Title: ChargedParticle and Radiation Equilibria I
1Charged-Particle and Radiation Equilibria I
- Radiation Equilibrium
- Charged-Particle Equilibrium
2Introduction
- The concepts of radiation equilibrium (RE) and
charged-particle equilibrium (CPE) are useful in
radiological physics as a means of relating
certain basic quantities - CPE allows the equating of the absorbed dose D to
the collision kerma Kc, while radiation
equilibrium makes D equal to the net rest mass
converted to energy per unit mass at the point of
interest
3Radiation Equilibrium
- Consider an extended volume V containing a
distributed radioactive source - A smaller internal volume v exists about a point
of interest, P - V is required to be large enough so that the
maximum distance of penetration d of any emitted
ray and its progeny (i.e., scattered and
secondary rays) is less than the minimum
separation s of the boundaries of V and v - Radioactivity is emitted isotropically on the
average
4Radiation equilibrium
5Radiation Equilibrium (cont.)
- If the following 4 conditions exist throughout V,
it will be shown that radiation equilibrium (RE)
exists for the volume v (in the nonstochastic
limit) - The atomic composition of the medium is
homogeneous - The density of the medium is homogeneous
- The radioactive source is uniformly distributed
- There are no electric or magnetic fields present
to perturb the charged-particle paths, except the
fields associated with the randomly oriented
individual atoms
6Radiation Equilibrium (cont.)
- Imagine a plane T that is tangent to the volume v
at a point P, and consider the rays crossing the
plane per unit area there - In the nonstochastic limit there will be perfect
reciprocity of rays of each type and energy
crossing both ways, since the radioactive source
distribution within the sphere S of radius d
about point P is perfectly symmetrical with
respect to plane T
7Radiation equilibrium
8Radiation Equilibrium (cont.)
- This will be true for all possible orientations
of tangent planes around the volume v hence one
can say that, in the nonstochastic limit, for
each type and energy of ray entering v, another
identical ray leaves - This condition is called radiation equilibrium
(RE) with respect to v
9Radiation Equilibrium (cont.)
- We can write as a consequence of radiation
equilibrium that the following equalities of
expectation values exist - and
- that is, the energy carried in and that
carried out of v are balanced for both indirectly
and directly ionizing radiation, where the bars
signify expectation values
10Radiation Equilibrium (cont.)
- The energy imparted can then be simplified to
- which means that under RE conditions the
expectation value of the energy imparted to the
matter in the volume v is equal to that emitted
by the radioactive material in v
11Radiation Equilibrium (cont.)
- The concept of radiation equilibrium has
practical importance especially in the fields of
nuclear medicine and radiobiology, where
distributed radioactive sources may be introduced
into the human body or other biological systems
for diagnostic, therapeutic, or analytical
purposes - The resulting absorbed dose at any given point in
such circumstances depends on the size of the
object relative to the radiation range and on the
location of the point within the object
12Radiation Equilibrium (cont.)
- The absence of electric and magnetic fields from
V allows the use of the simplest symmetry
argument for proving that RE occurs, since
radioactive point sources emit radiation
isotropically - The presence of a homogeneous, constant magnetic
and/or electric field throughout V makes the
symmetry argument more difficult to visualize,
since the flow of charged particles past a point
such as P will no longer be isotropic
13Radiation Equilibrium (cont.)
- Isotropicity is not a requirement for RE in the
volume v it is merely necessary that the inward
and outward flow of identical particles of the
same energy be balanced for all particles present - Even if all the particles flow in one side of v
and out the other side, RE will still obtain so
long as the in vs out flow is balanced - Any source anisotropy, or distortion of
charged-particle tracks, that is homogeneously
present everywhere throughout V will have no
perturbing effect on the existence of RE in v
14Radiation Equilibrium (cont.)
- Consider an elemental volume dv at point of
interest P, and two other elemental volumes dv?
and dv? that are symmetrically positioned with
respect to dv - We assume dv is located at a distance s from the
boundary of volume V that is greater than the
maximum range of radiation penetration, d - Throughout V both the medium and the distributed
source are homogeneous, but now we allow the
presence of a homogeneous electric and/or
magnetic field, and the source itself need not
emit radiation isotropically, so long as the
anisotropy is homogeneous everywhere in V
15Radiation equilibrium in homogeneous but
anisotropic fields of radiation
16Radiation Equilibrium (cont.)
- Assuming that radiation moves preferentially from
left to right, homogeneity and symmetry
considerations require that the particles (A)
traveling from dv? to dv are identical to those
(B) traveling from dv to dv?, in the
expectation-value limit - Likewise the lesser flow (b) of particles from
dv? to dv is identical to that (a) from dv to dv?
- Consequently a B A b, that is, the flow of
particles from dv to dv? dv? is identical to
that from dv? dv? to dv
17Radiation equilibrium in homogeneous but
anisotropic fields of radiation
18Radiation Equilibrium (cont.)
- The pair of volumes dv? and dv? can be moved to
all possible symmetrical locations within V, and
their particle flows are integrated - Locations outside of the sphere of radius d about
point P of course neither receive particles from
nor contribute particles to dv - One may conclude from such an argument that each
particle flowing out of dv is replaced by an
identical particle flowing in - Thus RE exists at P
19Charged-Particle Equilibrium
- Charged particle equilibrium (CPE) exists for the
volume v if each charged particle of a given type
and energy leaving v is replaced by an identical
particle of the same energy entering, in terms of
expectation values - If CPE exists,
- is of course satisfied
20CPE (cont.)
