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Chapter 13 Properties of Solutions

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Title: Chapter 13 Properties of Solutions


1
Chapter 13Properties of Solutions
Jozsef DevenyiDepartment of Chemistry, UTM
2
The Solution Process
  • A solution is a homogeneous mixture of solute
  • (present in smallest amount) and solvent
    (present
  • in largest amount).
  • Solutes and solvent are components of the
    solution.
  • In the process of making solutions with condensed
    phases, intermolecular forces become rearranged.
  • Consider NaCl (solute) dissolving in water
    (solvent)
  • the water H-bonds have to be interrupted,
  • NaCl dissociates into Na and Cl-,
  • ion-dipole forces form Na ?-OH2 and Cl-
    ?H2O.
  • We say the ions are solvated by water.
  • If water is the solvent, we say the ions are
    hydrated.

3
The Solution Process
Recall cation-dipole interaction
anion-dipole interaction
4
The Solution Process
Energy Changes and Solution Formation
There are three energy steps in forming a
solution
- separation of solute molecules (?H1)
  • separation of solvent
  • molecules (?H2)

- formation of solute-solvent interactions
(?H3)
5
The Solution Process
Energy Changes and Solution Formation
  • We define the enthalpy change in the solution
    process as
  • ?Hsoln ?H1 ?H2 ?H3
  • ?Hsoln can either be positive or negative
    depending on the intermolecular forces.

6
The Solution Process
Energy Changes and Solution Formation
  • Breaking attractive intermolecular forces is
    always endothermic.
  • Forming attractive intermolecular forces is
    always exothermic.
  • To determine whether ?Hsoln is positive or
    negative, we
  • consider the strengths of all solute-solute
    and
  • solute-solvent interactions
  • ?H1 and ?H2 are both positive
  • ?H3 is always negative
  • It is possible to have either ?H3 gt (?H1
    ?H2) or

  • ?H3 lt (?H1 ?H2).

7
The Solution Process
Energy Changes and Solution Formation
Examples
  • NaOH added to water has ?Hsoln - 44.48 kJ/mol.
  • NH4NO3 added to water has ?Hsoln 26.4 kJ/mol.
  • General rule similar dissolves in similar,
    i.e., polar
  • solvents dissolve polar solutes. Non-polar
    solvents
  • dissolve non-polar solutes.
  • - If ?Hsoln is too endothermic a solution will
    not form.
  • NaCl in gasoline the ion-dipole forces are
    weak because
  • gasoline is non-polar. Therefore, the
    ion-dipole forces do
  • not compensate for the separation of ions.

- Water in octane water has strong H-bonds.
There are no attractive forces between
water and octane to compensate for the
H-bonds.
8
Ways of Expressing Concentration
  • All methods involve quantifying amount of
  • solute per amount of solvent (or solution).
  • Generally amounts or measures are masses, moles
    or liters.
  • Qualitatively solutions are dilute or
    concentrated.
  • Definitions

9
Ways of Expressing Concentration
Mole Fraction, Molarity, and Molality
Recall
mass can be converted to moles using the molar
mass
10
Ways of Expressing Concentration
Mole Fraction, Molarity, and Molality
  • We define

Converting between molarity (M) and molality (m)
requires density.
11
Ways of Expressing Concentration
Mole Fraction, Molarity, and Molality
12
Ways of Expressing Concentration
Mole Fraction, Molarity, and Molality
Examples
  • Calculate the percent by mass concentration of
    sugar when 6.28g of sugar is dissolved in 173g of
    water.

13
Ways of Expressing Concentration
Mole Fraction, Molarity, and Molality
Examples
B)
Calculate the molality of the above solution if
the molar mass of sugar is 180.16g/mol.
14
Ways of Expressing Concentration
Mole Fraction, Molarity, and Molality
Examples
C)
15
Ways of Expressing Concentration
Mole Fraction, Molarity, and Molality
Examples
D)
16
Ways of Expressing Concentration
Mole Fraction, Molarity, and Molality
Examples
E)
17
Factors Affecting Solubility
Solute-Solvent Interaction
  • Polar liquids tend to dissolve in polar solvents.
  • Miscible liquids mix in any proportions.
  • Immiscible liquids do not mix.
  • Intermolecular forces are important water and
    ethanol are miscible because the broken hydrogen
    bonds in both pure liquids are re-established in
    the mixture.
  • The number of carbon atoms in a chain affect
    solubility the more C atoms the less soluble in
    water
  • (see Table 13.3)
  • The number of -OH groups within a molecule
    increases
  • solubility in water.

