen monoxide
  • with Kc4.8x10-31. In air at 25oC and 1 atm, the
    N2 concentrations and O2 are initially 0.033 M
    and 0.00810 M. What are the equilibrium
    concentrations?
  • ANALYSIS The equilibrium constant is very small,
    very little of the reactants will be converted
    into products

33

34
  • Substituting
  • N20.033-x0.033 M
  • O20.00810-x0.030810 M
  • NO2x1.60x10-17 M
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