- The existence of RE is a sufficient condition for
CPE to exist - The practical importance of CPE stems from the
fact that under certain conditions it can be
adequately approximated even in the absence of RE - Two important cases will be considered in the
following subsections
21CPE for Distributed Radioactive Sources
- Consider the trivial case were only charged
particles are emitted and radiative losses are
negligible - Again referring to the following diagram, the
dimension s is taken to be greater than the
maximum range d of the particles - If the same four conditions (1-4) are satisfied
throughout the volume V as required for RE, then
RE and CPE will of course both exist for the
volume v, since they are identical in this case
22Radiation equilibrium
23CPE for Distributed Radioactive Sources (cont.)
- Consider now the more interesting case where both
charged particles and relatively more penetrating
indirectly ionizing radiation are emitted - Let the distance d be the maximum range of the
charged particles only, and let V be just large
enough so the minimum distance s separating V
from v exceeds d
24CPE for Distributed Radioactive Sources (cont.)
- If the indirectly ionizing rays are penetrating
enough to escape from V without interacting
significantly with the medium, then they will
produce practically no secondary charged
particles - Only the primary charged particles then need be
considered in the symmetry argument as before,
where again we assume conditions 1-4 throughout
V, as stated for radiation equilibrium - Since the passage of identical charged particles
in and out of v is thus seen to be balanced, CPE
exists w.r.t. the primary charged particles
25CPE for Distributed Radioactive Sources (cont.)
- However, RE is not attained, since (Rout)u gt
(Rin)u for the volume v - This is evident from the fact that the indirectly
ionizing rays that originate in v and escape from
V are not replaced, because there is no source
outside of V - The equation for the expectation value of the
energy imparted in this case becomes
26CPE for Distributed Radioactive Sources (cont.)
- Since we are assuming that the indirectly
ionizing rays are so penetrating that they do not
interact significantly in v, ? is equal to the
kinetic energy given only to charged-particles by
the radioactive source in v, less any radiative
losses by those particles while in v - The average absorbed dose in v is thus equal to
- divided by the mass in v, for CPE conditions
27CPE for Distributed Radioactive Sources (cont.)
- Suppose that the size of the volume V occupied by
the source is expanded so that distance s
gradually increases from being merely equal to
the charged-particle range to being greater than
the effective range of the indirectly ionizing
rays and their secondaries - That transition will cause the (Rin)u term to
increase until it equals (Rout)u in value - Thus RE will be restored, according to the
symmetry argument applied to all rays - The energy imparted would be transformed into
that for RE
28CPE for Distributed Radioactive Sources (cont.)
- The calculation of the absorbed dose is evidently
straightforward for either of these limiting
cases (CPE or RE), but intermediate situations
are more difficult to deal with, i.e., when the
volume V is larger than necessary to achieve CPE
in v, but not large enough for RE - In that case some fraction of the energy of the
indirectly ionizing radiation component will be
absorbed, and it is relatively difficult to
determine what that fraction is
29CPE for Indirectly Ionizing Radiations from
External Sources
- In the following diagram a volume V is shown,
again containing a smaller volume v - The boundaries of v and V are required in this
case to be separated by at least the maximum
distance of penetration of any secondary charged
particle present - If the following conditions are satisfied
throughout V, CPE will exist for the volume v - The atomic composition of the medium is
homogeneous - The density of the medium is homogeneous
- There exists a uniform field of indirectly
ionizing radiation (i.e., the rays must be only
negligibly attenuated by passage through the
medium) - No inhomogeneous electric or magnetic fields are
present
30Charged-particle equilibrium conditions for an
external source
31CPE from External Sources (cont.)
- It is possible for CPE to exist in a volume
without satisfying all the above conditions under
certain geometrical conditions - The ion-collecting region of a free-air chamber
represents such a situation, to be discussed in
Chapter 12 - Another example is the trivial case of a point
source within a volume large enough so the
radiation cannot reach the boundary surface,
hence no replacement particles are required
32CPE from External Sources (cont.)
- Because of the uniformity of the indirectly
ionizing radiation field and of the medium
throughout V, one can say that the number of
charged particles produced per unit volume in
each energy interval and element of solid angle
will be uniform everywhere in V - However, the particles are not emitted
isotropically as in the case of radioactive point
sources
33CPE from External Sources (cont.)
- Neutron and photon interactions generally result
in anisotropic angular distributions of secondary
and scattered radiations - However, this anisotropy will be homogeneous
throughout V - This condition, together with a uniform medium in
which the charged particles can slow down
throughout V (as guaranteed by the first two
conditions) is sufficient to produce CPE for the
volume v
34CPE from External Sources (cont.)
- For CPE conditions
- However, under those same conditions we may also
assume that any radiative interaction by a
charged particle after it leaves v will be
replaced by an identical interaction inside of v,
as shown in the following diagram
35(No Transcript)
36CPE from External Sources (cont.)
- Thus
- provided that the volume v is small enough to
allow radiative-loss photons to escape - For that case
37CPE from External Sources (cont.)
- Reducing v to the infinitesimal volume dv,
containing mass dm about a point of interest P,
we can write - and hence
38CPE from External Sources (cont.)
- The derivation of this equation proves that under
CPE conditions at a point in a medium, the
absorbed dose is equal to the collision kerma
there - That is true irrespective of radiative losses
- This is a very important relationship, as it
equates the measurable quantity D with the
calculable quantity Kc ( ? ?en/?)
39CPE from External Sources (cont.)
- If the same photon energy fluence ? is present in
media A and B having two different average energy
absorption coefficients, the ratio of absorbed
doses under CPE conditions in the two media will
be given by