18
Factors Affecting Solubility
Solute-Solvent Interaction
  • Generalization like dissolves like.
  • The more polar bonds in the molecule, the better
    it dissolves in a polar solvent.
  • The less polar the molecule the less it dissolves
    in a polar solvent and the better is dissolves in
    a non-polar solvent.

19
Factors Affecting Solubility
Solute-Solvent Interaction
20
Factors Affecting Solubility
Temperature Effects
  • Experience tells us that sugar dissolves better
    in warm water than cold.
  • As temperature increases, solubility of solids
    generally increases.
  • Sometimes, solubility decreases as temperature
    increases (e.g. Ce2(SO4)3).

21
Factors Affecting Solubility
Temperature Effects
22
Factors Affecting Solubility
Temperature Effects
  • Experience tells us that carbonated beverages go
    flat as they get warm.
  • Therefore, gases get less soluble as temperature
    increases.
  • Why?
  • Thermal pollution if lakes get too warm, CO2 and
    O2 become less soluble and are not available for
    plants or animals.

23
Factors Affecting Solubility
Temperature Effects
24
Colligative Properties
  • Observations
  • freezing point of solution is lower than that of
    pure
  • solvent e.g., salt added to road in cold to
    lower melting
  • point (prevent freezing) of precipitation
    (water)
  • - boiling point of solution is higher than that
    of pure solvent
  • These effects of a solute on the solvent are
    called colligative properties. These properties
    depend only on the quantity of solute dissolved
    and independent of the type of solute that is
    dissolved.
  • Colligative properties
  • freezing point depression
  • melting point elevation
  • vapor pressure lowering
  • osmosis

25
Colligative Properties
Lowering Vapor Pressure
  • Non-volatile solutes reduce the ability of the
    surface solvent molecules to escape the liquid.
  • Therefore, vapor pressure above solution is
    lowered.
  • The amount of vapor pressure lowering depends on
    the amount of solute dissolved.
  • Raoults Law
  • PA is the vapor pressure with solute, PA? is
    the vapor pressure without solute, and ?A is the
    mole fraction of A, then

Recall Daltons Law
26
Colligative Properties
Lowering Vapor Pressure
  • ideal solution one that obeys Raoults law
  • Raoults law breaks down when the solvent-solvent
    and solute-solute intermolecular forces are
    greater than solute-solvent intermolecular forces.

Boiling-Point Elevation
  • - How does vapor pressure lowering effect the
    phase diagram?
  • Non-volatile solute lowers the vapor pressure.
  • - Therefore the triple point - critical point
    curve is lowered.

27
Colligative Properties
Boiling-Point Elevation
28
Colligative Properties
Boiling-Point Elevation
  • At 1 atm (normal boiling point of pure liquid)
    there is a lower vapor pressure of the solution.
    Therefore, a higher temperature is required to
    teach a vapor pressure of 1 atm for the solution.

The increase in the boiling point (?Tb) compared
to the boiling point of the pure solvent is
directly proportional to the molal concentration
of the solute (m).
Mathematically
where Kb is the molal boiling-point-elevation
constant.
29
Colligative Properties
Freezing-Point Depression
  • The melting-point (freezing-point) curve is a
    vertical line from the triple point.
  • The solution freezes at a lower temperature (?Tf)
    than the pure solvent.
  • Decrease in freezing point (?Tf) is directly
    proportional to molal cncentration of the
    solution, m.

Mathematically
where Kf is the molal freezing-point-depression
constant)
30
Colligative Properties
Freezing-Point Depression
31
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32
Colligative Properties
Examples
A solution was prepared by dissolving 34.6g of
NaCl in 827g of water. The molar freezing point
and boiling point constants of water are Kf
1.86 oC/m and Kb 0.52 oC/m, respectively.
F)
Calculate the freezing point of the solution.
33
Colligative Properties
Examples
A solution was prepared by dissolving 34.6g of
NaCl in 827g of water. The molar freezing point
and boiling point constants of water are Kf
1.86 oC/m and Kb 0.52 oC/m, respectively.
F)
Calculate the boiling point of the solution.
G)
34
Colligative Properties
Examples
H)
I)
35
Colligative Properties
Examples
J)
36
Colligative Properties
Examples
K)
37
End of Chapter 13Properties of Solutions
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