Title: Lecture 6 Confirmation
1Lecture 6Confirmation
2Inductive logic?
- Logic is about evidence or good reasons. In
deductive logic, it is all clear and simple a
good reason is something that guarantees the
truth of the conclusion. - But in inductive logic we deal with weaker
reasons, weaker type of evidence. If e is
inductive evidence for h, it is not guaranteed
that if e is true, h will also be true. It only
means that with e we will have more reason to
believe that h is true than before. - Someone might think that if h deductively implies
e, then we can take e to be inductive evidence
that h is true. - For example, if hypothesis h (all metals expand
when heated) deductively implies e (this piece of
metal will expand when heated), an observation
that e is true will confirm h. - But this is a logical fallacy, known as affirming
the consequent. - Wesley Salmon once joked that in deductive logic
we learn how to avoid fallacies, and in inductive
logic we learn how to commit these fallacies!
3What confirms what?
- In fact, no one thinks that for any hypothesis h,
every deductive consequence of h confirms h. If
this were true, every hypothesis would be
confirmed by every observation. - Proof
- Take a hypothesis h. Now, h deductively implies
(h v p), where p is any statement. (This is an
application of the rule of addition in natural
deduction.) Or, symbolically h ? (h v p). - Take any observational statement o. If h is true,
then (h v o) must also be true. In other words, h
? (h v o). - But if o is true, then (h v o) is true as well.
But then o makes true one of the deductive
consequences of h, and this means that o confirms
h. - How about limiting confirmation to instances of
generalizations? That is, maybe should take
statement All Fs are G to be confirmed only by
observations of things that are both F and G.
4The ravens paradox
- Carl Hempel showed that there are problems with
that idea too. He showed that two intuitively
very plausible assumptions lead to the conclusion
that sounds unacceptable. His problem is called
the ravens paradox. - Nicods Condition (NC)The proposition that a
given object a has both characteristics F and G
confirms the proposition that every F has G. - Equivalence Condition (EC)If proposition P
confirms Q, and Q is logically equivalent to Q,
then P confirms Q. - Paradoxical Conclusion (PC) The proposition (E)
that a is both non-black and a non-raven confirms
the proposition (H) that every raven is black
(because All R are B All B are R). - A white shoe confirms that all ravens are black!
5All ravens are black All non-black things
are non-ravens
Ravens
Black things
R B Empty!!!
R B
R B
R B
6Solutions to the ravens paradox
- The argument is valid. PC deductively follows
from NC and EC (assuming the equivalence of All
R are B and All B are R). - There are three possible strategies to solve this
paradox - One can reject NC deny that every generalization
is confirmed by any of its instances. - One can reject EC claim that an observation may
confirm h, but not a logically equivalent
hypothesis h. - One can accept the conclusion claim that
observing a brown shoe confirms that all ravens
are black (indoor ornithology!). - Hempel opted for strategy 3. He thinks that it
just seems that a white shoe does not confirm
All ravens are black. The reason is that we
tacitly introduce some information, and we are
therefore no longer looking at the relation only
between the evidence and the hypothesis.
7Hempels idea
- Hempel thought that since we assume that there
are so many more non-black things than ravens,
then if we take a non-black thing we expect it to
be a non-raven. - This explains why we do not take a non-black
(white) thing that is a non-raven (shoe) as
significantly confirming h. He thinks that
finding a white shoe actually does confirm h, but
to a very small degree, which we mistake for no
confirmation at all. - Non-black thing is a falsification opportunity
for h, so if this thing turns out not to be a
raven, this slightly confirms h. - Hempels idea is that if we remove all tacitly
introduced information that is influencing our
judgment of the degree of confirmation of h, and
if we focus only on the relation of the evidence
and hypothesis, we will see that a black raven
and a white shoe both confirm All ravens are
black.
8Against Hempel
- Hempel was searching for the pure relation
between e and h. The goal was to discover a
degree of confirmation that e give to h,
abstracting from all other information. - But many contemporary philosophers think that
there is no pure degree confirmation. They
believe that confirmation is not a binary
relation between e and h, but a relation between
three things e, h, and the background knowledge. - They think that without knowing anything else we
simply cannot know whether e confirms h or not. - There is a possibility that e confirms h, or that
e is irrelevant for h, or that e even disconfirms
h. - Without more information the degree of
confirmation is simply undefined.
9NC is false!
- An instance of a generalization does not
necessarily support it. Object a that is F and G
may not be evidence for All F are G. - Example All humans are shorter than 2.5
meters. But finding an instance of that
generalization can actually decrease our
confidence in that generalization. - Let H be human, and S be shorter than 2.5
meters. Now imagine that we find a person who is
2.48 meters tall. We found a person who is H and
S. But now we would be less ready to believe that
all H are S! - Another example There are three people (a, b and
c) who just left (L), and there is a hypothesis
that each left wearing someone elses hat (H)
All L are H. - Suppose that a left with bs hat, and b left with
as hat. So, these two instances of All L are
H refute the generalization.
10I. J. Goods counter-example
- I. J. Good invented the following possible
situation, in which observing a black raves seems
to disconfirm that all ravens are black. - We observe a black raven. Our background
knowledge K says that exactly one of the
following hypotheses is true (H) there are 100
black ravens, no non-black ravens, and 1 million
other birds, or else (H) there are 1,000 black
ravens, 1 white raven, and 1 million other birds.
And K also states that an object a is selected at
random from all the birds. - Observing a black raven in a random selection is
much more likely if H is true (than if H is
true), because there are more ravens under H
than under H. - Under the conditions, observing a black raven
gives you a reason to believe that not all ravens
are black.
11The Wason Selection Task
These four cards have a letter and number on two
sides.
D
F
7
3
If a card has a D on one side, the other side
must have a 3.
Which card or cards must you turn over in order
to test this rule?
12Solution
- Card D (a) if it has 3 on the other side, no
problem. (b) if it doesnt have 3
on the other side, the rule falsified. - Card F (a) if it has 3 on the other side, no
problem. (b) if it doesnt have 3
on the other side, no problem. - Card 3 (a) if it has D on the other side, no
problem. (b) if it doesnt have D
on the other side, no problem. - Card 7 (a) if it has D on the other side, the
rule is falsified. (b) if it
doesnt have D on the other side, no problem. - Cards 1 and 4 give different outcomes, depending
on what is on the other side, so they have to be
turned over. - Cards 2 and 3 always have the same outcome (no
problem), independently on what is on the other
side, so they are useless.
13Application to the raven paradox
- Whether a black raven confirms All R are B,
depends not only on the background information
but also on which characteristic is first
discovered. - If I have a raven behind my back and ask you
whether you would like to see it (and check
whether it is a black), you should say yes (if
you want to get more evidence about whether all R
are B). - But if I have a black thing behind my back and
ask you whether you would like to see (and check
whether it is a raven) you should say that you
are not interested, because whatever it is, it
cannot disprove that all R are B. - Notice, however, that the two situations may be
the same, in the sense that in both cases what I
actually have behind my back is a black raven.
14Four ways of observing R and B
- If we put an asterisk for an information that is
obtained first (out of the two pieces of
information), here are four possibilities
(similar to 4 cards in the Wason selection task) - RB - Confirming All R are B (For example you
see a raven in a dim light and cannot recognize
the color. But then you realize its black. There
was a possibility of falsification, so the result
is confirmation.) - BR - Useless
- RB - Useless
- BR - Confirming All R are B (You see
something white in a tree, and you are not sure
what it is, a bird or something else. Then you
realize it is a shoe. Again, there was a
possibility of falsification, so the result is
confirmation. White shoe confirms that all ravens
are black.)
15Four ways of sampling
- We can apply the same way of thinking to the
problem of sampling. There are four categories
that can be sampled ravens, non-ravens, black
things, non-black things. - Ravens Finding that all sampled ravens are black
supports the generalization All R are B. - Non-ravens Finding that all sampled non-ravens
are non-black does not support the generalization
All R are B. - Black things Finding that all sampled black
things are ravens does not support the
generalization All R are B. - Non-black things Finding that all sampled
non-black things are non-ravens support the
generalization All R are B.
16Sampling options graphical representation
(1) R B Empty!!!
(2) R B
(3) R B
(4) R B
Ravens (1,2) Useful because it includes area
1.Black things (2,3) Useless because it does
not include area 1.Non-ravens (3,4) Useless
because it does not include area 1.Non-black
things (1,4) Useful because it includes area 1.